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diff --git a/algorithms/algorithms-correctness/postcondition-ambiguity/index.html b/algorithms/algorithms-correctness/postcondition-ambiguity/index.html index d5818b8..19313a5 100644 --- a/algorithms/algorithms-correctness/postcondition-ambiguity/index.html +++ b/algorithms/algorithms-correctness/postcondition-ambiguity/index.html @@ -16,8 +16,8 @@ - - + +
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Vague postconditions and proving correctness of algorithms

Introduction

diff --git a/algorithms/category/algorithms-and-correctness/index.html b/algorithms/category/algorithms-and-correctness/index.html index 11800a0..766ee40 100644 --- a/algorithms/category/algorithms-and-correctness/index.html +++ b/algorithms/category/algorithms-and-correctness/index.html @@ -18,8 +18,8 @@ correctness. - - + +

Algorithms and Correctness

Materials related to basic ideas behind algorithms and proofs of their diff --git a/algorithms/category/asymptotic-notation-and-time-complexity/index.html b/algorithms/category/asymptotic-notation-and-time-complexity/index.html index 559a29a..c5cab4c 100644 --- a/algorithms/category/asymptotic-notation-and-time-complexity/index.html +++ b/algorithms/category/asymptotic-notation-and-time-complexity/index.html @@ -16,8 +16,8 @@ - - + +

Asymptotic Notation and Time Complexity

Materials related to asymptotic notation and time complexity. diff --git a/algorithms/category/graphs/index.html b/algorithms/category/graphs/index.html index e4a5473..128b425 100644 --- a/algorithms/category/graphs/index.html +++ b/algorithms/category/graphs/index.html @@ -16,8 +16,8 @@ - - + +

Graphs

Materials related to basic graph algorithms and graph problems. diff --git a/algorithms/category/hash-tables/index.html b/algorithms/category/hash-tables/index.html index 9447d86..0d487af 100644 --- a/algorithms/category/hash-tables/index.html +++ b/algorithms/category/hash-tables/index.html @@ -16,8 +16,8 @@ - - + +

Hash Tables

Materials related to hash tables. diff --git a/algorithms/category/recursion/index.html b/algorithms/category/recursion/index.html index 9dbef49..d2e2a85 100644 --- a/algorithms/category/recursion/index.html +++ b/algorithms/category/recursion/index.html @@ -16,15 +16,13 @@ - - + + -

\ No newline at end of file diff --git a/algorithms/category/red-black-trees/index.html b/algorithms/category/red-black-trees/index.html index 4cba31d..c62572f 100644 --- a/algorithms/category/red-black-trees/index.html +++ b/algorithms/category/red-black-trees/index.html @@ -16,8 +16,8 @@ - - + +

Red-Black Trees

Materials related to red-black trees. diff --git a/algorithms/graphs/bfs-tree/index.html b/algorithms/graphs/bfs-tree/index.html index c132383..fc8baca 100644 --- a/algorithms/graphs/bfs-tree/index.html +++ b/algorithms/graphs/bfs-tree/index.html @@ -16,8 +16,8 @@ - - + +

Distance boundaries from BFS tree on undirected graphs

Introduction

diff --git a/algorithms/graphs/iterative-and-iterators/index.html b/algorithms/graphs/iterative-and-iterators/index.html index 14802ab..7c1ab77 100644 --- a/algorithms/graphs/iterative-and-iterators/index.html +++ b/algorithms/graphs/iterative-and-iterators/index.html @@ -16,8 +16,8 @@ - - + +

Iterative algorithms via iterators

Introduction

diff --git a/algorithms/hash-tables/breaking/index.html b/algorithms/hash-tables/breaking/index.html index 951dfdd..b991bdf 100644 --- a/algorithms/hash-tables/breaking/index.html +++ b/algorithms/hash-tables/breaking/index.html @@ -16,8 +16,8 @@ - - + +

Breaking Hash Table

We will try to break a hash table and discuss possible ways how to prevent such diff --git a/algorithms/hash-tables/breaking/mitigations/index.html b/algorithms/hash-tables/breaking/mitigations/index.html index 2c88b23..c8d13e7 100644 --- a/algorithms/hash-tables/breaking/mitigations/index.html +++ b/algorithms/hash-tables/breaking/mitigations/index.html @@ -16,8 +16,8 @@ - - + +

Possible Mitigations

There are multiple ways the issues created above can be mitigated. Still we can diff --git a/algorithms/hash-tables/breaking/python/index.html b/algorithms/hash-tables/breaking/python/index.html index 527c34f..5d9fcb7 100644 --- a/algorithms/hash-tables/breaking/python/index.html +++ b/algorithms/hash-tables/breaking/python/index.html @@ -16,8 +16,8 @@ - - + +

Breaking the Hash Table in Python

diff --git a/algorithms/index.html b/algorithms/index.html index c514a2d..84e9915 100644 --- a/algorithms/index.html +++ b/algorithms/index.html @@ -14,8 +14,8 @@ - - + +

Introduction

In this part you can find “random” additional materials I have written over the @@ -23,6 +23,6 @@ course of teaching Algorithms and data structures I.

It is a various mix of stuff that may have been produced as a follow-up on some question asked at the seminar or spontanously.

If you have some ideas for posts, please do not hesitate to submit them as issues -in the linked GitLab.

+in the linked GitLab.

\ No newline at end of file diff --git a/algorithms/rb-trees/applications/index.html b/algorithms/rb-trees/applications/index.html index 6999567..534b42a 100644 --- a/algorithms/rb-trees/applications/index.html +++ b/algorithms/rb-trees/applications/index.html @@ -16,8 +16,8 @@ - - + +

Použití červeno-černých stromů

Použití

diff --git a/algorithms/rb-trees/rules/index.html b/algorithms/rb-trees/rules/index.html index 62fef1d..855822a 100644 --- a/algorithms/rb-trees/rules/index.html +++ b/algorithms/rb-trees/rules/index.html @@ -16,8 +16,8 @@ - - + +

On the rules of the red-black tree

Introduction

diff --git a/algorithms/recursion/karel-1/index.html b/algorithms/recursion/karel/index.html similarity index 63% rename from algorithms/recursion/karel-1/index.html rename to algorithms/recursion/karel/index.html index d2b266b..a618977 100644 --- a/algorithms/recursion/karel-1/index.html +++ b/algorithms/recursion/karel/index.html @@ -1,11 +1,11 @@ - + -Recursion and backtracking with Robot Karel | mfRecursion and backtracking with Robot Karel | mf +"> @@ -16,11 +16,11 @@ - - + + -

Recursion and backtracking with Robot Karel

\ No newline at end of file diff --git a/algorithms/recursion/karel/solution/index.html b/algorithms/recursion/karel/solution/index.html new file mode 100644 index 0000000..585dc6b --- /dev/null +++ b/algorithms/recursion/karel/solution/index.html @@ -0,0 +1,120 @@ + + + + + +Solution to the problem | mf + + + + + + + + + + + + + + +

Solving the maze problem

+

We will go through the given problem the same way as I have suggested in the +previous post.

+

Summary of the problem

+

We have a robot in some kind of a maze and we have to find our way out that is +marked with a so-called “beeper”. We've been given a restriction not to use +any variables, we can use just backtracking and recursion.

+

Brainstorming the idea

+

Let's start with some brainstorming of the solution.

+
    +
  • How will I know what I've checked without any variables? +
      +
    • answer: recursion will need to take care of that, cause I'm not allowed +anything else
    • +
    +
  • +
  • How will I pass around the fact I've found the exit? +
      +
    • answer: I can return values from helper functions, so I should be able to +indicate found/not found
    • +
    +
  • +
  • How is the exit marked? +
      +
    • answer: there is one “beeper” as a mark
    • +
    +
  • +
  • Can I reduce my problem somehow? +
      +
    • answer: I could check each possible direction as a reduced search space
    • +
    +
  • +
+

»Rough« pseudocode

+

We should be able to construct a skeleton of our solution at least. Pseudocode +follows:

+
def find_exit
if found the exit then
signal others
terminate
end

check left
check front
check right
end
+

As you can see, we only mention what we want to do very roughly, technical +details are left out, except for the early return (which is the base of our +recursive function).

+

»Proper« pseudocode

+

In the proper pseudocode we will need to dive into the technical details like +the way we check for exit, move around, etc.

+

We can start by cleaning up and decomposing the function written above:

+
def find_exit
# BASE: found exit
if found_exit() then
return true
end

# check left
if left_is_clear() then
turn_left()
step()
if find_exit() then
return true
end

turn_around()
step()
turn_left()
end

# check front
if front_is_clear() then
step()
if find_exit() then
return true
end

turn_around()
step()
turn_around()
end

# check right
if right_is_clear() then
turn_right()
step()
if find_exit() then
return true
end

turn_around()
step()
turn_right()
end

return false
end
+

We are missing few of the functions that we use in our pseudocode above:

+
    +
  • found_exit()
  • +
  • turn_around()
  • +
  • turn_right()
  • +
+

We can implement those easily:

+
def found_exit
if not beepers_present() then
return false
end

pick_beeper()
if beepers_present() then
put_beeper()
return false
end

put_beeper()
return true
end

def turn_around
turn_left()
turn_left()
end

def turn_right
turn_around()
turn_left()
end
+

Now we have everything ready for implementing it in Python.

+

Actual implementation

+

It's just a matter of rewriting the pseudocode into Python1:

+
class SuperKarel(Karel):
# you can define your own helper functions on Karel here, if you wish to

def found_exit(self) -> bool:
if not self.beepers_present():
return False

self.pick_beeper()
if self.beepers_present():
self.put_beeper()
return False

self.put_beeper()
return True

def turn_around(self):
for _ in range(2):
self.turn_left()

def turn_right(self):
for _ in range(3):
self.turn_left()

def find_exit(self) -> bool:
if self.found_exit():
return True

# check left
if self.left_is_clear():
self.turn_left()
self.step()
if self.find_exit():
return True

self.turn_around()
self.step()
self.turn_left()

# check front
if self.front_is_clear():
self.step()
if self.find_exit():
return True

self.turn_around()
self.step()
self.turn_around()

# check right
if self.right_is_clear():
self.turn_right()
self.step()
if self.find_exit():
return True

self.turn_around()
self.step()
self.turn_right()

return False

def run(self):
self.find_exit()
+

We have relatively repetitive code for checking each of the directions, I would +propose to refactor a bit, in a fashion of checkin just forward, so it's more +readable:

+
def find_exit(self) -> bool:
if self.found_exit():
return True

self.turn_left()
for _ in range(3):
if self.front_is_blocked():
self.turn_right()
continue

self.step()
if self.find_exit():
return True

self.step()
self.turn_around()
self.turn_right()

return False
+

We can also notice that turning around takes 2 left turns and turning to right +does 3. We get 5 left turns in total when we turn around and right afterwards… +Taking 4 left turns just rotates us back to our initial direction, therefore it +is sufficient to do just one left turn (5 % 4 == 1). That way we get:

+
def find_exit(self) -> bool:
if self.found_exit():
return True

self.turn_left()
for _ in range(3):
if self.front_is_blocked():
self.turn_right()
continue

self.step()
if self.find_exit():
return True

self.step()
# turning around and right is same as one turn to the left
self.turn_left()

return False
+

Testing

+

In the skeleton, with the previous post, I have included multiple mazes that can +be tested. I have tried this solution with all of the given mazes, and it was +successful in finding the exit. However there is one precondition of our +solution that we haven't spoken about.

+

We are silently expecting the maze not to have any loops. Example of such +maze can be the maze666.kw:

+
┌─────────┬─┐
│. . . . .│.│
│ ┌─────┐ │ │
│.│. . .│.│.│
│ │ │ │ │ │
│.│.│. . .│.│
│ │ │ └─┤
│.│.│. . . 1│
│ │ │ │ ┌─┤
│.│. . .│.│.│
│ └─────┘ │ │
│. > . . .│.│
└─────────┴─┘
+

If you try running our solution on this map, Karel just loops and never finds +the solution. Let's have a look at the loop he gets stuck in:

+
┌─────────┬─┐
│* * * * *│.│
│ ┌─────┐ │ │
│*│* * *│*│.│
│ │ │ │ │ │
│*│*│. * *│.│
│ │ │ └─┤
│*│*│. * * 1│
│ │ │ │ ┌─┤
│*│* * *│*│.│
│ └─────┘ │ │
│* * * * *│.│
└─────────┴─┘
+

He walks past the exit, but can't see it, cause there's always a feasible path +that is worth trying.

+
Algorithm

The algorithm we have written to find the exit is a depth-first search (DFS). +However, as opposed to the usual implementation, we have no notion of paths that +are being (or have already been) explored.

+

Fixing the issue

+

Since we are not allowed to use variables, the only way to resolve this issue is +to mark the “cells” that we have tried. We can easily use beepers for this, but +we need to be careful not to confuse the exit with already visited cell.

+

To do that we'll use 2 beepers instead of the one. Implementation follows:

+
def visited(self) -> bool:
if not self.beepers_present():
return False

self.pick_beeper()
if not self.beepers_present():
self.put_beeper()
return False

self.pick_beeper()
if self.beepers_present():
assert False, "no cell shall be marked with 3 beepers"

self.put_beeper()
self.put_beeper()
return True


def find_exit(self) -> bool:
# BASE: already tried
if self.visited():
self.turn_around()
return False

# BASE
if self.found_exit():
return True

# mark the cell as visited
for _ in range(2):
self.put_beeper()

self.turn_left()
for _ in range(3):
if self.front_is_blocked():
self.turn_right()
continue

self.step()
if self.find_exit():
return True

self.step()
# turning around and right is same as one turn to the left
self.turn_left()

return False
+

Now our solution works also for mazes that have loops.

+

Footnotes

+
    +
  1. +

    which is usually very easy matter

    +
  2. +
+
+ + \ No newline at end of file diff --git a/algorithms/recursion/pyramid-slide-down/index.html b/algorithms/recursion/pyramid-slide-down/index.html index 9e58d34..bb5fb17 100644 --- a/algorithms/recursion/pyramid-slide-down/index.html +++ b/algorithms/recursion/pyramid-slide-down/index.html @@ -16,11 +16,11 @@ - - + + -

Introduction to dynamic programming

In this post we will try to solve one problem in different ways.

