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4(A,java): solve “Watermelon”
Signed-off-by: Matej Focko <me@mfocko.xyz>
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2 changed files with 1081 additions and 0 deletions
124
4/A.java
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124
4/A.java
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import java.io.BufferedReader;
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import java.io.IOException;
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import java.io.InputStreamReader;
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import java.io.PrintWriter;
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import java.util.ArrayList;
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import java.util.Arrays;
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import java.util.Collections;
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import java.util.Random;
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import java.util.StringTokenizer;
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public class A {
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private FastScanner fs = new FastScanner();
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private PrintWriter out = new PrintWriter(System.out);
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void solve() {
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int N = fs.nextInt();
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if (N > 2 && N % 2 == 0) {
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out.println("YES");
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} else {
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out.println("NO");
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}
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}
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void run() {
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solve();
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out.close();
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}
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public static void main(String[] args) {
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new A().run();
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}
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static final Random random = new Random();
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static final int mod = 1_000_000_007;
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static void ruffleSort(int[] a) {
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int n = a.length;// shuffle, then sort
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for (int i = 0; i < n; i++) {
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int oi = random.nextInt(n), temp = a[oi];
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a[oi] = a[i];
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a[i] = temp;
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}
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Arrays.sort(a);
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}
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static long add(long a, long b) {
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return (a + b) % mod;
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}
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static long sub(long a, long b) {
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return ((a - b) % mod + mod) % mod;
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}
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static long mul(long a, long b) {
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return (a * b) % mod;
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}
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static long exp(long base, long exp) {
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if (exp == 0)
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return 1;
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long half = exp(base, exp / 2);
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if (exp % 2 == 0)
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return mul(half, half);
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return mul(half, mul(half, base));
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}
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static long[] factorials = new long[2_000_001];
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static long[] invFactorials = new long[2_000_001];
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static void precompFacts() {
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factorials[0] = invFactorials[0] = 1;
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for (int i = 1; i < factorials.length; i++)
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factorials[i] = mul(factorials[i - 1], i);
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invFactorials[factorials.length - 1] = exp(factorials[factorials.length - 1], mod - 2);
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for (int i = invFactorials.length - 2; i >= 0; i--)
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invFactorials[i] = mul(invFactorials[i + 1], i + 1);
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}
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static long nCk(int n, int k) {
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return mul(factorials[n], mul(invFactorials[k], invFactorials[n - k]));
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}
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static void sort(int[] a) {
