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<div class="ttypography"><div class="problem-statement"><div class="header"><div class="title">A. Way Too Long Words</div><div class="time-limit"><div class="property-title">time limit per test</div>1 second</div><div class="memory-limit"><div class="property-title">memory limit per test</div>256 megabytes</div><div class="input-file"><div class="property-title">input</div>standard input</div><div class="output-file"><div class="property-title">output</div>standard output</div></div><div><p>Sometimes some words like "<span class="tex-font-style-tt">localization</span>" or "<span class="tex-font-style-tt">internationalization</span>" are so long that writing them many times in one text is quite tiresome.</p><p>Let's consider a word <span class="tex-font-style-it">too long</span>, if its length is <span class="tex-font-style-bf">strictly more</span> than <span class="tex-span">10</span> characters. All too long words should be replaced with a special abbreviation.</p><p>This abbreviation is made like this: we write down the first and the last letter of a word and between them we write the number of letters between the first and the last letters. That number is in decimal system and doesn't contain any leading zeroes.</p><p>Thus, "<span class="tex-font-style-tt">localization</span>" will be spelt as "<span class="tex-font-style-tt">l10n</span>", and "<span class="tex-font-style-tt">internationalization</span>» will be spelt as "<span class="tex-font-style-tt">i18n</span>".</p><p>You are suggested to automatize the process of changing the words with abbreviations. At that all too long words should be replaced by the abbreviation and the words that are not too long should not undergo any changes.</p></div><div class="input-specification"><div class="section-title">Input</div><p>The first line contains an integer <span class="tex-span"><i>n</i></span> (<span class="tex-span">1 ≤ <i>n</i> ≤ 100</span>). Each of the following <span class="tex-span"><i>n</i></span> lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from <span class="tex-span">1</span> to <span class="tex-span">100</span> characters.</p></div><div class="output-specification"><div class="section-title">Output</div><p>Print <span class="tex-span"><i>n</i></span> lines. The <span class="tex-span"><i>i</i></span>-th line should contain the result of replacing of the <span class="tex-span"><i>i</i></span>-th word from the input data.</p></div><div class="sample-tests"><div class="section-title">Examples</div><div class="sample-test"><div class="input"><div class="title">Input</div><pre>4<br />word<br />localization<br />internationalization<br />pneumonoultramicroscopicsilicovolcanoconiosis<br /></pre></div><div class="output"><div class="title">Output</div><pre>word<br />l10n<br />i18n<br />p43s<br /></pre></div></div></div></div></div>
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<div class="ttypography"><div class="problem-statement"><div class="header"><div class="title">B. Progress Bar</div><div class="time-limit"><div class="property-title">time limit per test</div>1 second</div><div class="memory-limit"><div class="property-title">memory limit per test</div>256 megabytes</div><div class="input-file"><div class="property-title">input</div>standard input</div><div class="output-file"><div class="property-title">output</div>standard output</div></div><div><p>A progress bar is an element of graphical interface that displays the progress of a process for this very moment before it is completed. Let's take a look at the following form of such a bar.</p><p>A bar is represented as <span class="tex-span"><i>n</i></span> squares, located in line. To add clarity, let's number them with positive integers from <span class="tex-span">1</span> to <span class="tex-span"><i>n</i></span> from the left to the right. Each square has saturation (<span class="tex-span"><i>a</i><sub class="lower-index"><i>i</i></sub></span> for the <span class="tex-span"><i>i</i></span>-th square), which is measured by an integer from <span class="tex-span">0</span> to <span class="tex-span"><i>k</i></span>. When the bar for some <span class="tex-span"><i>i</i></span> (<span class="tex-span">1 ≤ <i>i</i> ≤ <i>n</i></span>) is displayed, squares <span class="tex-span">1, 2, ... , <i>i</i> - 1</span> has the saturation <span class="tex-span"><i>k</i></span>, squares <span class="tex-span"><i>i</i> + 1, <i>i</i> + 2, ... , <i>n</i></span> has the saturation <span class="tex-span">0</span>, and the saturation of the square <span class="tex-span"><i>i</i></span> can have any value from <span class="tex-span">0</span> to <span class="tex-span"><i>k</i></span>.