+ +
\ No newline at end of file diff --git a/algorithms/tags/applications/index.html b/algorithms/tags/applications/index.html index 02ad29b..b0c4d8f 100644 --- a/algorithms/tags/applications/index.html +++ b/algorithms/tags/applications/index.html @@ -14,8 +14,8 @@ - - + +

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Použití červeno-černých stromů

Ukázka použití červeno-černých stromů v standardních knižnicích známých jazyků. diff --git a/algorithms/tags/backtracking/index.html b/algorithms/tags/backtracking/index.html index 3654e96..a1811a1 100644 --- a/algorithms/tags/backtracking/index.html +++ b/algorithms/tags/backtracking/index.html @@ -3,7 +3,7 @@ -One doc tagged with "backtracking" | mf +2 docs tagged with "backtracking" | mf @@ -14,11 +14,12 @@ - - + + -

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Recursion and backtracking with Robot Karel

A problem with too many restrictions. +

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2 docs tagged with "balanced trees"

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On the rules of the red-black tree

Shower thoughts on the rules of the red-black tree. diff --git a/algorithms/tags/bfs/index.html b/algorithms/tags/bfs/index.html index fe419f4..e313ee4 100644 --- a/algorithms/tags/bfs/index.html +++ b/algorithms/tags/bfs/index.html @@ -14,8 +14,8 @@ - - + +

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Distance boundaries from BFS tree on undirected graphs

Short explanation of distance boundaries deduced from a BFS tree. diff --git a/algorithms/tags/bottom-up-dp/index.html b/algorithms/tags/bottom-up-dp/index.html index c1995fc..75985fc 100644 --- a/algorithms/tags/bottom-up-dp/index.html +++ b/algorithms/tags/bottom-up-dp/index.html @@ -14,8 +14,8 @@ - - + +

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Introduction to dynamic programming

Solving a problem in different ways. diff --git a/algorithms/tags/c/index.html b/algorithms/tags/c/index.html index 42e2f6b..ac416a5 100644 --- a/algorithms/tags/c/index.html +++ b/algorithms/tags/c/index.html @@ -14,8 +14,8 @@ - - + +

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Time complexity of ‹extend›

How to make inefficient algorithm unknowingly. diff --git a/algorithms/tags/cpp/index.html b/algorithms/tags/cpp/index.html index 7ff8940..b4ab7a0 100644 --- a/algorithms/tags/cpp/index.html +++ b/algorithms/tags/cpp/index.html @@ -14,8 +14,8 @@ - - + +

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Breaking Hash Table

How to get the linear time complexity in a hash table. diff --git a/algorithms/tags/csharp/index.html b/algorithms/tags/csharp/index.html index 0019ea7..edf0326 100644 --- a/algorithms/tags/csharp/index.html +++ b/algorithms/tags/csharp/index.html @@ -14,8 +14,8 @@ - - + +

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Iterative algorithms via iterators

Iterative DFS using iterators. diff --git a/algorithms/tags/dynamic-array/index.html b/algorithms/tags/dynamic-array/index.html index 9fc8195..1bd17d8 100644 --- a/algorithms/tags/dynamic-array/index.html +++ b/algorithms/tags/dynamic-array/index.html @@ -14,8 +14,8 @@ - - + +

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Time complexity of ‹extend›

How to make inefficient algorithm unknowingly. diff --git a/algorithms/tags/dynamic-programming/index.html b/algorithms/tags/dynamic-programming/index.html index 5613ef8..a29290b 100644 --- a/algorithms/tags/dynamic-programming/index.html +++ b/algorithms/tags/dynamic-programming/index.html @@ -14,8 +14,8 @@ - - + +

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Introduction to dynamic programming

Solving a problem in different ways. diff --git a/algorithms/tags/exponential/index.html b/algorithms/tags/exponential/index.html index 626713e..79cf4b3 100644 --- a/algorithms/tags/exponential/index.html +++ b/algorithms/tags/exponential/index.html @@ -14,8 +14,8 @@ - - + +

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Introduction to dynamic programming

Solving a problem in different ways. diff --git a/algorithms/tags/graphs/index.html b/algorithms/tags/graphs/index.html index b3dd1ed..4aa9cf0 100644 --- a/algorithms/tags/graphs/index.html +++ b/algorithms/tags/graphs/index.html @@ -14,8 +14,8 @@ - - + +

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Distance boundaries from BFS tree on undirected graphs

Short explanation of distance boundaries deduced from a BFS tree. diff --git a/algorithms/tags/greedy/index.html b/algorithms/tags/greedy/index.html index d2f54bb..3ef0cf3 100644 --- a/algorithms/tags/greedy/index.html +++ b/algorithms/tags/greedy/index.html @@ -14,8 +14,8 @@ - - + +

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Introduction to dynamic programming

Solving a problem in different ways. diff --git a/algorithms/tags/hash-tables/index.html b/algorithms/tags/hash-tables/index.html index 64bfb41..563d7e5 100644 --- a/algorithms/tags/hash-tables/index.html +++ b/algorithms/tags/hash-tables/index.html @@ -14,8 +14,8 @@ - - + +

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Breaking Hash Table

How to get the linear time complexity in a hash table. diff --git a/algorithms/tags/index.html b/algorithms/tags/index.html index 628ce8e..a363492 100644 --- a/algorithms/tags/index.html +++ b/algorithms/tags/index.html @@ -14,10 +14,10 @@ - - + + -

+ \ No newline at end of file diff --git a/algorithms/tags/iterative/index.html b/algorithms/tags/iterative/index.html index 8428772..e930d0b 100644 --- a/algorithms/tags/iterative/index.html +++ b/algorithms/tags/iterative/index.html @@ -14,8 +14,8 @@ - - + +

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Iterative algorithms via iterators

Iterative DFS using iterators. diff --git a/algorithms/tags/iterators/index.html b/algorithms/tags/iterators/index.html index 47f06bf..0a0c88f 100644 --- a/algorithms/tags/iterators/index.html +++ b/algorithms/tags/iterators/index.html @@ -14,8 +14,8 @@ - - + +

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Iterative algorithms via iterators

Iterative DFS using iterators. diff --git a/algorithms/tags/java/index.html b/algorithms/tags/java/index.html index cd113ba..7c0e470 100644 --- a/algorithms/tags/java/index.html +++ b/algorithms/tags/java/index.html @@ -14,8 +14,8 @@ - - + +

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Introduction to dynamic programming

Solving a problem in different ways. diff --git a/algorithms/tags/karel/index.html b/algorithms/tags/karel/index.html index 5c4291a..0de55f3 100644 --- a/algorithms/tags/karel/index.html +++ b/algorithms/tags/karel/index.html @@ -3,7 +3,7 @@ -One doc tagged with "karel" | mf +2 docs tagged with "karel" | mf @@ -14,11 +14,12 @@ - - + + -

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Recursion and backtracking with Robot Karel

A problem with too many restrictions. +

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Vague postconditions and proving correctness of algorithms

Debugging and testing with precise postconditions. diff --git a/algorithms/tags/python/index.html b/algorithms/tags/python/index.html index 8062c62..8db2a8d 100644 --- a/algorithms/tags/python/index.html +++ b/algorithms/tags/python/index.html @@ -3,7 +3,7 @@ -6 docs tagged with "python" | mf +7 docs tagged with "python" | mf @@ -14,14 +14,15 @@ - - + + -

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Breaking Hash Table

How to get the linear time complexity in a hash table. +

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diff --git a/algorithms/tags/recursion/index.html b/algorithms/tags/recursion/index.html index 80f7b07..254c958 100644 --- a/algorithms/tags/recursion/index.html +++ b/algorithms/tags/recursion/index.html @@ -3,7 +3,7 @@ -3 docs tagged with "recursion" | mf +4 docs tagged with "recursion" | mf @@ -14,12 +14,13 @@ - - + + -

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Recursion and backtracking with Robot Karel

A problem with too many restrictions. +

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diff --git a/algorithms/tags/red-black-trees/index.html b/algorithms/tags/red-black-trees/index.html index f84bbdc..dc94a21 100644 --- a/algorithms/tags/red-black-trees/index.html +++ b/algorithms/tags/red-black-trees/index.html @@ -14,8 +14,8 @@ - - + +

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On the rules of the red-black tree

Shower thoughts on the rules of the red-black tree. diff --git a/algorithms/tags/solution/index.html b/algorithms/tags/solution/index.html new file mode 100644 index 0000000..0b8a879 --- /dev/null +++ b/algorithms/tags/solution/index.html @@ -0,0 +1,24 @@ + + + + + +One doc tagged with "solution" | mf + + + + + + + + + + + + + + +

One doc tagged with "solution"

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+ + \ No newline at end of file diff --git a/algorithms/tags/sorting/index.html b/algorithms/tags/sorting/index.html index 488af43..9b1ff51 100644 --- a/algorithms/tags/sorting/index.html +++ b/algorithms/tags/sorting/index.html @@ -14,8 +14,8 @@ - - + +

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Vague postconditions and proving correctness of algorithms

Debugging and testing with precise postconditions. diff --git a/algorithms/tags/testing/index.html b/algorithms/tags/testing/index.html index aca234a..401709d 100644 --- a/algorithms/tags/testing/index.html +++ b/algorithms/tags/testing/index.html @@ -14,8 +14,8 @@ - - + +

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Vague postconditions and proving correctness of algorithms

Debugging and testing with precise postconditions. diff --git a/algorithms/tags/time-complexity/index.html b/algorithms/tags/time-complexity/index.html index ac8b92a..78c6f34 100644 --- a/algorithms/tags/time-complexity/index.html +++ b/algorithms/tags/time-complexity/index.html @@ -14,8 +14,8 @@ - - + +

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Time complexity of ‹extend›

How to make inefficient algorithm unknowingly. diff --git a/algorithms/tags/top-down-dp/index.html b/algorithms/tags/top-down-dp/index.html index 651a19e..70acac6 100644 --- a/algorithms/tags/top-down-dp/index.html +++ b/algorithms/tags/top-down-dp/index.html @@ -14,8 +14,8 @@ - - + +

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Introduction to dynamic programming

Solving a problem in different ways. diff --git a/algorithms/time-complexity/extend/index.html b/algorithms/time-complexity/extend/index.html index 93bcaa1..bd65409 100644 --- a/algorithms/time-complexity/extend/index.html +++ b/algorithms/time-complexity/extend/index.html @@ -16,8 +16,8 @@ - - + +