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ArrayList<Integer> l = new ArrayList<>();
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for (int i : a)
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l.add(i);
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Collections.sort(l);
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for (int i = 0; i < a.length; i++)
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a[i] = l.get(i);
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}
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static class FastScanner {
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BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
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StringTokenizer st = new StringTokenizer("");
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String next() {
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while (!st.hasMoreTokens())
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try {
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st = new StringTokenizer(br.readLine());
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} catch (IOException e) {
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e.printStackTrace();
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}
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return st.nextToken();
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}
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int nextInt() {
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return Integer.parseInt(next());
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}
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int[] readArray(int n) {
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int[] a = new int[n];
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for (int i = 0; i < n; i++)
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a[i] = nextInt();
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return a;
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}
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long nextLong() {
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return Long.parseLong(next());
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}
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}
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}
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957
4/index.html
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4/index.html
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var ratio = Math.min(screenWidthPx / siteWidthPx, 1.0);
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var viewport = "width=device-width, initial-scale=" + ratio;
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$('#viewport').attr('content', viewport);
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<div class="ttypography"><div class="problem-statement"><div class="header"><div class="title">A. Watermelon</div><div class="time-limit"><div class="property-title">time limit per test</div>1 second</div><div class="memory-limit"><div class="property-title">memory limit per test</div>64 megabytes</div><div class="input-file"><div class="property-title">input</div>standard input</div><div class="output-file"><div class="property-title">output</div>standard output</div></div><div><p>One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed <span class="tex-span"><i>w</i></span> kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.</p><p>Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.</p></div><div class="input-specification"><div class="section-title">Input</div><p>The first (and the only) input line contains integer number <span class="tex-span"><i>w</i></span> (<span class="tex-span">1 ≤ <i>w</i> ≤ 100</span>) — the weight of the watermelon bought by the boys.</p></div><div class="output-specification"><div class="section-title">Output</div><p>Print <span class="tex-font-style-tt">YES</span>, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and <span class="tex-font-style-tt">NO</span> in the opposite case.</p></div><div class="sample-tests"><div class="section-title">Examples</div><div class="sample-test"><div class="input"><div class="title">Input</div><pre>8<br /></pre></div><div class="output"><div class="title">Output</div><pre>YES<br /></pre></div></div></div><div class="note"><div class="section-title">Note</div><p>For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos).</p></div></div></div>
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<div class="ttypography"><div class="problem-statement"><div class="header"><div class="title">B. Before an Exam</div><div class="time-limit"><div class="property-title">time limit per test</div>0.5 second</div><div class="memory-limit"><div class="property-title">memory limit per test</div>64 megabytes</div><div class="input-file"><div class="property-title">input</div>standard input</div><div class="output-file"><div class="property-title">output</div>standard output</div></div><div><p>Tomorrow Peter has a Biology exam. He does not like this subject much, but <span class="tex-span"><i>d</i></span> days ago he learnt that he would have to take this exam. Peter's strict parents made him prepare for the exam immediately, for this purpose he has to study not less than <span class="tex-span"><i>minTime</i><sub class="lower-index"><i>i</i></sub></span> and not more than <span class="tex-span"><i>maxTime</i><sub class="lower-index"><i>i</i></sub></span> hours per each <span class="tex-span"><i>i</i></span>-th day. Moreover, they warned Peter that a day before the exam they would check how he has followed their instructions.