</p><p>So some first squares of the progress bar always have the saturation <span class="tex-span"><i>k</i></span>. Some last squares always have the saturation <span class="tex-span">0</span>. And there is no more than one square that has the saturation different from <span class="tex-span">0</span> and <span class="tex-span"><i>k</i></span>.</p><p>The degree of the process's completion is measured in percents. Let the process be <span class="tex-span"><i>t</i></span>% completed. Then the following inequation is fulfilled: </p><center class="tex-equation"><img align="middle" class="tex-formula" src="https://espresso.codeforces.com/b409a1d17f3e5356e7e72566ff1b99fd47ec1b59.png" style="max-width: 100.0%;max-height: 100.0%;" /></center><p>An example of such a bar can be seen on the picture.</p><center> <img class="tex-graphics" src="https://espresso.codeforces.com/c5c3951d407b9d376bf210a8c1a4010bfedcaf36.png" style="max-width: 100.0%;max-height: 100.0%;" /> </center><p>For the given <span class="tex-span"><i>n</i></span>, <span class="tex-span"><i>k</i></span>, <span class="tex-span"><i>t</i></span> determine the measures of saturation for all the squares <span class="tex-span"><i>a</i><sub class="lower-index"><i>i</i></sub></span> of the progress bar.</p></div><div class="input-specification"><div class="section-title">Input</div><p>We are given 3 space-separated integers <span class="tex-span"><i>n</i></span>, <span class="tex-span"><i>k</i></span>, <span class="tex-span"><i>t</i></span> (<span class="tex-span">1 ≤ <i>n</i>, <i>k</i> ≤ 100</span>, <span class="tex-span">0 ≤ <i>t</i> ≤ 100</span>).</p></div><div class="output-specification"><div class="section-title">Output</div><p>Print <span class="tex-span"><i>n</i></span> numbers. The <span class="tex-span"><i>i</i></span>-th of them should be equal to <span class="tex-span"><i>a</i><sub class="lower-index"><i>i</i></sub></span>.</p></div><div class="sample-tests"><div class="section-title">Examples</div><div class="sample-test"><div class="input"><div class="title">Input</div><pre>10 10 54<br /></pre></div><div class="output"><div class="title">Output</div><pre>10 10 10 10 10 4 0 0 0 0 </pre></div><div class="input"><div class="title">Input</div><pre>11 13 37
|
|||
|
|
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|
|||
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<div class="ttypography"><div class="problem-statement"><div class="header"><div class="title">C. Round Table Knights</div><div class="time-limit"><div class="property-title">time limit per test</div>0.5 second</div><div class="memory-limit"><div class="property-title">memory limit per test</div>256 megabytes</div><div class="input-file"><div class="property-title">input</div>standard input</div><div class="output-file"><div class="property-title">output</div>standard output</div></div><div><p>There are <span class="tex-span"><i>n</i></span> knights sitting at the Round Table at an equal distance from each other. Each of them is either in a good or in a bad mood.</p><p>Merlin, the wizard predicted to King Arthur that the next month will turn out to be particularly fortunate if the <span class="tex-font-style-it">regular</span> polygon can be found. On all vertices of the polygon knights in a good mood should be located. Otherwise, the next month will bring misfortunes.</p><p>A convex polygon is regular if all its sides have same length and all his angles are equal. In this problem we consider only regular polygons with at least 3 vertices, i. e. only nondegenerated.</p><p>On a picture below some examples of such polygons are present. Green points mean knights in a good mood. Red points mean ones in a bad mood.</p><center> <img class="tex-graphics" src="https://espresso.codeforces.com/74f876ccab06b18381319757d775aafd5756bf26.png" style="max-width: 100.0%;max-height: 100.0%;" /> </center><p>King Arthur knows the knights' moods. Help him find out if the next month will be fortunate or not.</p></div><div class="input-specification"><div class="section-title">Input</div><p>The first line contains number <span class="tex-span"><i>n</i></span>, which is the number of knights at the round table (<span class="tex-span">3 ≤ <i>n</i> ≤ 10<sup class="upper-index">5</sup></span>). The second line contains space-separated moods of all the <span class="tex-span"><i>n</i></span> knights in the order of passing them around the table. "1" means that the knight is in a good mood an "0" means that he is in a bad mood.