Time complexity of ‹extend›

Introduction

diff --git a/assets/js/1535ede8.c4da4d68.js b/assets/js/1535ede8.f94d015a.js similarity index 99% rename from assets/js/1535ede8.c4da4d68.js rename to assets/js/1535ede8.f94d015a.js index 567038d..7bfe18e 100644 --- a/assets/js/1535ede8.c4da4d68.js +++ b/assets/js/1535ede8.f94d015a.js @@ -1 +1 @@ -"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[5376],{44969:(e,n,t)=>{t.r(n),t.d(n,{assets:()=>c,contentTitle:()=>o,default:()=>h,frontMatter:()=>r,metadata:()=>a,toc:()=>l});var s=t(85893),i=t(11151);const r={id:"seminar-10",title:"10th seminar",description:"Finding bugs in a hangman.\n"},o=void 0,a={id:"bonuses/seminar-10",title:"10th seminar",description:"Finding bugs in a hangman.\n",source:"@site/c/bonuses/10.md",sourceDirName:"bonuses",slug:"/bonuses/seminar-10",permalink:"/c/bonuses/seminar-10",draft:!1,unlisted:!1,editUrl:"https://github.com/mfocko/blog/tree/main/c/bonuses/10.md",tags:[],version:"current",lastUpdatedAt:1701271124,formattedLastUpdatedAt:"Nov 29, 2023",frontMatter:{id:"seminar-10",title:"10th seminar",description:"Finding bugs in a hangman.\n"},sidebar:"autogeneratedBar",previous:{title:"8th seminar",permalink:"/c/bonuses/seminar-08"},next:{title:"Practice Exams",permalink:"/c/category/practice-exams"}},c={},l=[{value:"Introduction",id:"introduction",level:2},{value:"Project",id:"project",level:2},{value:"Summary of the gameplay",id:"summary-of-the-gameplay",level:3},{value:"Suggested workflow",id:"suggested-workflow",level:2},{value:"Tasks",id:"tasks",level:2},{value:"Dictionary",id:"dictionary",level:2},{value:"Submitting",id:"submitting",level:2}];function d(e){const n={a:"a",blockquote:"blockquote",code:"code",em:"em",h2:"h2",h3:"h3",hr:"hr",img:"img",li:"li",ol:"ol",p:"p",pre:"pre",table:"table",tbody:"tbody",td:"td",th:"th",thead:"thead",tr:"tr",ul:"ul",...(0,i.a)(),...e.components};return(0,s.jsxs)(s.Fragment,{children:[(0,s.jsx)(n.p,{children:(0,s.jsx)(n.a,{href:"pathname:///files/c/bonuses/10.tar.gz",children:"Source"})}),"\n",(0,s.jsx)(n.h2,{id:"introduction",children:"Introduction"}),"\n",(0,s.jsx)(n.p,{children:"For this bonus you are given almost finished project - The Hangman Game. Your\ntask is to try the game, in case you find any bugs point them out and cover as\nmuch of the game as possible with tests."}),"\n",(0,s.jsx)(n.p,{children:"For this bonus you can get at maximum 2 K\u20a1."}),"\n",(0,s.jsxs)(n.table,{children:[(0,s.jsx)(n.thead,{children:(0,s.jsxs)(n.tr,{children:[(0,s.jsx)(n.th,{children:"Item"}),(0,s.jsx)(n.th,{children:"Bonus"})]})}),(0,s.jsxs)(n.tbody,{children:[(0,s.jsxs)(n.tr,{children:[(0,s.jsx)(n.td,{children:"Fixing bugs from failing tests"}),(0,s.jsx)(n.td,{children:"0.25"})]}),(0,s.jsxs)(n.tr,{children:[(0,s.jsx)(n.td,{children:(0,s.jsx)(n.code,{children:"word_guessed"})}),(0,s.jsx)(n.td,{children:"0.50"})]}),(0,s.jsxs)(n.tr,{children:[(0,s.jsx)(n.td,{children:"Hidden bug"}),(0,s.jsx)(n.td,{children:"0.50"})]}),(0,s.jsxs)(n.tr,{children:[(0,s.jsx)(n.td,{children:"Extending tests, undetectable bugs or evil bug"}),(0,s.jsx)(n.td,{children:"0.37"})]}),(0,s.jsxs)(n.tr,{children:[(0,s.jsx)(n.td,{children:"Refactor"}),(0,s.jsx)(n.td,{children:"0.38"})]})]})]}),"\n",(0,s.jsx)(n.h2,{id:"project",children:"Project"}),"\n",(0,s.jsxs)(n.p,{children:["Project consists of 2 source files - ",(0,s.jsx)(n.code,{children:"hangman.c"})," and ",(0,s.jsx)(n.code,{children:"main.c"}),"."]}),"\n",(0,s.jsxs)(n.p,{children:[(0,s.jsx)(n.code,{children:"main.c"})," is quite short and concise, there is nothing for you to do."]}),"\n",(0,s.jsxs)(n.p,{children:[(0,s.jsx)(n.code,{children:"hangman.c"})," contains implementation of the game. In case you feel lost, consult\nthe documentation in ",(0,s.jsx)(n.code,{children:"hangman.h"})," that represents an interface that can be used\nfor implementing the game."]}),"\n",(0,s.jsxs)(n.p,{children:["Apart from those sources this project is a bit more complicated. ",(0,s.jsx)(n.em,{children:"Game loop"})," is\nrealised via single encapsulated function that complicates the testing. Because\nof that, there are 2 kinds of tests:"]}),"\n",(0,s.jsxs)(n.ul,{children:["\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsxs)(n.p,{children:[(0,s.jsx)(n.em,{children:"Unit tests"})," - that are present in ",(0,s.jsx)(n.code,{children:"test_hangman.c"})," and can be run via:"]}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{children:"$ make check-unit\n"})}),"\n",(0,s.jsx)(n.p,{children:"They cover majorly functions that can be tested easily via testing framework."}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsxs)(n.p,{children:[(0,s.jsx)(n.em,{children:"Functional tests"})," - same as in ",(0,s.jsx)(n.code,{children:"seminar-08"})," and are focused on testing the\nprogram as whole. Basic smoke test is already included in ",(0,s.jsx)(n.code,{children:"usage"})," test case."]}),"\n",(0,s.jsx)(n.p,{children:"They can be run via:"}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{children:"$ make check-functional\n"})}),"\n",(0,s.jsxs)(n.p,{children:["When testing ",(0,s.jsx)(n.code,{children:"hangman"})," function (the game loop), it is suggested to create\nfunctional tests."]}),"\n",(0,s.jsx)(n.p,{children:"When submitting the files for review, please leave out functional tests that\nwere given as a part of the assignment, so that it is easier to navigate, I\nwill drag the common files myself. :)"}),"\n"]}),"\n"]}),"\n",(0,s.jsxs)(n.blockquote,{children:["\n",(0,s.jsx)(n.p,{children:"Whole test suite can be run via:"}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{children:"$ make check\n"})}),"\n"]}),"\n",(0,s.jsx)(n.h3,{id:"summary-of-the-gameplay",children:"Summary of the gameplay"}),"\n",(0,s.jsxs)(n.ol,{children:["\n",(0,s.jsx)(n.li,{children:"Secret word gets chosen from the file that's path is given as an argument."}),"\n",(0,s.jsx)(n.li,{children:"You get 8 guesses."}),"\n",(0,s.jsx)(n.li,{children:"Invalid characters don't count."}),"\n",(0,s.jsx)(n.li,{children:"Already guessed characters don't count, even if not included in the secret."}),"\n",(0,s.jsxs)(n.li,{children:["You can guess the whole word at once","\n",(0,s.jsxs)(n.ul,{children:["\n",(0,s.jsx)(n.li,{children:"If you get it right, you won, game ends."}),"\n",(0,s.jsx)(n.li,{children:"If you don't get it right, you get to see the secret, game ends."}),"\n"]}),"\n"]}),"\n",(0,s.jsx)(n.li,{children:"In case of end of input, game finishes via force."}),"\n",(0,s.jsx)(n.li,{children:"In case of invalid input, no guesses are subtracted, game carries on."}),"\n",(0,s.jsx)(n.li,{children:"Letters and words are not case sensitive."}),"\n"]}),"\n",(0,s.jsx)(n.h2,{id:"suggested-workflow",children:"Suggested workflow"}),"\n",(0,s.jsxs)(n.p,{children:["As we have talked about on the seminar, I suggest you to follow\n",(0,s.jsx)(n.em,{children:"Test-Driven Development"}),"\nin this case."]}),"\n",(0,s.jsx)(n.p,{children:(0,s.jsx)(n.img,{alt:"TDD workflow",src:t(27420).Z+"",width:"2814",height:"1652"})}),"\n",(0,s.jsx)(n.p,{children:"In our current scenario we are already in the stage of refactoring and fixing the\nbugs. Therefore try to follow this succession of steps:"}),"\n",(0,s.jsxs)(n.ol,{children:["\n",(0,s.jsx)(n.li,{children:"Try to reproduce the bug."}),"\n",(0,s.jsx)(n.li,{children:"Create a test that proves the presence of the bug."}),"\n",(0,s.jsx)(n.li,{children:"Fix the bug."}),"\n"]}),"\n",(0,s.jsxs)(n.p,{children:["In case you are submitting the bonus via GitLab, it is helpful to commit tests\nbefore commiting the fixes, so that it is apparent that the bug is manifested.\nExample of ",(0,s.jsx)(n.code,{children:"git log"})," (notice that the first line represents latest commit):"]}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{children:"feat: Implement fizz_buzzer\ntest: Add tests for fizz_buzzer\nfix: Fix NULL-check in print_name\ntest: Add test for NULL in print_name\n"})}),"\n",(0,s.jsx)(n.h2,{id:"tasks",children:"Tasks"}),"\n",(0,s.jsx)(n.p,{children:"As to your tasks, there are multiple things wrong in this project."}),"\n",(0,s.jsxs)(n.ol,{children:["\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsx)(n.p,{children:'There are 2 "bugs" that cannot be detected via tests, i.e. they are not bugs\nthat affect functionality of the game.'}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsxs)(n.p,{children:["There is one evil bug in ",(0,s.jsx)(n.code,{children:"get_word"}),". It is not required to be fixed ;) Assign\nit the lowest priority."]}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsx)(n.p,{children:"There are some tests failing. Please try to figure it out, so you have green\ntests for the rest :)"}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsxs)(n.p,{children:["We have gotten a bug report for ",(0,s.jsx)(n.code,{children:"word_guessed"}),", all we got is"]}),"\n",(0,s.jsxs)(n.blockquote,{children:["\n",(0,s.jsxs)(n.p,{children:["doesn't work when there are too many ",(0,s.jsx)(n.code,{children:"a"}),"s"]}),"\n"]}),"\n",(0,s.jsx)(n.p,{children:"Please try to replicate the bug and create a tests, so we don't get any\nregression later on."}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsx)(n.p,{children:"One hidden bug :) Closely non-specified, we cannot reproduce it and we were\ndrunk while playing the game, so we don't remember a thing. :/"}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsx)(n.p,{children:"Try to cover as much code via the tests as possible. We are not going to look\nat the metrics, but DRY is violated a lot, so as a last task try to remove as\nmuch of the duplicit code as possible."}),"\n",(0,s.jsx)(n.p,{children:"Tests should help you a lot in case there are some regressions."}),"\n"]}),"\n"]}),"\n",(0,s.jsx)(n.hr,{}),"\n",(0,s.jsxs)(n.p,{children:["In case you wonder why there are always 3 same words in the file with words, it\nis because of the ",(0,s.jsx)(n.code,{children:"get_word"})," bug. It is not a bug that can be easily fixed, so\nit is a not requirement at all and you can still get all points for the bonus ;)"]}),"\n",(0,s.jsx)(n.h2,{id:"dictionary",children:"Dictionary"}),"\n",(0,s.jsxs)(n.ul,{children:["\n",(0,s.jsx)(n.li,{children:(0,s.jsx)(n.a,{href:"https://en.wikipedia.org/wiki/Functional_testing",children:"Functional tests"})}),"\n",(0,s.jsx)(n.li,{children:(0,s.jsx)(n.a,{href:"https://en.wikipedia.org/wiki/Smoke_testing_%28software%29",children:"Smoke test"})}),"\n",(0,s.jsx)(n.li,{children:(0,s.jsx)(n.a,{href:"https://en.wikipedia.org/wiki/Don%27t_repeat_yourself",children:"DRY"})}),"\n"]}),"\n",(0,s.jsx)(n.h2,{id:"submitting",children:"Submitting"}),"\n",(0,s.jsx)(n.p,{children:"In case you have any questions, feel free to reach out to me."}),"\n",(0,s.jsx)(n.hr,{})]})}function h(e={}){const{wrapper:n}={...(0,i.a)(),...e.components};return n?(0,s.jsx)(n,{...e,children:(0,s.jsx)(d,{...e})}):d(e)}},27420:(e,n,t)=>{t.d(n,{Z:()=>s});const s=t.p+"assets/images/tdd_lifecycle-327ad9ee0ed8318ed11e19a28e02b2cc.png"},11151:(e,n,t)=>{t.d(n,{Z:()=>a,a:()=>o});var s=t(67294);const i={},r=s.createContext(i);function o(e){const n=s.useContext(r);return s.useMemo((function(){return"function"==typeof e?e(n):{...n,...e}}),[n,e])}function a(e){let n;return n=e.disableParentContext?"function"==typeof e.components?e.components(i):e.components||i:o(e.components),s.createElement(r.Provider,{value:n},e.children)}}}]); \ No newline at end of file +"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[5376],{44969:(e,n,t)=>{t.r(n),t.d(n,{assets:()=>c,contentTitle:()=>o,default:()=>h,frontMatter:()=>r,metadata:()=>a,toc:()=>l});var s=t(85893),i=t(11151);const r={id:"seminar-10",title:"10th seminar",description:"Finding bugs in a hangman.\n"},o=void 0,a={id:"bonuses/seminar-10",title:"10th seminar",description:"Finding bugs in a hangman.\n",source:"@site/c/bonuses/10.md",sourceDirName:"bonuses",slug:"/bonuses/seminar-10",permalink:"/c/bonuses/seminar-10",draft:!1,unlisted:!1,editUrl:"https://github.com/mfocko/blog/tree/main/c/bonuses/10.md",tags:[],version:"current",lastUpdatedAt:1703373170,formattedLastUpdatedAt:"Dec 23, 2023",frontMatter:{id:"seminar-10",title:"10th seminar",description:"Finding bugs in a hangman.\n"},sidebar:"autogeneratedBar",previous:{title:"8th seminar",permalink:"/c/bonuses/seminar-08"},next:{title:"Practice Exams",permalink:"/c/category/practice-exams"}},c={},l=[{value:"Introduction",id:"introduction",level:2},{value:"Project",id:"project",level:2},{value:"Summary of the gameplay",id:"summary-of-the-gameplay",level:3},{value:"Suggested workflow",id:"suggested-workflow",level:2},{value:"Tasks",id:"tasks",level:2},{value:"Dictionary",id:"dictionary",level:2},{value:"Submitting",id:"submitting",level:2}];function d(e){const n={a:"a",blockquote:"blockquote",code:"code",em:"em",h2:"h2",h3:"h3",hr:"hr",img:"img",li:"li",ol:"ol",p:"p",pre:"pre",table:"table",tbody:"tbody",td:"td",th:"th",thead:"thead",tr:"tr",ul:"ul",...(0,i.a)(),...e.components};return(0,s.jsxs)(s.Fragment,{children:[(0,s.jsx)(n.p,{children:(0,s.jsx)(n.a,{href:"pathname:///files/c/bonuses/10.tar.gz",children:"Source"})}),"\n",(0,s.jsx)(n.h2,{id:"introduction",children:"Introduction"}),"\n",(0,s.jsx)(n.p,{children:"For this bonus you are given almost finished project - The Hangman Game. Your\ntask is to try the game, in case you find any bugs point them out and cover as\nmuch of the game as possible with tests."