</p><p>So, today is the day when Peter's parents ask him to show the timetable of his preparatory studies. But the boy has counted only the sum of hours <span class="tex-span"><i>sumTime</i></span> spent him on preparation, and now he wants to know if he can show his parents a timetable <span class="tex-span"><i>sсhedule</i></span> with <span class="tex-span"><i>d</i></span> numbers, where each number <span class="tex-span"><i>sсhedule</i><sub class="lower-index"><i>i</i></sub></span> stands for the time in hours spent by Peter each <span class="tex-span"><i>i</i></span>-th day on biology studies, and satisfying the limitations imposed by his parents, and at the same time the sum total of all <span class="tex-span"><i>schedule</i><sub class="lower-index"><i>i</i></sub></span> should equal to <span class="tex-span"><i>sumTime</i></span>.</p></div><div class="input-specification"><div class="section-title">Input</div><p>The first input line contains two integer numbers <span class="tex-span"><i>d</i>, <i>sumTime</i></span> (<span class="tex-span">1 ≤ <i>d</i> ≤ 30, 0 ≤ <i>sumTime</i> ≤ 240</span>) — the amount of days, during which Peter studied, and the total amount of hours, spent on preparation. Each of the following <span class="tex-span"><i>d</i></span> lines contains two integer numbers <span class="tex-span"><i>minTime</i><sub class="lower-index"><i>i</i></sub>, <i>maxTime</i><sub class="lower-index"><i>i</i></sub></span> (<span class="tex-span">0 ≤ <i>minTime</i><sub class="lower-index"><i>i</i></sub> ≤ <i>maxTime</i><sub class="lower-index"><i>i</i></sub> ≤ 8</span>), separated by a space — minimum and maximum amount of hours that Peter could spent in the <span class="tex-span"><i>i</i></span>-th day.</p></div><div class="output-specification"><div class="section-title">Output</div><p>In the first line print <span class="tex-font-style-tt">YES</span>, and in the second line print <span class="tex-span"><i>d</i></span> numbers (separated by a space), each of the numbers — amount of hours, spent by Peter on preparation in the corresponding day, if he followed his parents' instructions; or print <span class="tex-font-style-tt">NO</span> in the unique line. If there are many solutions, print any of them.</p></div><div class="sample-tests"><div class="section-title">Examples</div><div class="sample-test"><div class="input"><div class="title">Input</div><pre>1 48<br />5 7<br /></pre></div><div class="output"><div class="title">Output</div><pre>NO<br /></pre></div><div class="input"><div class="title">Input</div><pre>2 5<br />0 1<br />3 5<br /></pre></div><div class="output"><div class="title">Output</div><pre>YES<br />1 4 </pre></div></div></div></div></div>
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<div class="ttypography"><div class="problem-statement"><div class="header"><div class="title">C. Registration system</div><div class="time-limit"><div class="property-title">time limit per test</div>5 seconds</div><div class="memory-limit"><div class="property-title">memory limit per test</div>64 megabytes</div><div class="input-file"><div class="property-title">input</div>standard input</div><div class="output-file"><div class="property-title">output</div>standard output</div></div><div><p>A new e-mail service "Berlandesk" is going to be opened in Berland in the near future. The site administration wants to launch their project as soon as possible, that's why they ask you to help. You're suggested to implement the prototype of site registration system. The system should work on the following principle. </p><p>Each time a new user wants to register, he sends to the system a request with his <span class="tex-font-style-tt">name</span>. If such a <span class="tex-font-style-tt">name</span> does not exist in the system database, it is inserted into the database, and the user gets the response <span class="tex-font-style-tt">OK</span>, confirming the successful registration. If the <span class="tex-font-style-tt">name</span> already exists in the system database, the system makes up a new user name, sends it to the user as a prompt and <span class="tex-font-style-it">also inserts the prompt into the database</span>. The new name is formed by the following rule. Numbers, starting with 1, are appended one after another to <span class="tex-font-style-tt">name</span> (<span class="tex-font-style-tt">name1</span>, <span class="tex-font-style-tt">name2</span>, ...), among these numbers the least <span class="tex-span"><i>i</i></span> is found so that <span class="tex-font-style-tt">name</span><span class="tex-span"><i>i</i></span> does not yet exist in the database.</p></div><div class="input-specification"><div class="section-title">Input</div><p>The first line contains number <span class="tex-span"><i>n</i></span> (<span class="tex-span">1 ≤ <i>n</i> ≤ 10<sup class="upper-index">5</sup></span>). The following <span class="tex-span"><i>n</i></span> lines contain the requests to the system. Each request is a non-empty line, and consists of not more than 32 characters, which are all lowercase Latin letters.</p></div><div class="output-specification"><div class="section-title">Output</div><p>Print <span class="tex-span"><i>n</i></span> lines, which are system responses to the requests: <span class="tex-font-style-tt">OK</span> in case of successful registration, or a prompt with a new name, if the requested name is already taken.</p></div><div class="sample-tests"><div class="section-title">Examples</div><div class="sample-test"><div class="input"><div class="title">Input</div><pre>4<br />abacaba<br />acaba<br />abacaba<br />acab<br /></pre></div><div class="output"><div class="title">Output</div><pre>OK<br />OK<br />abacaba1<br />OK<br /></pre></div><div class="input"><div class="title">Input</div><pre>6<br />first<br />first<br />second<br />second<br />third<br />third<br /></pre></div><div class="output"><div class="title">Output</div><pre>OK<br />first1<br />OK<br />second1<br />OK<br />third1<br /></pre></div></div></div></div></div>