</p></div><div class="output-specification"><div class="section-title">Output</div><p>Print "<span class="tex-font-style-tt">YES</span>" without the quotes if the following month will turn out to be lucky. Otherwise, print "<span class="tex-font-style-tt">NO</span>".</p></div><div class="sample-tests"><div class="section-title">Examples</div><div class="sample-test"><div class="input"><div class="title">Input</div><pre>3<br />1 1 1<br /></pre></div><div class="output"><div class="title">Output</div><pre>YES</pre></div><div class="input"><div class="title">Input</div><pre>6<br />1 0 1 1 1 0<br /></pre></div><div class="output"><div class="title">Output</div><pre>YES</pre></div><div class="input"><div class="title">Input</div><pre>6<br />1 0 0 1 0 1<br /></pre></div><div class="output"><div class="title">Output</div><pre>NO</pre></div></div></div></div></div>
|
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<div class="ttypography"><div class="problem-statement"><div class="header"><div class="title">D. Solitaire</div><div class="time-limit"><div class="property-title">time limit per test</div>1.5 seconds</div><div class="memory-limit"><div class="property-title">memory limit per test</div>256 megabytes</div><div class="input-file"><div class="property-title">input</div>standard input</div><div class="output-file"><div class="property-title">output</div>standard output</div></div><div><p>Vasya has a pack of <span class="tex-span">54</span> cards (<span class="tex-span">52</span> standard cards and <span class="tex-span">2</span> distinct jokers). That is all he has at the moment. Not to die from boredom, Vasya plays Solitaire with them.</p><p>Vasya lays out <span class="tex-span"><i>nm</i></span> cards as a rectangle <span class="tex-span"><i>n</i> × <i>m</i></span>. If there are jokers among them, then Vasya should change them with some of the rest of <span class="tex-span">54 - <i>nm</i></span> cards (which are not layed out) so that there were no jokers left. Vasya can pick the cards to replace the jokers arbitrarily. Remember, that each card presents in pack exactly once (i. e. <span class="tex-font-style-bf">in a single copy</span>). Vasya tries to perform the replacements so that the solitaire was <span class="tex-font-style-it">solved</span>.</p><p>Vasya thinks that the solitaire is solved if after the jokers are replaced, there exist two non-overlapping squares <span class="tex-span">3 × 3</span>, inside each of which all the cards either have the same suit, or pairwise different ranks.</p><p>Determine by the initial position whether the solitaire can be solved or not. If it can be solved, show the way in which it is possible.</p></div><div class="input-specification"><div class="section-title">Input</div><p>The first line contains integers <span class="tex-span"><i>n</i></span> and <span class="tex-span"><i>m</i></span> (<span class="tex-span">3 ≤ <i>n</i>, <i>m</i> ≤ 17</span>, <span class="tex-span"><i>n</i> × <i>m</i> ≤ 52</span>). Next <span class="tex-span"><i>n</i></span> lines contain <span class="tex-span"><i>m</i></span> words each. Each word consists of two letters. The jokers are defined as "<span class="tex-font-style-tt">J1</span>" and "<span class="tex-font-style-tt">J2</span>" correspondingly. For the rest of the cards, the first letter stands for the rank and the second one — for the suit. The possible ranks are: "<span class="tex-font-style-tt">2</span>", "<span class="tex-font-style-tt">3</span>", "<span class="tex-font-style-tt">4</span>", "<span class="tex-font-style-tt">5</span>", "<span class="tex-font-style-tt">6</span>", "<span class="tex-font-style-tt">7</span>", "<span class="tex-font-style-tt">8</span>", "<span class="tex-font-style-tt">9</span>", "<span class="tex-font-style-tt">T</span>", "<span class="tex-font-style-tt">J</span>", "<span class="tex-font-style-tt">Q</span>", "<span class="tex-font-style-tt">K</span>" and "<span class="tex-font-style-tt">A</span>". The possible suits are: "<span class="tex-font-style-tt">C</span>", "<span class="tex-font-style-tt">D</span>", "<span class="tex-font-style-tt">H</span>" and "<span class="tex-font-style-tt">S</span>". All the cards are different.</p></div><div class="output-specification"><div class="section-title">Output</div><p>If the Solitaire can be solved, print on the first line "<span class="tex-font-style-tt">Solution exists.</span>" without the quotes. On the second line print in what way the jokers can be replaced. Three variants are possible:</p><ul> <li> "<span class="tex-font-style-tt">There are no jokers.</span>", if there are no jokers in the input data.</li><li> "<span class="tex-font-style-tt">Replace J<span class="tex-span"><i>x</i></span> with <span class="tex-sp