}),"\n",(0,s.jsx)(n.p,{children:"For this bonus you can get at maximum 2 K\u20a1."}),"\n",(0,s.jsxs)(n.table,{children:[(0,s.jsx)(n.thead,{children:(0,s.jsxs)(n.tr,{children:[(0,s.jsx)(n.th,{children:"Item"}),(0,s.jsx)(n.th,{children:"Bonus"})]})}),(0,s.jsxs)(n.tbody,{children:[(0,s.jsxs)(n.tr,{children:[(0,s.jsx)(n.td,{children:"Fixing bugs from failing tests"}),(0,s.jsx)(n.td,{children:"0.25"})]}),(0,s.jsxs)(n.tr,{children:[(0,s.jsx)(n.td,{children:(0,s.jsx)(n.code,{children:"word_guessed"})}),(0,s.jsx)(n.td,{children:"0.50"})]}),(0,s.jsxs)(n.tr,{children:[(0,s.jsx)(n.td,{children:"Hidden bug"}),(0,s.jsx)(n.td,{children:"0.50"})]}),(0,s.jsxs)(n.tr,{children:[(0,s.jsx)(n.td,{children:"Extending tests, undetectable bugs or evil bug"}),(0,s.jsx)(n.td,{children:"0.37"})]}),(0,s.jsxs)(n.tr,{children:[(0,s.jsx)(n.td,{children:"Refactor"}),(0,s.jsx)(n.td,{children:"0.38"})]})]})]}),"\n",(0,s.jsx)(n.h2,{id:"project",children:"Project"}),"\n",(0,s.jsxs)(n.p,{children:["Project consists of 2 source files - ",(0,s.jsx)(n.code,{children:"hangman.c"})," and ",(0,s.jsx)(n.code,{children:"main.c"}),"."]}),"\n",(0,s.jsxs)(n.p,{children:[(0,s.jsx)(n.code,{children:"main.c"})," is quite short and concise, there is nothing for you to do."]}),"\n",(0,s.jsxs)(n.p,{children:[(0,s.jsx)(n.code,{children:"hangman.c"})," contains implementation of the game. In case you feel lost, consult\nthe documentation in ",(0,s.jsx)(n.code,{children:"hangman.h"})," that represents an interface that can be used\nfor implementing the game."]}),"\n",(0,s.jsxs)(n.p,{children:["Apart from those sources this project is a bit more complicated. ",(0,s.jsx)(n.em,{children:"Game loop"})," is\nrealised via single encapsulated function that complicates the testing. Because\nof that, there are 2 kinds of tests:"]}),"\n",(0,s.jsxs)(n.ul,{children:["\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsxs)(n.p,{children:[(0,s.jsx)(n.em,{children:"Unit tests"})," - that are present in ",(0,s.jsx)(n.code,{children:"test_hangman.c"})," and can be run via:"]}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{children:"$ make check-unit\n"})}),"\n",(0,s.jsx)(n.p,{children:"They cover majorly functions that can be tested easily via testing framework."}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsxs)(n.p,{children:[(0,s.jsx)(n.em,{children:"Functional tests"})," - same as in ",(0,s.jsx)(n.code,{children:"seminar-08"})," and are focused on testing the\nprogram as whole. Basic smoke test is already included in ",(0,s.jsx)(n.code,{children:"usage"})," test case."]}),"\n",(0,s.jsx)(n.p,{children:"They can be run via:"}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{children:"$ make check-functional\n"})}),"\n",(0,s.jsxs)(n.p,{children:["When testing ",(0,s.jsx)(n.code,{children:"hangman"})," function (the game loop), it is suggested to create\nfunctional tests."]}),"\n",(0,s.jsx)(n.p,{children:"When submitting the files for review, please leave out functional tests that\nwere given as a part of the assignment, so that it is easier to navigate, I\nwill drag the common files myself. :)"}),"\n"]}),"\n"]}),"\n",(0,s.jsxs)(n.blockquote,{children:["\n",(0,s.jsx)(n.p,{children:"Whole test suite can be run via:"}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{children:"$ make check\n"})}),"\n"]}),"\n",(0,s.jsx)(n.h3,{id:"summary-of-the-gameplay",children:"Summary of the gameplay"}),"\n",(0,s.jsxs)(n.ol,{children:["\n",(0,s.jsx)(n.li,{children:"Secret word gets chosen from the file that's path is given as an argument."}),"\n",(0,s.jsx)(n.li,{children:"You get 8 guesses."}),"\n",(0,s.jsx)(n.li,{children:"Invalid characters don't count."}),"\n",(0,s.jsx)(n.li,{children:"Already guessed characters don't count, even if not included in the secret."}),"\n",(0,s.jsxs)(n.li,{children:["You can guess the whole word at once","\n",(0,s.jsxs)(n.ul,{children:["\n",(0,s.jsx)(n.li,{children:"If you get it right, you won, game ends."}),"\n",(0,s.jsx)(n.li,{children:"If you don't get it right, you get to see the secret, game ends."}),"\n"]}),"\n"]}),"\n",(0,s.jsx)(n.li,{children:"In case of end of input, game finishes via force."}),"\n",(0,s.jsx)(n.li,{children:"In case of invalid input, no guesses are subtracted, game carries on."}),"\n",(0,s.jsx)(n.li,{children:"Letters and words are not case sensitive."}),"\n"]}),"\n",(0,s.jsx)(n.h2,{id:"suggested-workflow",children:"Suggested workflow"}),"\n",(0,s.jsxs)(n.p,{children:["As we have talked about on the seminar, I suggest you to follow\n",(0,s.jsx)(n.em,{children:"Test-Driven Development"}),"\nin this case."]}),"\n",(0,s.jsx)(n.p,{children:(0,s.jsx)(n.img,{alt:"TDD workflow",src:t(27420).Z+"",width:"2814",height:"1652"})}),"\n",(0,s.jsx)(n.p,{children:"In our current scenario we are already in the stage of refactoring and fixing the\nbugs. Therefore try to follow this succession of steps:"}),"\n",(0,s.jsxs)(n.ol,{children:["\n",(0,s.jsx)(n.li,{children:"Try to reproduce the bug."}),"\n",(0,s.jsx)(n.li,{children:"Create a test that proves the presence of the bug."}),"\n",(0,s.jsx)(n.li,{children:"Fix the bug."}),"\n"]}),"\n",(0,s.jsxs)(n.p,{children:["In case you are submitting the bonus via GitLab, it is helpful to commit tests\nbefore commiting the fixes, so that it is apparent that the bug is manifested.\nExample of ",(0,s.jsx)(n.code,{children:"git log"})," (notice that the first line represents latest commit):"]}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{children:"feat: Implement fizz_buzzer\ntest: Add tests for fizz_buzzer\nfix: Fix NULL-check in print_name\ntest: Add test for NULL in print_name\n"})}),"\n",(0,s.jsx)(n.h2,{id:"tasks",children:"Tasks"}),"\n",(0,s.jsx)(n.p,{children:"As to your tasks, there are multiple things wrong in this project."}),"\n",(0,s.jsxs)(n.ol,{children:["\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsx)(n.p,{children:'There are 2 "bugs" that cannot be detected via tests, i.e. they are not bugs\nthat affect functionality of the game.'}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsxs)(n.p,{children:["There is one evil bug in ",(0,s.jsx)(n.code,{children:"get_word"}),". It is not required to be fixed ;) Assign\nit the lowest priority."]}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsx)(n.p,{children:"There are some tests failing. Please try to figure it out, so you have green\ntests for the rest :)"}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsxs)(n.p,{children:["We have gotten a bug report for ",(0,s.jsx)(n.code,{children:"word_guessed"}),", all we got is"]}),"\n",(0,s.jsxs)(n.blockquote,{children:["\n",(0,s.jsxs)(n.p,{children:["doesn't work when there are too many ",(0,s.jsx)(n.code,{children:"a"}),"s"]}),"\n"]}),"\n",(0,s.jsx)(n.p,{children:"Please try to replicate the bug and create a tests, so we don't get any\nregression later on."}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsx)(n.p,{children:"One hidden bug :) Closely non-specified, we cannot reproduce it and we were\ndrunk while playing the game, so we don't remember a thing. :/"}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsx)(n.p,{children:"Try to cover as much code via the tests as possible. We are not going to look\nat the metrics, but DRY is violated a lot, so as a last task try to remove as\nmuch of the duplicit code as possible."}),"\n",(0,s.jsx)(n.p,{children:"Tests should help you a lot in case there are some regressions."}),"\n"]}),"\n"]}),"\n",(0,s.jsx)(n.hr,{}),"\n",(0,s.jsxs)(n.p,{children:["In case you wonder why there are always 3 same words in the file with words, it\nis because of the ",(0,s.jsx)(n.code,{children:"get_word"})," bug. It is not a bug that can be easily fixed, so\nit is a not requirement at all and you can still get all points for the bonus ;)"]}),"\n",(0,s.jsx)(n.h2,{id:"dictionary",children:"Dictionary"}),"\n",(0,s.jsxs)(n.ul,{children:["\n",(0,s.jsx)(n.li,{children:(0,s.jsx)(n.a,{href:"https://en.wikipedia.org/wiki/Functional_testing",children:"Functional tests"})}),"\n",(0,s.jsx)(n.li,{children:(0,s.jsx)(n.a,{href:"https://en.wikipedia.org/wiki/Smoke_testing_%28software%29",children:"Smoke test"})}),"\n",(0,s.jsx)(n.li,{children:(0,s.jsx)(n.a,{href:"https://en.wikipedia.org/wiki/Don%27t_repeat_yourself",children:"DRY"})}),"\n"]}),"\n",(0,s.jsx)(n.h2,{id:"submitting",children:"Submitting"}),"\n",(0,s.jsx)(n.p,{children:"In case you have any questions, feel free to reach out to me."}),"\n",(0,s.jsx)(n.hr,{})]})}function h(e={}){const{wrapper:n}={...(0,i.a)(),...e.components};return n?(0,s.jsx)(n,{...e,children:(0,s.jsx)(d,{...e})}):d(e)}},27420:(e,n,t)=>{t.d(n,{Z:()=>s});const s=t.p+"assets/images/tdd_lifecycle-327ad9ee0ed8318ed11e19a28e02b2cc.png"},11151:(e,n,t)=>{t.d(n,{Z:()=>a,a:()=>o});var s=t(67294);const i={},r=s.createContext(i);function o(e){const n=s.useContext(r);return s.useMemo((function(){return"function"==typeof e?e(n):{...n,...e}}),[n,e])}function a(e){let n;return n=e.disableParentContext?"function"==typeof e.components?e.components(i):e.components||i:o(e.components),s.createElement(r.Provider,{value:n},e.children)}}}]); 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\ No newline at end of file diff --git a/assets/js/2b89902a.cec021fa.js b/assets/js/2b89902a.cec021fa.js deleted file mode 100644 index 30747fa..0000000 --- a/assets/js/2b89902a.cec021fa.js +++ /dev/null @@ -1 +0,0 @@ -"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[6342],{45443:i=>{i.exports=JSON.parse('{"label":"recursion","permalink":"/algorithms/tags/recursion","allTagsPath":"/algorithms/tags","count":3,"items":[{"id":"recursion/pyramid-slide-down","title":"Introduction to dynamic programming","description":"Solving a problem in different ways.\\n","permalink":"/algorithms/recursion/pyramid-slide-down"},{"id":"recursion/karel-1","title":"Recursion and backtracking with Robot Karel","description":"A problem with too many restrictions.\\n","permalink":"/algorithms/recursion/karel-1"},{"id":"time-complexity/extend","title":"Time complexity of \u2039extend\u203a","description":"How to make inefficient algorithm unknowingly.\\n","permalink":"/algorithms/time-complexity/extend"}],"unlisted":false}')}}]); \ No newline at end of file diff --git a/assets/js/2ca64e35.e4c24d50.js b/assets/js/2ca64e35.e4c24d50.js new file mode 100644 index 0000000..0f50338 --- /dev/null +++ b/assets/js/2ca64e35.e4c24d50.js @@ -0,0 +1 @@ +"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[281],{99544:(e,n,t)=>{t.r(n),t.d(n,{assets:()=>a,contentTitle:()=>s,default:()=>h,frontMatter:()=>i,metadata:()=>l,toc:()=>d});var r=t(85893),o=t(11151);const i={id:"karel",slug:"/recursion/karel",title:"Recursion and backtracking with Robot Karel",description:"A problem with too many restrictions.\n",tags:["python","karel","recursion","backtracking"],last_update:{date:new Date("2022-11-29T00:00:00.000Z")}},s=void 0,l={id:"recursion/2022-11-29-karel/karel",title:"Recursion and backtracking with Robot Karel",description:"A problem with too many restrictions.\n",source:"@site/algorithms/04-recursion/2022-11-29-karel/index.md",sourceDirName:"04-recursion/2022-11-29-karel",slug:"/recursion/karel",permalink:"/algorithms/recursion/karel",draft:!1,unlisted:!1,editUrl:"https://github.com/mfocko/blog/tree/main/algorithms/04-recursion/2022-11-29-karel/index.md",tags:[{label:"python",permalink:"/algorithms/tags/python"},{label:"karel",permalink:"/algorithms/tags/karel"},{label:"recursion",permalink:"/algorithms/tags/recursion"},{label:"backtracking",permalink:"/algorithms/tags/backtracking"}],version:"current",lastUpdatedAt:166968e4,formattedLastUpdatedAt:"Nov 29, 2022",frontMatter:{id:"karel",slug:"/recursion/karel",title:"Recursion and backtracking with Robot Karel",description:"A problem with too many restrictions.\n",tags:["python","karel","recursion","backtracking"],last_update:{date:"2022-11-29T00:00:00.000Z"}},sidebar:"autogeneratedBar",previous:{title:"Recursion",permalink:"/algorithms/category/recursion"},next:{title:"Solution to the problem",permalink:"/algorithms/recursion/karel/solution"}},a={},d=[{value:"Introduction",id:"introduction",level:2},{value:"Your environment and problem description",id:"your-environment-and-problem-description",level:2},{value:"Environment",id:"environment",level:3},{value:"Interface",id:"interface",level:3},{value:"Problem",id:"problem",level:3},{value:"Simple problem to get familiar with the robot",id:"simple-problem-to-get-familiar-with-the-robot",level:2},{value:"Brainstorm the idea",id:"brainstorm-the-idea",level:2},{value:"\xbbRough\xab pseudocode",id:"rough-pseudocode",level:2},{value:"\xbbProper\xab pseudocode",id:"proper-pseudocode",level:2},{value:"Library",id:"library",level:2},{value:"Solution",id:"solution",level:2}];function c(e){const n={a:"a",admonition:"admonition",code:"code",em:"em",h2:"h2",h3:"h3",img:"img",li:"li",ol:"ol",p:"p",pre:"pre",strong:"strong",ul:"ul",...