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<div class="ttypography"><div class="problem-statement"><div class="header"><div class="title">D. Mysterious Present</div><div class="time-limit"><div class="property-title">time limit per test</div>1 second</div><div class="memory-limit"><div class="property-title">memory limit per test</div>64 megabytes</div><div class="input-file"><div class="property-title">input</div>standard input</div><div class="output-file"><div class="property-title">output</div>standard output</div></div><div><p>Peter decided to wish happy birthday to his friend from Australia and send him a card. To make his present more mysterious, he decided to make a <span class="tex-font-style-it">chain</span>. Chain here is such a sequence of envelopes <span class="tex-span"><i>A</i></span> = {<span class="tex-span"><i>a</i><sub class="lower-index">1</sub>, <i>a</i><sub class="lower-index">2</sub>, ..., <i>a</i><sub class="lower-index"><i>n</i></sub></span>}, where the width and the height of the <span class="tex-span"><i>i</i></span>-th envelope is strictly higher than the width and the height of the <span class="tex-span">(<i>i</i> - 1)</span>-th envelope respectively. Chain size is the number of envelopes in the chain. </p><p>Peter wants to make the chain of the maximum size from the envelopes he has, the chain should be such, that he'll be able to put a card into it. The card fits into the chain if its width and height is lower than the width and the height of the smallest envelope in the chain respectively. It's forbidden to turn the card and the envelopes. </p><p>Peter has very many envelopes and very little time, this hard task is entrusted to you.</p></div><div class="input-specification"><div class="section-title">Input</div><p>The first line contains integers <span class="tex-span"><i>n</i></span>, <span class="tex-span"><i>w</i></span>, <span class="tex-span"><i>h</i></span> (<span class="tex-span">1 ≤ <i>n</i> ≤ 5000</span>, <span class="tex-span">1 ≤ <i>w</i>, <i>h</i> ≤ 10<sup class="upper-index">6</sup></span>) — amount of envelopes Peter has, the card width and height respectively. Then there follow <span class="tex-span"><i>n</i></span> lines, each of them contains two integer numbers <span class="tex-span"><i>w</i><sub class="lower-index"><i>i</i></sub></span> and <span class="tex-span"><i>h</i><sub class="lower-index"><i>i</i></sub></span> — width and height of the <span class="tex-span"><i>i</i></span>-th envelope (<span class="tex-span">1 ≤ <i>w</i><sub class="lower-index"><i>i</i></sub>, <i>h</i><sub class="lower-index"><i>i</i></sub> ≤ 10<sup class="upper-index">6</sup></span>).</p></div><div class="output-specification"><div class="section-title">Output</div><p>In the first line print the maximum chain size. In the second line print the numbers of the envelopes (separated by space), forming the required chain, starting with the number of the smallest envelope. Remember, please, that the card should fit into the smallest envelope. If the chain of maximum size is not unique, print any of the answers.</p><p>If the card does not fit into any of the envelopes, print number <span class="tex-span">0</span> in the single line.</p></div><div class="sample-tests"><div class="section-title">Examples</div><div class="sample-test"><div class="input"><div class="title">Input</div><pre>2 1 1<br />2 2<br />2 2<br /></pre></div><div class="output"><div class="title">Output</div><pre>1<br />1 <br /></pre></div><div class="input"><div class="title">Input</div><pre>3 3 3<br />5 4<br />12 11<br />9 8<br /></pre></div><div class="output"><div class="title">Output</div><pre>3<br />1 3 2 <br /></pre></div></div></div></div></div>
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</div>
|
||||
</div>
|
||||
<script type="application/javascript">
|
||||
if ('serviceWorker' in navigator && 'fetch' in window && 'caches' in window) {
|
||||
navigator.serviceWorker.register('/service-worker-34323.js')
|
||||
.then(function (registration) {
|
||||
console.log('Service worker registered: ', registration);
|
||||
})
|
||||
.catch(function (error) {
|
||||
console.log('Registration failed: ', error);
|
||||
});
|
||||
}
|
||||
</script>
|
||||
<script>(function(){var js = "window['__CF$cv$params']={r:'7e42c32209c9b333',m:'y4WMhCYWbnQ8cfIFAC9QoyvR5BKDufe48ET0SKOcALQ-1688928727-0-AUVuoHQ4Klt60gEBPOz3zQKUrABX7QiS/eSwuM6VYvMF'};_cpo=document.createElement('script');_cpo.nonce='',_cpo.src='/cdn-cgi/challenge-platform/scripts/invisible.js',document.getElementsByTagName('head')[0].appendChild(_cpo);";var _0xh = document.createElement('iframe');_0xh.height = 1;_0xh.width = 1;_0xh.style.position = 'absolute';_0xh.style.top = 0;_0xh.style.left = 0;_0xh.style.border = 'none';_0xh.style.visibility = 'hidden';document.body.appendChild(_0xh);function handler() {var _0xi = _0xh.contentDocument || _0xh.contentWindow.document;if (_0xi) {var _0xj = _0xi.createElement('script');_0xj.nonce = '';_0xj.innerHTML = js;_0xi.getElementsByTagName('head')[0].appendChild(_0xj);}}if (document.readyState !== 'loading') {handler();} else if (window.addEventListener) {document.addEventListener('DOMContentLoaded', handler);} else {var prev = document.onreadystatechange || function () {};document.onreadystatechange = function (e) {prev(e);if (document.readyState !== 'loading') {document.onreadystatechange = prev;handler();}};}})();</script></body>
|
||||
</html>
|
||||
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Reference in a new issue