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<div class="ttypography"><div class="problem-statement"><div class="header"><div class="title">E. Nuclear Fusion</div><div class="time-limit"><div class="property-title">time limit per test</div>1.5 seconds</div><div class="memory-limit"><div class="property-title">memory limit per test</div>256 megabytes</div><div class="input-file"><div class="property-title">input</div>standard input</div><div class="output-file"><div class="property-title">output</div>standard output</div></div><div><p>There is the following puzzle popular among nuclear physicists.</p><p>A reactor contains a set of <span class="tex-span"><i>n</i></span> atoms of some chemical elements. We shall understand the phrase "atomic number" as the number of this atom's element in the periodic table of the chemical elements.</p><p>You are allowed to take any two different atoms and fuse a new one from them. That results in a new atom, whose number is equal to the sum of the numbers of original atoms. The fusion operation can be performed several times.</p><p>The aim is getting a new pregiven set of <span class="tex-span"><i>k</i></span> atoms.</p><p>The puzzle's difficulty is that it is only allowed to fuse two atoms into one, it is not allowed to split an atom into several atoms. You are suggested to try to solve the puzzle.</p></div><div class="input-specification"><div class="section-title">Input</div><p>The first line contains two integers <span class="tex-span"><i>n</i></span> and <span class="tex-span"><i>k</i></span> (<span class="tex-span">1 ≤ <i>k</i> ≤ <i>n</i> ≤ 17</span>). The second line contains space-separated symbols of elements of <span class="tex-span"><i>n</i></span> atoms, which are available from the start. The third line contains space-separated symbols of elements of <span class="tex-span"><i>k</i></span> atoms which need to be the result of the fusion. The symbols of the elements coincide with the symbols from the periodic table of the chemical elements. The atomic numbers do not exceed <span class="tex-span">100</span> (elements possessing larger numbers are highly unstable). Some atoms can have identical numbers (that is, there can be several atoms of the same element). The sum of numbers of initial atoms is equal to the sum of numbers of the atoms that need to be synthesized.</p></div><div class="output-specification"><div class="section-title">Output</div><p>If it is impossible to synthesize the required atoms, print "<span class="tex-font-style-tt">NO</span>" without the quotes. Otherwise, print on the first line «<span class="tex-font-style-tt">YES</span>», and on the next <span class="tex-span"><i>k</i></span> lines print the way of synthesizing each of <span class="tex-span"><i>k</i></span> atoms as equations. Each equation has the following form: "<span class="tex-span"><i>x</i><sub class="lower-index">1</sub></span><span class="tex-font-style-tt">+</span><span class="tex-span"><i>x</i><sub class="lower-index">2</sub></span><span class="tex-font-style-tt">+</span><span class="tex-span">...</span><span class="tex-font-style-tt">+</span><span class="tex-span"><i>x</i><sub class="lower-index"><i>t</i></sub></span><span class="tex-font-style-tt">-></span><span class="tex-span"><i>y</i><sub class="lower-index"><i>i</i></sub></span>", where <span class="tex-span"><i>x</i><sub class="lower-index"><i>j</i></sub></span> is the symbol of the element of some atom from the original set, and <span class="tex-span"><i>y</i><sub class="lower-index"><i>i</i></sub></span> is the symbol of the element of some atom from the resulting set. Each atom from the input data should occur in the output data exactly one time. The order of summands in the equations, as well as the output order does not matter. If there are several solutions, print any of them. For a better understanding of the output format, see the samples.</p></div><div class="sample-tests"><div class="section-title">Examples</div><div class="sample-test"><div class="input"><div class="title">Input</div><pre>10 3<br />Mn Co Li
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