(0,o.a)(),...e.components};return(0,r.jsxs)(r.Fragment,{children:[(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsx)(n.li,{children:(0,r.jsx)(n.a,{href:"pathname:///files/algorithms/recursion/karel-1.tar.gz",children:"Sources"})}),"\n"]}),"\n",(0,r.jsx)(n.h2,{id:"introduction",children:"Introduction"}),"\n",(0,r.jsx)(n.p,{children:"In this exercise we will be working with a Robot Karel and with a \xbbvery\xab limited\nresources. The point of this exercise is to show how powerful recursion and\nbacktracking can be even without anything else at your hand."}),"\n",(0,r.jsx)(n.h2,{id:"your-environment-and-problem-description",children:"Your environment and problem description"}),"\n",(0,r.jsx)(n.h3,{id:"environment",children:"Environment"}),"\n",(0,r.jsx)(n.p,{children:"You are given a robot that is present in a maze and is looking for an exit. Maze\nconsists of different walls and exit is marked with a single so-called \u201cbeeper\u201d."}),"\n",(0,r.jsx)(n.p,{children:"Walking into a wall results in a permanent damage of the robot."}),"\n",(0,r.jsx)(n.h3,{id:"interface",children:"Interface"}),"\n",(0,r.jsx)(n.p,{children:"You can control the robot using the following interface:"}),"\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:["actions \u200b\xad\u2014 you can use them to change the current state of the robot and its\nsurroundings","\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:[(0,r.jsx)(n.code,{children:"robot.step()"})," \u2014 moves robot one step further"]}),"\n",(0,r.jsxs)(n.li,{children:[(0,r.jsx)(n.code,{children:"robot.turn_left()"})," \u2014 turns robot 90-degrees counter-clockwise","\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:["notice that you are not given ",(0,r.jsx)(n.code,{children:"turn_right"})," or ",(0,r.jsx)(n.code,{children:"turn_around"}),", but feel free\nto implement them yourself"]}),"\n"]}),"\n"]}),"\n",(0,r.jsxs)(n.li,{children:[(0,r.jsx)(n.code,{children:"robot.pick_beeper()"})," and opposite operation ",(0,r.jsx)(n.code,{children:"robot.put_beeper()"})," \u2014 that\nallows you to either pick or put \u201cbeeper\u201d from or onto the current position"]}),"\n"]}),"\n"]}),"\n",(0,r.jsxs)(n.li,{children:["queries \u2014 you can use them to check the current state of the robot and its\nsurroundings","\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:[(0,r.jsx)(n.code,{children:"robot.beepers_present()"})," \u2014 to check if there are any beepers at the robot's\ncurrent location"]}),"\n",(0,r.jsxs)(n.li,{children:[(0,r.jsx)(n.code,{children:"robot.left_is_clear()"})," \u2014 to check if you can step to the left","\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:["analogically for ",(0,r.jsx)(n.code,{children:"front"})," and ",(0,r.jsx)(n.code,{children:"right"})]}),"\n"]}),"\n"]}),"\n"]}),"\n"]}),"\n"]}),"\n",(0,r.jsxs)(n.admonition,{type:"caution",children:[(0,r.jsx)(n.p,{children:"Helper functions / procedures are allowed. Return values are allowed."}),(0,r.jsx)(n.p,{children:(0,r.jsx)(n.strong,{children:"Variables are prohibited!"})})]}),"\n",(0,r.jsx)(n.h3,{id:"problem",children:"Problem"}),"\n",(0,r.jsx)(n.p,{children:"Your task is to decide whether there is an exit from the maze or not. You can see\nan example of a maze here:"}),"\n",(0,r.jsx)(n.p,{children:(0,r.jsx)(n.img,{alt:"Image of the maze",src:t(19857).Z+"",width:"770",height:"839"})}),"\n",(0,r.jsx)(n.h2,{id:"simple-problem-to-get-familiar-with-the-robot",children:"Simple problem to get familiar with the robot"}),"\n",(0,r.jsx)(n.p,{children:"If you feel completely lost after the previous description, let me start you off\nwith a simpler problem."}),"\n",(0,r.jsx)(n.p,{children:"You are standing in front of the stairs, your task is to walk up the stairs."}),"\n",(0,r.jsx)(n.p,{children:"You can see an example of such map here:"}),"\n",(0,r.jsx)(n.p,{children:(0,r.jsx)(n.img,{alt:"Image of the stairs",src:t(68617).Z+"",width:"1058",height:"1161"})}),"\n",(0,r.jsx)(n.h2,{id:"brainstorm-the-idea",children:"Brainstorm the idea"}),"\n",(0,r.jsx)(n.p,{children:"As a first step write down any ideas and things that you have noticed or came to\nyour mind. Ideally:"}),"\n",(0,r.jsxs)(n.ol,{children:["\n",(0,r.jsx)(n.li,{children:"Write down a nested list of the problems"}),"\n",(0,r.jsx)(n.li,{children:"Write down list of problems that can happen"}),"\n",(0,r.jsxs)(n.li,{children:["Write down ",(0,r.jsx)(n.strong,{children:"anything"})," you consider important to solving the problem"]}),"\n"]}),"\n",(0,r.jsxs)(n.admonition,{title:"Example",type:"tip",children:[(0,r.jsxs)(n.p,{children:[(0,r.jsx)(n.strong,{children:"Problem"}),": I want to find out whether the display on smartphone should rotate."]}),(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:["nested list of problems","\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:["Check if display has been rotated","\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:["Read data from some sensor","\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsx)(n.li,{children:"From what sensor"}),"\n"]}),"\n"]}),"\n",(0,r.jsx)(n.li,{children:"In what format are the data I have read?"}),"\n",(0,r.jsx)(n.li,{children:"How do I communicate with the sensor?"}),"\n",(0,r.jsx)(n.li,{children:"What is the meaning of the data that I got?"}),"\n",(0,r.jsx)(n.li,{children:"How can I process it?"}),"\n"]}),"\n"]}),"\n"]}),"\n"]}),"\n",(0,r.jsxs)(n.li,{children:["any problems that can happen","\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsx)(n.li,{children:"What if the sensor doesn't work?"}),"\n",(0,r.jsx)(n.li,{children:"What if the data doesn't conform to the specification?"}),"\n",(0,r.jsx)(n.li,{children:"What if my formulas are wrong?"}),"\n"]}),"\n"]}),"\n",(0,r.jsxs)(n.li,{children:["anything important","\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsx)(n.li,{children:"I could probably use gyroscope."}),"\n",(0,r.jsx)(n.li,{children:"I should probably look up the datasheet for that module."}),"\n",(0,r.jsx)(n.li,{children:"I could write some tests to verify that my computations are correct."}),"\n"]}),"\n"]}),"\n"]})]}),"\n",(0,r.jsx)(n.h2,{id:"rough-pseudocode",children:"\xbbRough\xab pseudocode"}),"\n",(0,r.jsxs)(n.p,{children:["As a next step write a ",(0,r.jsx)(n.strong,{children:"mock up"})," of a pseudocode solving the problem, you are\nallowed to use comments as placeholders for bigger chunks of code."]}),"\n",(0,r.jsx)(n.p,{children:"Those comments are also a very good hints for decomposition and short, but\ndescriptive, commnets (if they are short enough and you decide not to factor them\nout to separate functions)."}),"\n",(0,r.jsx)(n.admonition,{type:"tip",children:(0,r.jsx)(n.p,{children:"The smaller the function is, the easier it is to test it and argue about its\ncorrectness."})}),"\n",(0,r.jsx)(n.h2,{id:"proper-pseudocode",children:"\xbbProper\xab pseudocode"}),"\n",(0,r.jsxs)(n.p,{children:["If you are satisfied with the ",(0,r.jsx)(n.em,{children:"\xbbrough\xab pseudocode"}),", it's time to convert it into\na proper one. Get rid of the uncertain pieces of functionality and replace them\nwith proper pseudocode, i.e. list of the things that should happen in its place."]}),"\n",(0,r.jsx)(n.h2,{id:"library",children:"Library"}),"\n",(0,r.jsxs)(n.p,{children:["If you got here, and you ",(0,r.jsx)(n.strong,{children:"actually"})," wrote down the pseudocode, you can try your\nsolution after downloading the sources linked at the beginning. If you download\nthe ZIP-file, you can there:"]}),"\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:["\n",(0,r.jsxs)(n.p,{children:[(0,r.jsx)(n.code,{children:"generate_mazes.py"})," - that was used to generate the same maze with beepers in\ndifferent locations"]}),"\n"]}),"\n",(0,r.jsxs)(n.li,{children:["\n",(0,r.jsxs)(n.p,{children:[(0,r.jsx)(n.code,{children:"karel_tk.py"})," - library which can run Karel given the his world"]}),"\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:["documentation can be found ",(0,r.jsx)(n.a,{href:"https://www.fi.muni.cz/~xfocko/ib111/10/docs/",children:"here"})]}),"\n",(0,r.jsx)(n.li,{children:"also requires Tk Python library to be installed (it should be included in\nmajority of Python installations)"}),"\n"]}),"\n"]}),"\n",(0,r.jsxs)(n.li,{children:["\n",(0,r.jsxs)(n.p,{children:[(0,r.jsx)(n.code,{children:"*.kw"})," - which represent multiple worlds for Karel I have prepared"]}),"\n"]}),"\n",(0,r.jsxs)(n.li,{children:["\n",(0,r.jsxs)(n.p,{children:[(0,r.jsx)(n.code,{children:"skeleton.py"})," - skeleton for your solution, needs to be put in the same directory\nas ",(0,r.jsx)(n.code,{children:"karel_tk.py"})," and takes path to the world as a first argument, example usage:"]}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{children:"$ python3 skeleton.py stairs.kw\n"})}),"\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsx)(n.li,{children:"of course, this file can be renamed ;)"}),"\n"]}),"\n"]}),"\n"]}),"\n",(0,r.jsx)(n.h2,{id:"solution",children:"Solution"}),"\n",(0,r.jsx)(n.p,{children:"Solution to this problem will be released as a second part, so that you can try\nit out by yourself without any influence of \u201cexample solution\u201d."}),"\n",(0,r.jsx)(n.p,{children:"If you want to get any feedback, feel free to mail me your solution (including\nall the steps that lead to your final solution, if you wish to get feedback on\nthose too)."})]})}function h(e={}){const{wrapper:n}={...(0,o.a)(),...e.components};return n?(0,r.jsx)(n,{...e,children:(0,r.jsx)(c,{...e})}):c(e)}},19857:(e,n,t)=>{t.d(n,{Z:()=>r});const r=t.p+"assets/images/maze-a374d908bc9445061e15faeddc71641e.png"},68617:(e,n,t)=>{t.d(n,{Z:()=>r});const r=t.p+"assets/images/stairs-5ee5d03905645aeb13eeaa7774451a64.png"},11151:(e,n,t)=>{t.d(n,{Z:()=>l,a:()=>s});var r=t(67294);const o={},i=r.createContext(o);function s(e){const n=r.useContext(i);return r.useMemo((function(){return"function"==typeof e?e(n):{...n,...e}}),[n,e])}function l(e){let n;return n=e.disableParentContext?"function"==typeof e.components?e.components(o):e.components||o:s(e.components),r.createElement(i.Provider,{value:n},e.children)}}}]); \ No newline at end of file diff --git a/assets/js/30814625.1cb0ad07.js b/assets/js/30814625.1cb0ad07.js new file mode 100644 index 0000000..de8c91c --- /dev/null +++ b/assets/js/30814625.1cb0ad07.js @@ -0,0 +1 @@ +"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[115],{78416:(e,n,t)=>{t.r(n),t.d(n,{assets:()=>a,contentTitle:()=>o,default:()=>c,frontMatter:()=>i,metadata:()=>l,toc:()=>d});var r=t(85893),s=t(11151);const i={id:"solution",slug:"/recursion/karel/solution",title:"Solution to the problem",description:"Solving the problem introduced in the previous post.\n",tags:["python","karel","recursion","backtracking","solution"],last_update:{date:new Date("2023-12-24T00:00:00.000Z")}},o="Solving the maze problem",l={id:"recursion/2022-11-29-karel/solution",title:"Solution to the problem",description:"Solving the problem introduced in the previous post.\n",source:"@site/algorithms/04-recursion/2022-11-29-karel/2023-12-24-solution.md",sourceDirName:"04-recursion/2022-11-29-karel",slug:"/recursion/karel/solution",permalink:"/algorithms/recursion/karel/solution",draft:!1,unlisted:!1,editUrl:"https://github.com/mfocko/blog/tree/main/algorithms/04-recursion/2022-11-29-karel/2023-12-24-solution.md",tags:[{label:"python",permalink:"/algorithms/tags/python"},{label:"karel",permalink:"/algorithms/tags/karel"},{label:"recursion",permalink:"/algorithms/tags/recursion"},{label:"backtracking",permalink:"/algorithms/tags/backtracking"},{label:"solution",permalink:"/algorithms/tags/solution"}],version:"current",lastUpdatedAt:1703376e3,formattedLastUpdatedAt:"Dec 24, 2023",frontMatter:{id:"solution",slug:"/recursion/karel/solution",title:"Solution to the problem",description:"Solving the problem introduced in the previous post.\n",tags:["python","karel","recursion","backtracking","solution"],last_update:{date:"2023-12-24T00:00:00.000Z"}},sidebar:"autogeneratedBar",previous:{title:"Recursion and backtracking with Robot Karel",permalink:"/algorithms/recursion/karel"},next:{title:"Introduction to dynamic programming",permalink:"/algorithms/recursion/pyramid-slide-down"}},a={},d=[{value:"Summary of the problem",id:"summary-of-the-problem",level:2},{value:"Brainstorming the idea",id:"brainstorming-the-idea",level:2},{value:"\xbbRough\xab pseudocode",id:"rough-pseudocode",level:2},{value:"\xbbProper\xab pseudocode",id:"proper-pseudocode",level:2},{value:"Actual implementation",id:"actual-implementation",level:2},{value:"Testing",id:"testing",level:2},{value:"Fixing the issue",id:"fixing-the-issue",level:2}];function u(e){const n={a:"a",admonition:"admonition",code:"code",em:"em",h1:"h1",h2:"h2",li:"li",ol:"ol",p:"p",pre:"pre",section:"section",strong:"strong",sup:"sup",ul:"ul",...(0,s.a)(),...e.components};return(0,r.jsxs)(r.Fragment,{children:[(0,r.jsx)(n.h1,{id:"solving-the-maze-problem",children:"Solving the maze problem"}),"\n",(0,r.jsx)(n.p,{children:"We will go through the given problem the same way as I have suggested in the\nprevious post."}),"\n",(0,r.jsx)(n.h2,{id:"summary-of-the-problem",children:"Summary of the problem"}),"\n",(0,r.jsxs)(n.p,{children:["We have a robot in some kind of a maze and we have to find our way out that is\nmarked with a so-called \u201cbeeper\u201d. We've been given a restriction ",(0,r.jsx)(n.strong,{children:"not to"})," use\nany variables, we can use just backtracking and recursion."]}),"\n",(0,r.jsx)(n.h2,{id:"brainstorming-the-idea",children:"Brainstorming the idea"}),"\n",(0,r.jsx)(n.p,{children:"Let's start with some brainstorming of the solution."}),"\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:["How will I know what I've checked without any variables?","\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:[(0,r.jsx)(n.em,{children:"answer"}),": recursion will need to take care of that, cause I'm not allowed\nanything else"]}),"\n"]}),"\n"]}),"\n",(0,r.jsxs)(n.li,{children:["How will I pass around the fact I've found the exit?","\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:[(0,r.jsx)(n.em,{children:"answer"}),": I can return values from helper functions, so I should be able to\nindicate ",(0,r.jsx)(n.em,{children:"found"}),"/",(0,r.jsx)(n.em,{children:"not found"})]}),"\n"]}),"\n"]}),"\n",(0,r.jsxs)(n.li,{children:["How is the exit marked?","\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:[(0,r.jsx)(n.em,{children:"answer"}),": there is one \u201cbeeper\u201d as a mark"]}),"\n"]}),"\n"]}),"\n",(0,r.jsxs)(n.li,{children:["Can I reduce my problem somehow?","\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsxs)(n.li,{children:[(0,r.jsx)(n.em,{children:"answer"}),": I could check each possible direction as a reduced search space"]}),"\n"]}),"\n"]}),"\n"]}),"\n",(0,r.jsx)(n.h2,{id:"rough-pseudocode",children:"\xbbRough\xab pseudocode"}),"\n",(0,r.jsxs)(n.p,{children:["We should be able to construct a ",(0,r.jsx)(n.em,{children:"skeleton"})," of our solution at least. Pseudocode\nfollows:"]}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{className:"language-ruby",children:"def find_exit\n if found the exit then\n signal others\n terminate\n end\n\n check left\n check front\n check right\nend\n"})}),"\n",(0,r.jsx)(n.p,{children:"As you can see, we only mention what we want to do very roughly, technical\ndetails are left out, except for the early return (which is the base of our\nrecursive function)."}),"\n",(0,r.jsx)(n.h2,{id:"proper-pseudocode",children:"\xbbProper\xab pseudocode"}),"\n",(0,r.jsx)(n.p,{children:"In the proper pseudocode we will need to dive into the technical details like\nthe way we check for exit, move around, etc."}),"\n",(0,r.jsx)(n.p,{children:"We can start by cleaning up and decomposing the function written above:"}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{className:"language-ruby",children:"def find_exit\n # BASE: found exit\n if found_exit() then\n return true\n end\n\n # check left\n if left_is_clear() then\n turn_left()\n step()\n if find_exit() then\n return true\n end\n\n turn_around()\n step()\n turn_left()\n end\n\n # check front\n if front_is_clear() then\n step()\n if find_exit() then\n return true\n end\n\n turn_around()\n step()\n turn_around()\n end\n\n # check right\n if right_is_clear() then\n turn_right()\n step()\n if find_exit() then\n return true\n end\n\n turn_around()\n step()\n turn_right()\n end\n\n return false\nend\n"})}),"\n",(0,r.jsx)(n.p,{children:"We are missing few of the functions that we use in our pseudocode above:"}),"\n",(0,r.jsxs)(n.ul,{children:["\n",(0,r.jsx)(n.li,{children:(0,r.jsx)(n.code,{children:"found_exit()"})}),"\n",(0,r.jsx)(n.li,{children:(0,r.jsx)(n.code,{children:"turn_around()"})}),"\n",(0,r.jsx)(n.li,{children:(0,r.jsx)(n.code,{children:"turn_right()"})}),"\n"]}),"\n",(0,r.jsx)(n.p,{children:"We can implement those easily:"}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{className:"language-ruby",children:"def found_exit\n if not beepers_present() then\n return false\n end\n\n pick_beeper()\n if beepers_present() then\n put_beeper()\n return false\n end\n\n put_beeper()\n return true\nend\n\ndef turn_around\n turn_left()\n turn_left()\nend\n\ndef turn_right\n turn_around()\n turn_left()\nend\n"})}),"\n",(0,r.jsx)(n.p,{children:"Now we have everything ready for implementing it in Python."}),"\n",(0,r.jsx)(n.h2,{id:"actual-implementation",children:"Actual implementation"}),"\n",(0,r.jsxs)(n.p,{children:["It's just a matter of rewriting the pseudocode into Python",(0,r.jsx)(n.sup,{children:(0,r.jsx)(n.a,{href:"#user-content-fn-1",id:"user-content-fnref-1","data-footnote-ref":!0,"aria-describedby":"footnote-label",children:"1"})}),":"]}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{className:"language-py",children:"class SuperKarel(Karel):\n # you can define your own helper functions on Karel here, if you wish to\n\n def found_exit(self) -> bool:\n if not self.beepers_present():\n return False\n\n self.pick_beeper()\n if self.beepers_present():\n self.put_beeper()\n return False\n\n self.put_beeper()\n return True\n\n def turn_around(self):\n for _ in range(2):\n self.turn_left()\n\n def turn_right(self):\n for _ in range(3):\n self.turn_left()\n\n def find_exit(self) -> bool:\n if self.found_exit():\n return True\n\n # check left\n if self.left_is_clear():\n self.turn_left()\n self.step()\n if self.find_exit():\n return True\n\n self.turn_around()\n self.step()\n self.turn_left()\n\n # check front\n if self.front_is_clear():\n self.step()\n if self.find_exit():\n return True\n\n self.turn_around()\n self.step()\n self.turn_around()\n\n # check right\n if self.right_is_clear():\n self.turn_right()\n self.step()\n if self.find_exit():\n return True\n\n self.turn_around()\n self.step()\n self.turn_right()\n\n return False\n\n def run(self):\n self.find_exit()\n"})}),"\n",(0,r.jsx)(n.p,{children:"We have relatively repetitive code for checking each of the directions, I would\npropose to refactor a bit, in a fashion of checkin just forward, so it's more\nreadable:"}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{className:"language-py",children:"def find_exit(self) -> bool:\n if self.found_exit():\n return True\n\n self.turn_left()\n for _ in range(3):\n if self.front_is_blocked():\n self.turn_right()\n continue\n\n self.step()\n if self.find_exit():\n return True\n\n self.step()\n self.turn_around()\n self.turn_right()\n\n return False\n"})}),"\n",(0,r.jsxs)(n.p,{children:["We can also notice that turning around takes 2 left turns and turning to right\ndoes 3. We get 5 left turns in total when we turn around and right afterwards\u2026\nTaking 4 left turns just rotates us back to our initial direction, therefore it\nis sufficient to do just one left turn (",(0,r.jsx)(n.code,{children:"5 % 4 == 1"}),"). That way we get:"]}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{className:"language-py",children:"def find_exit(self) -> bool:\n if self.found_exit():\n return True\n\n self.turn_left()\n for _ in range(3):\n if self.front_is_blocked():\n self.turn_right()\n continue\n\n self.step()\n if self.find_exit():\n return True\n\n self.step()\n # turning around and right is same as one turn to the left\n self.turn_left()\n\n return False\n"})}),"\n",(0,r.jsx)(n.h2,{id:"testing",children:"Testing"}),"\n",(0,r.jsx)(n.p,{children:"In the skeleton, with the previous post, I have included multiple mazes that can\nbe tested. I have tried this solution with all of the given mazes, and it was\nsuccessful in finding the exit. However there is one precondition of our\nsolution that we haven't spoken about."}),"\n",(0,r.jsxs)(n.p,{children:["We are silently expecting the maze ",(0,r.jsx)(n.strong,{children:"not to"})," have any loops. Example of such\nmaze can be the ",(0,r.jsx)(n.code,{children:"maze666.kw"}),":"]}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{children:"\u250c\u2500\u2500\u2500\u2500\u2500\u2500\u2500\u2500\u2500\u252c\u2500\u2510\n\u2502. . . . .\u2502.\u2502\n\u2502 \u250c\u2500\u2500\u2500\u2500\u2500\u2510 \u2502 \u2502\n\u2502.\u2502. . .\u2502.\u2502.\u2502\n\u2502 \u2502 \u2502 \u2502 \u2502 \u2502\n\u2502.\u2502.\u2502. . .\u2502.\u2502\n\u2502 \u2502 \u2502 \u2514\u2500\u2524\n\u2502.\u2502.\u2502. . . 1\u2502\n\u2502 \u2502 \u2502 \u2502 \u250c\u2500\u2524\n\u2502.\u2502. . .\u2502.\u2502.\u2502\n\u2502 \u2514\u2500\u2500\u2500\u2500\u2500\u2518 \u2502 \u2502\n\u2502. > . . .\u2502.\u2502\n\u2514\u2500\u2500\u2500\u2500\u2500\u2500\u2500\u2500\u2500\u2534\u2500\u2518\n"})}),"\n",(0,r.jsx)(n.p,{children:"If you try running our solution on this map, Karel just loops and never finds\nthe solution. Let's have a look at the loop he gets stuck in:"}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{children:"\u250c\u2500\u2500\u2500\u2500\u2500\u2500\u2500\u2500\u2500\u252c\u2500\u2510\n\u2502* * * * *\u2502.\u2502\n\u2502 \u250c\u2500\u2500\u2500\u2500\u2500\u2510 \u2502 \u2502\n\u2502*\u2502* * *\u2502*\u2502.\u2502\n\u2502 \u2502 \u2502 \u2502 \u2502 \u2502\n\u2502*\u2502*\u2502. * *\u2502.\u2502\n\u2502 \u2502 \u2502 \u2514\u2500\u2524\n\u2502*\u2502*\u2502. * * 1\u2502\n\u2502 \u2502 \u2502 \u2502 \u250c\u2500\u2524\n\u2502*\u2502* * *\u2502*\u2502.\u2502\n\u2502 \u2514\u2500\u2500\u2500\u2500\u2500\u2518 \u2502 \u2502\n\u2502* * * * *\u2502.\u2502\n\u2514\u2500\u2500\u2500\u2500\u2500\u2500\u2500\u2500\u2500\u2534\u2500\u2518\n"})}),"\n",(0,r.jsx)(n.p,{children:"He walks past the exit, but can't see it, cause there's always a feasible path\nthat is worth trying."}),"\n",(0,r.jsx)(n.admonition,{title:"Algorithm",type:"tip",children:(0,r.jsx)(n.p,{children:"The algorithm we have written to find the exit is a depth-first search (DFS).\nHowever, as opposed to the usual implementation, we have no notion of paths that\nare being (or have already been) explored."})}),"\n",(0,r.jsx)(n.h2,{id:"fixing-the-issue",children:"Fixing the issue"}),"\n",(0,r.jsxs)(n.p,{children:["Since we are not allowed to use variables, the only way to resolve this issue is\nto mark the \u201ccells\u201d that we have tried. We can easily use beepers for this, but\nwe need to be careful ",(0,r.jsx)(n.strong,{children:"not to"})," confuse the exit with already visited cell."]}),"\n",(0,r.jsxs)(n.p,{children:["To do that we'll use ",(0,r.jsx)(n.strong,{children:"2"})," beepers instead of the one. Implementation follows:"]}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{className:"language-py",children:'def visited(self) -> bool:\n if not self.beepers_present():\n return False\n\n self.pick_beeper()\n if not self.beepers_present():\n self.put_beeper()\n return False\n\n self.pick_beeper()\n if self.beepers_present():\n assert False, "no cell shall be marked with 3 beepers"\n\n self.put_beeper()\n self.put_beeper()\n return True\n\n\ndef find_exit(self) -> bool:\n # BASE: already tried\n if self.visited():\n self.turn_around()\n return False\n\n # BASE\n if self.found_exit():\n return True\n\n # mark the cell as visited\n for _ in range(2):\n self.put_beeper()\n\n self.turn_left()\n for _ in range(3):\n if self.front_is_blocked():\n self.turn_right()\n continue\n\n self.step()\n if self.find_exit():\n return True\n\n self.step()\n # turning around and right is same as one turn to the left\n self.turn_left()\n\n return False\n'})}),"\n",(0,r.jsx)(n.p,{children:"Now our solution works also for mazes that have loops."}),"\n",(0,r.jsxs)(n.section,{"data-footnotes":!0,className:"footnotes",children:[(0,r.jsx)(n.h2,{className:"sr-only",id:"footnote-label",children:"Footnotes"}),"\n",(0,r.jsxs)(n.ol,{children:["\n",(0,r.jsxs)(n.li,{id:"user-content-fn-1",children:["\n",(0,r.jsxs)(n.p,{children:["which is usually very easy matter ",(0,r.jsx)(n.a,{href:"#user-content-fnref-1","data-footnote-backref":"","aria-label":"Back to reference 1",className:"data-footnote-backref",children:"\u21a9"})]}),"\n"]}),"\n"]}),"\n"]})]})}function c(e={}){const{wrapper:n}={...(0,s.a)(),...e.components};return n?(0,r.jsx)(n,{...e,children:(0,r.jsx)(u,{...e})}):u(e)}},11151:(e,n,t)=>{t.d(n,{Z:()=>l,a:()=>o});var r=t(67294);const s={},i=r.createContext(s);function o(e){const n=r.useContext(i);return r.useMemo((function(){return"function"==typeof e?e(n):{...n,...e}}),[n,e])}function l(e){let n;return n=e.disableParentContext?"function"==typeof e.components?e.components(s):e.components||s:o(e.components),r.createElement(i.Provider,{value:n},e.children)}}}]); \ No newline at end of file diff --git a/assets/js/595c7293.a068725e.js b/assets/js/595c7293.b6dbfa38.js similarity index 98% rename from assets/js/595c7293.a068725e.js rename to assets/js/595c7293.b6dbfa38.js index d246898..cc5e475 100644 --- a/assets/js/595c7293.a068725e.js +++ b/assets/js/595c7293.b6dbfa38.js @@ -1 +1 @@ -"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[5634],{58396:(e,n,t)=>{t.r(n),t.d(n,{assets:()=>a,contentTitle:()=>o,default:()=>h,frontMatter:()=>r,metadata:()=>c,toc:()=>l});var i=t(85893),s=t(11151);const r={id:"seminar-08",title:"8th seminar",description:"Manipulating with files only char-by-char and a magic tree.\n"},o="8th seminar bonus assignment",c={id:"bonuses/seminar-08",title:"8th seminar",description:"Manipulating with files only char-by-char and a magic tree.\n",source:"@site/c/bonuses/08.md",sourceDirName:"bonuses",slug:"/bonuses/seminar-08",permalink:"/c/bonuses/seminar-08",draft:!1,unlisted:!1,editUrl:"https://github.com/mfocko/blog/tree/main/c/bonuses/08.md",tags:[],version:"current",lastUpdatedAt:1701271124,formattedLastUpdatedAt:"Nov 29, 2023",frontMatter:{id:"seminar-08",title:"8th seminar",description:"Manipulating with files only char-by-char and a magic tree.\n"},sidebar:"autogeneratedBar",previous:{title:"5th and 6th seminar",permalink:"/c/bonuses/seminar-05-06"},next:{title:"10th seminar",permalink:"/c/bonuses/seminar-10"}},a={},l=[{value:"Introduction",id:"introduction",level:2},{value:"Warning",id:"warning",level:2},{value:"Testing",id:"testing",level:2},{value:"Task no. 1: Counting (0.75 K\u20a1)",id:"task-no-1-counting-075-k",level:2},{value:"Requirements",id:"requirements",level:3},{value:"Bonus part (0.75 K\u20a1)",id:"bonus-part-075-k",level:3},{value:"Task no. 2: Weird trees (1 K\u20a1)",id:"task-no-2-weird-trees-1-k",level:2},{value:"Submitting",id:"submitting",level:2}];function d(e){const n={a:"a",blockquote:"blockquote",code:"code",em:"em",h1:"h1",h2:"h2",h3:"h3",hr:"hr",img:"img",li:"li",ol:"ol",p:"p",pre:"pre",strong:"strong",ul:"ul",...(0,s.a)(),...e.components};return(0,i.jsxs)(i.Fragment,{children:[(0,i.jsx)(n.h1,{id:"8th-seminar-bonus-assignment",children:"8th seminar bonus assignment"}),"\n",(0,i.jsx)(n.p,{children:(0,i.jsx)(n.a,{href:"pathname:///files/c/bonuses/08.tar.gz",children:"Source"})}),"\n",(0,i.jsx)(n.h2,{id:"introduction",children:"Introduction"}),"\n",(0,i.jsx)(n.p,{children:"In this bonus you can implement two tasks, one of them has a bonus part with generic\nsolution."}),"\n",(0,i.jsx)(n.p,{children:"One is focused on counting ananas or in case of generic version any substring in\nthe file, but with a restriction on the function you use."}),"\n",(0,i.jsx)(n.p,{children:"Other one has a more algorithmic spirit."}),"\n",(0,i.jsx)(n.p,{children:"For this bonus you can get at maximum 2.5 K\u20a1."}),"\n",(0,i.jsx)(n.h2,{id:"warning",children:"Warning"}),"\n",(0,i.jsxs)(n.p,{children:[(0,i.jsx)(n.strong,{children:"DO NOT COMMIT test data"})," to your own git repository, since the tests include\nfiles that exceed 10MB by themselves. Even if they are on separate branch, they\ntake up the space."]}),"\n",(0,i.jsx)(n.h2,{id:"testing",children:"Testing"}),"\n",(0,i.jsxs)(n.p,{children:["For testing you are provided with python script (requires ",(0,i.jsx)(n.code,{children:"click"})," to be installed:\n",(0,i.jsx)(n.code,{children:"pip3 install --user click"}),") and ",(0,i.jsx)(n.code,{children:"Makefile"})," that provides following targets:"]}),"\n",(0,i.jsxs)(n.ul,{children:["\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:"check-counting"})," - runs the ",(0,i.jsx)(n.code,{children:"counting"})," tests"]}),"\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:"check-counting-bonus"})," - runs the ",(0,i.jsx)(n.code,{children:"counting"})," tests with bonus implemented"]}),"\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:"check"})," - runs both ",(0,i.jsx)(n.code,{children:"counting"})," and ",(0,i.jsx)(n.code,{children:"counting-bonus"})," tests"]}),"\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:"clean"})," - removes output files from the test runs"]}),"\n"]}),"\n",(0,i.jsx)(n.h2,{id:"task-no-1-counting-075-k",children:"Task no. 1: Counting (0.75 K\u20a1)"}),"\n",(0,i.jsx)(n.p,{children:"Your first task is to make smallish program that counts occurences of specific\n(or given) word from file and writes the number to other file."}),"\n",(0,i.jsx)(n.p,{children:"Usage of the program is:"}),"\n",(0,i.jsx)(n.pre,{children:(0,i.jsx)(n.code,{children:"Usage: ./counting [string-to-be-counted]\n"})}),"\n",(0,i.jsx)(n.p,{children:"Arguments that are passed to the program represent:"}),"\n",(0,i.jsxs)(n.ul,{children:["\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:""})," - path to the file where we count the words"]}),"\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:""})," - path to the file where we output the count"]}),"\n",(0,i.jsxs)(n.li,{children:["(optional argument) ",(0,i.jsx)(n.code,{children:"[string-to-be-counted]"})," - in case you implement bonus,\notherwise we default to word ",(0,i.jsx)(n.code,{children:"ananas"})," ;)"]}),"\n"]}),"\n",(0,i.jsx)(n.p,{children:"In skeleton you are given 3 empty, but documented, functions to implement."}),"\n",(0,i.jsxs)(n.ol,{children:["\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:"count_anything"})," - function accepts input file and substring to be counted in\nthe file, returns the count."]}),"\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:"count_ananas"})," - same as ",(0,i.jsx)(n.code,{children:"count_anything"}),", but specialized for ananases, the\ndefault implementation from the skeleton expects you to implement ",(0,i.jsx)(n.code,{children:"count_anything"}),"\nand therefore it just calls the other function."]}),"\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:"write_number"})," - function that writes the number to the file, why would you\nneed the function is explained later :)"]}),"\n"]}),"\n",(0,i.jsx)(n.h3,{id:"requirements",children:"Requirements"}),"\n",(0,i.jsxs)(n.p,{children:["For manipulation with the files you are only allowed to use ",(0,i.jsx)(n.code,{children:"fopen"}),", ",(0,i.jsx)(n.code,{children:"fclose"}),",\n",(0,i.jsx)(n.code,{children:"fgetc"})," and ",(0,i.jsx)(n.code,{children:"fputc"}),". Functions like ",(0,i.jsx)(n.code,{children:"fprintf"})," (except for ",(0,i.jsx)(n.code,{children:"stderr"})," or logging) and\n",(0,i.jsx)(n.code,{children:"fscanf"})," are ",(0,i.jsx)(n.strong,{children:"forbidden"}),"."]}),"\n",(0,i.jsx)(n.p,{children:"In case you struggle and want to use one of those functions, the solution will be\npenalized by 50% of points."}),"\n",(0,i.jsx)(n.h3,{id:"bonus-part-075-k",children:"Bonus part (0.75 K\u20a1)"}),"\n",(0,i.jsxs)(n.p,{children:["Bonus part of this assignment is to implement ",(0,i.jsx)(n.code,{children:"count_anything"})," rather than ",(0,i.jsx)(n.code,{children:"count_ananas"}),"."]}),"\n",(0,i.jsxs)(n.blockquote,{children:["\n",(0,i.jsx)(n.p,{children:"Smaller hint: This task does not need dynamic allocation :) You just need one\ngood helper function and the right idea ;)"}),"\n"]}),"\n",(0,i.jsx)(n.h2,{id:"task-no-2-weird-trees-1-k",children:"Task no. 2: Weird trees (1 K\u20a1)"}),"\n",(0,i.jsxs)(n.p,{children:["In this task we are crossing our paths with ",(0,i.jsx)(n.em,{children:"algorithms and data structures"}),".\nYour task is to write a program that constructs tree from the file that is given\nas an argument and pretty-prints it."]}),"\n",(0,i.jsxs)(n.p,{children:["Input file consists of lines, that include ",(0,i.jsx)(n.code,{children:"key"})," and ",(0,i.jsx)(n.code,{children:"rank"})," in form ",(0,i.jsx)(n.code,{children:"key;rank"}),"\nor ",(0,i.jsx)(n.code,{children:"nil"}),". Why would we have ",(0,i.jsx)(n.code,{children:"nil"})," in a file? The file represents pre-order iteration\nthrough the tree. Leaves never have rank different than 0, so you can safely assume\n2 non-existing ",(0,i.jsx)(n.code,{children:"nil"}),"s in the input after you read such node ;)"]}),"\n",(0,i.jsxs)("table",{children:[(0,i.jsxs)("tr",{children:[(0,i.jsx)("th",{children:"Example input file"}),(0,i.jsx)("th",{children:"Tree it represents"})]}),(0,i.jsxs)("tr",{children:[(0,i.jsx)("td",{children:(0,i.jsx)(n.pre,{children:(0,i.jsx)(n.code,{children:"8;4\n5;3\n3;2\n2;1\n1;0\nnil\n4;0\n7;1\n6;0\nnil\n11;2\n10;1\n9;0\nnil\n12;0\n"})})}),(0,i.jsx)("td",{children:(0,i.jsx)(n.p,{children:(0,i.jsx)(n.img,{alt:"tree",src:t(30073).Z+"",width:"633",height:"684"})})})]})]}),"\n",(0,i.jsxs)(n.p,{children:["In this task you are only provided with different trees in the ",(0,i.jsx)(n.code,{children:"test-trees"})," directory.\nImplementation and format of the pretty-print is totally up to you. :)"]}),"\n",(0,i.jsx)(n.p,{children:"Example of mine for the tree above:"}),"\n",(0,i.jsx)(n.pre,{children:(0,i.jsx)(n.code,{children:"8 (rank = 4)\n+-- 5 (rank = 3)\n| +-- 3 (rank = 2)\n| | +-- 2 (rank = 1)\n| | | +-- 1 (rank = 0)\n| | +-- 4 (rank = 0)\n| +-- 7 (rank = 1)\n| +-- 6 (rank = 0)\n+-- 11 (rank = 2)\n +-- 10 (rank = 1)\n | +-- 9 (rank = 0)\n +-- 12 (rank = 0)\n"})}),"\n",(0,i.jsxs)(n.blockquote,{children:["\n",(0,i.jsx)(n.p,{children:"Can you find out what are those trees? :)"}),"\n"]}),"\n",(0,i.jsx)(n.h2,{id:"submitting",children:"Submitting"}),"\n",(0,i.jsx)(n.p,{children:"In case you have any questions, feel free to reach out to me."}),"\n",(0,i.jsx)(n.hr,{})]})}function h(e={}){const{wrapper:n}={...(0,s.a)(),...e.components};return n?(0,i.jsx)(n,{...e,children:(0,i.jsx)(d,{...e})}):d(e)}},30073:(e,n,t)=>{t.d(n,{Z:()=>i});const i=t.p+"assets/images/tree-c9e37f87f9095c00fad33ea034485ce6.png"},11151:(e,n,t)=>{t.d(n,{Z:()=>c,a:()=>o});var i=t(67294);const s={},r=i.createContext(s);function o(e){const n=i.useContext(r);return i.useMemo((function(){return"function"==typeof e?e(n):{...n,...e}}),[n,e])}function c(e){let n;return n=e.disableParentContext?"function"==typeof e.components?e.components(s):e.components||s:o(e.components),i.createElement(r.Provider,{value:n},e.children)}}}]); \ No newline at end of file +"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[5634],{58396:(e,n,t)=>{t.r(n),t.d(n,{assets:()=>a,contentTitle:()=>o,default:()=>h,frontMatter:()=>r,metadata:()=>c,toc:()=>l});var i=t(85893),s=t(11151);const r={id:"seminar-08",title:"8th seminar",description:"Manipulating with files only char-by-char and a magic tree.\n"},o="8th seminar bonus assignment",c={id:"bonuses/seminar-08",title:"8th seminar",description:"Manipulating with files only char-by-char and a magic tree.\n",source:"@site/c/bonuses/08.md",sourceDirName:"bonuses",slug:"/bonuses/seminar-08",permalink:"/c/bonuses/seminar-08",draft:!1,unlisted:!1,editUrl:"https://github.com/mfocko/blog/tree/main/c/bonuses/08.md",tags:[],version:"current",lastUpdatedAt:1703373170,formattedLastUpdatedAt:"Dec 23, 2023",frontMatter:{id:"seminar-08",title:"8th seminar",description:"Manipulating with files only char-by-char and a magic tree.\n"},sidebar:"autogeneratedBar",previous:{title:"5th and 6th seminar",permalink:"/c/bonuses/seminar-05-06"},next:{title:"10th seminar",permalink:"/c/bonuses/seminar-10"}},a={},l=[{value:"Introduction",id:"introduction",level:2},{value:"Warning",id:"warning",level:2},{value:"Testing",id:"testing",level:2},{value:"Task no. 1: Counting (0.75 K\u20a1)",id:"task-no-1-counting-075-k",level:2},{value:"Requirements",id:"requirements",level:3},{value:"Bonus part (0.75 K\u20a1)",id:"bonus-part-075-k",level:3},{value:"Task no. 2: Weird trees (1 K\u20a1)",id:"task-no-2-weird-trees-1-k",level:2},{value:"Submitting",id:"submitting",level:2}];function d(e){const n={a:"a",blockquote:"blockquote",code:"code",em:"em",h1:"h1",h2:"h2",h3:"h3",hr:"hr",img:"img",li:"li",ol:"ol",p:"p",pre:"pre",strong:"strong",ul:"ul",...(0,s.a)(),...e.components};return(0,i.jsxs)(i.Fragment,{children:[(0,i.jsx)(n.h1,{id:"8th-seminar-bonus-assignment",children:"8th seminar bonus assignment"}),"\n",(0,i.jsx)(n.p,{children:(0,i.jsx)(n.a,{href:"pathname:///files/c/bonuses/08.tar.gz",children:"Source"})}),"\n",(0,i.jsx)(n.h2,{id:"introduction",children:"Introduction"}),"\n",(0,i.jsx)(n.p,{children:"In this bonus you can implement two tasks, one of them has a bonus part with generic\nsolution."}),"\n",(0,i.jsx)(n.p,{children:"One is focused on counting ananas or in case of generic version any substring in\nthe file, but with a restriction on the function you use."}),"\n",(0,i.jsx)(n.p,{children:"Other one has a more algorithmic spirit."}),"\n",(0,i.jsx)(n.p,{children:"For this bonus you can get at maximum 2.5 K\u20a1."}),"\n",(0,i.jsx)(n.h2,{id:"warning",children:"Warning"}),"\n",(0,i.jsxs)(n.p,{children:[(0,i.jsx)(n.strong,{children:"DO NOT COMMIT test data"})," to your own git repository, since the tests include\nfiles that exceed 10MB by themselves. Even if they are on separate branch, they\ntake up the space."]}),"\n",(0,i.jsx)(n.h2,{id:"testing",children:"Testing"}),"\n",(0,i.jsxs)(n.p,{children:["For testing you are provided with python script (requires ",(0,i.jsx)(n.code,{children:"click"})," to be installed:\n",(0,i.jsx)(n.code,{children:"pip3 install --user click"}),") and ",(0,i.jsx)(n.code,{children:"Makefile"})," that provides following targets:"]}),"\n",(0,i.jsxs)(n.ul,{children:["\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:"check-counting"})," - runs the ",(0,i.jsx)(n.code,{children:"counting"})," tests"]}),"\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:"check-counting-bonus"})," - runs the ",(0,i.jsx)(n.code,{children:"counting"})," tests with bonus implemented"]}),"\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:"check"})," - runs both ",(0,i.jsx)(n.code,{children:"counting"})," and ",(0,i.jsx)(n.code,{children:"counting-bonus"})," tests"]}),"\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:"clean"})," - removes output files from the test runs"]}),"\n"]}),"\n",(0,i.jsx)(n.h2,{id:"task-no-1-counting-075-k",children:"Task no. 1: Counting (0.75 K\u20a1)"}),"\n",(0,i.jsx)(n.p,{children:"Your first task is to make smallish program that counts occurences of specific\n(or given) word from file and writes the number to other file."}),"\n",(0,i.jsx)(n.p,{children:"Usage of the program is:"}),"\n",(0,i.jsx)(n.pre,{children:(0,i.jsx)(n.code,{children:"Usage: ./counting [string-to-be-counted]\n"})}),"\n",(0,i.jsx)(n.p,{children:"Arguments that are passed to the program represent:"}),"\n",(0,i.jsxs)(n.ul,{children:["\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:""})," - path to the file where we count the words"]}),"\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:""})," - path to the file where we output the count"]}),"\n",(0,i.jsxs)(n.li,{children:["(optional argument) ",(0,i.jsx)(n.code,{children:"[string-to-be-counted]"})," - in case you implement bonus,\notherwise we default to word ",(0,i.jsx)(n.code,{children:"ananas"})," ;)"]}),"\n"]}),"\n",(0,i.jsx)(n.p,{children:"In skeleton you are given 3 empty, but documented, functions to implement."}),"\n",(0,i.jsxs)(n.ol,{children:["\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:"count_anything"})," - function accepts input file and substring to be counted in\nthe file, returns the count."]}),"\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:"count_ananas"})," - same as ",(0,i.jsx)(n.code,{children:"count_anything"}),", but specialized for ananases, the\ndefault implementation from the skeleton expects you to implement ",(0,i.jsx)(n.code,{children:"count_anything"}),"\nand therefore it just calls the other function."]}),"\n",(0,i.jsxs)(n.li,{children:[(0,i.jsx)(n.code,{children:"write_number"})," - function that writes the number to the file, why would you\nneed the function is explained later :)"]}),"\n"]}),"\n",(0,i.jsx)(n.h3,{id:"requirements",children:"Requirements"}),"\n",(0,i.jsxs)(n.p,{children:["For manipulation with the files you are only allowed to use ",(0,i.jsx)(n.code,{children:"fopen"}),", ",(0,i.jsx)(n.code,{children:"fclose"}),",\n",(0,i.jsx)(n.code,{children:"fgetc"})," and ",(0,i.jsx)(n.code,{children:"fputc"}),". Functions like ",(0,i.jsx)(n.code,{children:"fprintf"})," (except for ",(0,i.jsx)(n.code,{children:"stderr"})," or logging) and\n",(0,i.jsx)(n.code,{children:"fscanf"})," are ",(0,i.jsx)(n.strong,{children:"forbidden"}),"."]}),"\n",(0,i.jsx)(n.p,{children:"In case you struggle and want to use one of those functions, the solution will be\npenalized by 50% of points."}),"\n",(0,i.jsx)(n.h3,{id:"bonus-part-075-k",children:"Bonus part (0.75 K\u20a1)"}),"\n",(0,i.jsxs)(n.p,{children:["Bonus part of this assignment is to implement ",(0,i.jsx)(n.code,{children:"count_anything"})," rather than ",(0,i.jsx)(n.code,{children:"count_ananas"}),"."]}),"\n",(0,i.jsxs)(n.blockquote,{children:["\n",(0,i.jsx)(n.p,{children:"Smaller hint: This task does not need dynamic allocation :) You just need one\ngood helper function and the right idea ;)"}),"\n"]}),"\n",(0,i.jsx)(n.h2,{id:"task-no-2-weird-trees-1-k",children:"Task no. 2: Weird trees (1 K\u20a1)"}),"\n",(0,i.jsxs)(n.p,{children:["In this task we are crossing our paths with ",(0,i.jsx)(n.em,{children:"algorithms and data structures"}),".\nYour task is to write a program that constructs tree from the file that is given\nas an argument and pretty-prints it."]}),"\n",(0,i.jsxs)(n.p,{children:["Input file consists of lines, that include ",(0,i.jsx)(n.code,{children:"key"})," and ",(0,i.jsx)(n.code,{children:"rank"})," in form ",(0,i.jsx)(n.code,{children:"key;rank"}),"\nor ",(0,i.jsx)(n.code,{children:"nil"}),". Why would we have ",(0,i.jsx)(n.code,{children:"nil"})," in a file? The file represents pre-order iteration\nthrough the tree. Leaves never have rank different than 0, so you can safely assume\n2 non-existing ",(0,i.jsx)(n.code,{children:"nil"}),"s in the input after you read such node ;)"]}),"\n",(0,i.jsxs)("table",{children:[(0,i.jsxs)("tr",{children:[(0,i.jsx)("th",{children:"Example input file"}),(0,i.jsx)("th",{children:"Tree it represents"})]}),(0,i.jsxs)("tr",{children:[(0,i.jsx)("td",{children:(0,i.jsx)(n.pre,{children:(0,i.jsx)(n.code,{children:"8;4\n5;3\n3;2\n2;1\n1;0\nnil\n4;0\n7;1\n6;0\nnil\n11;2\n10;1\n9;0\nnil\n12;0\n"})})}),(0,i.jsx)("td",{children:(0,i.jsx)(n.p,{children:(0,i.jsx)(n.img,{alt:"tree",src:t(30073).Z+"",width:"633",height:"684"})})})]})]}),"\n",(0,i.jsxs)(n.p,{children:["In this task you are only provided with different trees in the ",(0,i.jsx)(n.code,{children:"test-trees"})," directory.\nImplementation and format of the pretty-print is totally up to you. :)"]}),"\n",(0,i.jsx)(n.p,{children:"Example of mine for the tree above:"}),"\n",(0,i.jsx)(n.pre,{children:(0,i.jsx)(n.code,{children:"8 (rank = 4)\n+-- 5 (rank = 3)\n| +-- 3 (rank = 2)\n| | +-- 2 (rank = 1)\n| | | +-- 1 (rank = 0)\n| | +-- 4 (rank = 0)\n| +-- 7 (rank = 1)\n| +-- 6 (rank = 0)\n+-- 11 (rank = 2)\n +-- 10 (rank = 1)\n | +-- 9 (rank = 0)\n +-- 12 (rank = 0)\n"})}),"\n",(0,i.jsxs)(n.blockquote,{children:["\n",(0,i.jsx)(n.p,{children:"Can you find out what are those trees? :)"}),"\n"]}),"\n",(0,i.jsx)(n.h2,{id:"submitting",children:"Submitting"}),"\n",(0,i.jsx)(n.p,{children:"In case you have any questions, feel free to reach out to me."}),"\n",(0,i.jsx)(n.hr,{})]})}function h(e={}){const{wrapper:n}={...(0,s.a)(),...e.components};return n?(0,i.jsx)(n,{...e,children:(0,i.jsx)(d,{...e})}):d(e)}},30073:(e,n,t)=>{t.d(n,{Z:()=>i});const i=t.p+"assets/images/tree-c9e37f87f9095c00fad33ea034485ce6.png"},11151:(e,n,t)=>{t.d(n,{Z:()=>c,a:()=>o});var i=t(67294);const s={},r=i.createContext(s);function o(e){const n=i.useContext(r);return i.useMemo((function(){return"function"==typeof e?e(n):{...n,...e}}),[n,e])}function c(e){let n;return n=e.disableParentContext?"function"==typeof e.components?e.components(s):e.components||s:o(e.components),i.createElement(r.Provider,{value:n},e.children)}}}]); \ No newline at end of file diff --git a/assets/js/5fe5d476.4c192803.js b/assets/js/5fe5d476.4c192803.js new file mode 100644 index 0000000..283d800 --- /dev/null +++ b/assets/js/5fe5d476.4c192803.js @@ -0,0 +1 @@ +"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[2619],{14457:(s,e,n)=>{n.r(e),n.d(e,{assets:()=>c,contentTitle:()=>t,default:()=>o,frontMatter:()=>l,metadata:()=>r,toc:()=>m});var a=n(85893),i=n(11151);const l={id:"pyramid-slide-down",title:"Introduction to dynamic programming",description:"Solving a problem in different ways.\n",tags:["java","recursion","exponential","greedy","dynamic-programming","top-down-dp","bottom-up-dp"],last_updated:{date:new Date("2023-08-17T00:00:00.000Z")}},t=void 0,r={id:"recursion/pyramid-slide-down",title:"Introduction to dynamic programming",description:"Solving a problem in different ways.\n",source:"@site/algorithms/04-recursion/2023-08-17-pyramid-slide-down.md",sourceDirName:"04-recursion",slug:"/recursion/pyramid-slide-down",permalink:"/algorithms/recursion/pyramid-slide-down",draft:!1,unlisted:!1,editUrl:"https://github.com/mfocko/blog/tree/main/algorithms/04-recursion/2023-08-17-pyramid-slide-down.md",tags:[{label:"java",permalink:"/algorithms/tags/java"},{label:"recursion",permalink:"/algorithms/tags/recursion"},{label:"exponential",permalink:"/algorithms/tags/exponential"},{label:"greedy",permalink:"/algorithms/tags/greedy"},{label:"dynamic-programming",permalink:"/algorithms/tags/dynamic-programming"},{label:"top-down-dp",permalink:"/algorithms/tags/top-down-dp"},{label:"bottom-up-dp",permalink:"/algorithms/tags/bottom-up-dp"}],version:"current",lastUpdatedAt:1703373170,formattedLastUpdatedAt:"Dec 23, 2023",frontMatter:{id:"pyramid-slide-down",title:"Introduction to dynamic programming",description:"Solving a problem in different ways.\n",tags:["java","recursion","exponential","greedy","dynamic-programming","top-down-dp","bottom-up-dp"],last_updated:{date:"2023-08-17T00:00:00.000Z"}},sidebar:"autogeneratedBar",previous:{title:"Solution to the problem",permalink:"/algorithms/recursion/karel/solution"},next:{title:"Red-Black Trees",permalink:"/algorithms/category/red-black-trees"}},c={},m=[{value:"Problem",id:"problem",level:2},{value:"Solving the problem",id:"solving-the-problem",level:2},{value:"Na\xefve solution",id:"na\xefve-solution",level:2},{value:"Time complexity",id:"time-complexity",level:3},{value:"Greedy solution",id:"greedy-solution",level:2},{value:"Time complexity",id:"time-complexity-1",level:3},{value:"Running the tests",id:"running-the-tests",level:3},{value:"Top-down DP",id:"top-down-dp",level:2},{value:"Time complexity",id:"time-complexity-2",level:3},{value:"Memory complexity",id:"memory-complexity",level:3},{value:"Bottom-up DP",id:"bottom-up-dp",level:2},{value:"Time complexity",id:"time-complexity-3",level:3},{value:"Memory complexity",id:"memory-complexity-1",level:3},{value:"Summary",id:"summary",level:2}];function h(s){const e={a:"a",admonition:"admonition",annotation:"annotation",code:"code",em:"em",h2:"h2",h3:"h3",hr:"hr",li:"li",math:"math",mdxAdmonitionTitle:"mdxAdmonitionTitle",mi:"mi",mn:"mn",mo:"mo",mrow:"mrow",mspace:"mspace",mstyle:"mstyle",msub:"msub",msup:"msup",mtable:"mtable",mtd:"mtd",mtext:"mtext",mtr:"mtr",munderover:"munderover",ol:"ol",p:"p",pre:"pre",section:"section",semantics:"semantics",span:"span",strong:"strong",sup:"sup",...(0,i.a)(),...s.components};return(0,a.jsxs)(a.Fragment,{children:[(0,a.jsx)(e.p,{children:"In this post we will try to solve one problem in different ways."}),"\n",(0,a.jsx)(e.h2,{id:"problem",children:"Problem"}),"\n",(0,a.jsxs)(e.p,{children:["The problem we are going to solve is one of ",(0,a.jsx)(e.em,{children:"CodeWars"})," katas and is called\n",(0,a.jsx)(e.a,{href:"https://www.codewars.com/kata/551f23362ff852e2ab000037",children:"Pyramid Slide Down"}),"."]}),"\n",(0,a.jsxs)(e.p,{children:["We are given a 2D array of integers and we are to find the ",(0,a.jsx)(e.em,{children:"slide down"}),".\n",(0,a.jsx)(e.em,{children:"Slide down"})," is a maximum sum of consecutive numbers from the top to the bottom."]}),"\n",(0,a.jsx)(e.p,{children:"Let's have a look at few examples. Consider the following pyramid:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{children:" 3\n 7 4\n 2 4 6\n8 5 9 3\n"})}),"\n",(0,a.jsx)(e.p,{children:"This pyramid has following slide down:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{children:" *3\n *7 4\n 2 *4 6\n8 5 *9 3\n"})}),"\n",(0,a.jsxs)(e.p,{children:["And its value is ",(0,a.jsx)(e.code,{children:"23"}),"."]}),"\n",(0,a.jsxs)(e.p,{children:["We can also have a look at a ",(0,a.jsx)(e.em,{children:"bigger"})," example:"]}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{children:" 75\n 95 64\n 17 47 82\n 18 35 87 10\n 20 4 82 47 65\n 19 1 23 3 34\n 88 2 77 73 7 63 67\n 99 65 4 28 6 16 70 92\n 41 41 26 56 83 40 80 70 33\n 41 48 72 33 47 32 37 16 94 29\n 53 71 44 65 25 43 91 52 97 51 14\n 70 11 33 28 77 73 17 78 39 68 17 57\n 91 71 52 38 17 14 91 43 58 50 27 29 48\n 63 66 4 68 89 53 67 30 73 16 69 87 40 31\n 4 62 98 27 23 9 70 98 73 93 38 53 60 4 23\n"})}),"\n",(0,a.jsxs)(e.p,{children:["Slide down in this case is equal to ",(0,a.jsx)(e.code,{children:"1074"}),"."]}),"\n",(0,a.jsx)(e.h2,{id:"solving-the-problem",children:"Solving the problem"}),"\n",(0,a.jsx)(e.admonition,{type:"caution",children:(0,a.jsxs)(e.p,{children:["I will describe the following ways you can approach this problem and implement\nthem in ",(0,a.jsx)(e.em,{children:"Java"}),(0,a.jsx)(e.sup,{children:(0,a.jsx)(e.a,{href:"#user-content-fn-1",id:"user-content-fnref-1","data-footnote-ref":!0,"aria-describedby":"footnote-label",children:"1"})}),"."]})}),"\n",(0,a.jsxs)(e.p,{children:["For all of the following solutions I will be using basic ",(0,a.jsx)(e.code,{children:"main"})," function that\nwill output ",(0,a.jsx)(e.code,{children:"true"}),"/",(0,a.jsx)(e.code,{children:"false"})," based on the expected output of our algorithm. Any\nother differences will lie only in the solutions of the problem. You can see the\n",(0,a.jsx)(e.code,{children:"main"})," here:"]}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:'public static void main(String[] args) {\n System.out.print("Test #1: ");\n System.out.println(longestSlideDown(new int[][] {\n { 3 },\n { 7, 4 },\n { 2, 4, 6 },\n { 8, 5, 9, 3 }\n }) == 23 ? "passed" : "failed");\n\n System.out.print("Test #2: ");\n System.out.println(longestSlideDown(new int[][] {\n { 75 },\n { 95, 64 },\n { 17, 47, 82 },\n { 18, 35, 87, 10 },\n { 20, 4, 82, 47, 65 },\n { 19, 1, 23, 75, 3, 34 },\n { 88, 2, 77, 73, 7, 63, 67 },\n { 99, 65, 4, 28, 6, 16, 70, 92 },\n { 41, 41, 26, 56, 83, 40, 80, 70, 33 },\n { 41, 48, 72, 33, 47, 32, 37, 16, 94, 29 },\n { 53, 71, 44, 65, 25, 43, 91, 52, 97, 51, 14 },\n { 70, 11, 33, 28, 77, 73, 17, 78, 39, 68, 17, 57 },\n { 91, 71, 52, 38, 17, 14, 91, 43, 58, 50, 27, 29, 48 },\n { 63, 66, 4, 68, 89, 53, 67, 30, 73, 16, 69, 87, 40, 31 },\n { 4, 62, 98, 27, 23, 9, 70, 98, 73, 93, 38, 53, 60, 4, 23 },\n }) == 1074 ? "passed" : "failed");\n}\n'})}),"\n",(0,a.jsx)(e.h2,{id:"na\xefve-solution",children:"Na\xefve solution"}),"\n",(0,a.jsx)(e.p,{children:"Our na\xefve solution consists of trying out all the possible slides and finding\nthe one with maximum sum."}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:"public static int longestSlideDown(int[][] pyramid, int row, int col) {\n if (row >= pyramid.length || col < 0 || col >= pyramid[row].length) {\n // BASE: We have gotten out of bounds, there's no reasonable value to\n // return, so we just return the \u2039MIN_VALUE\u203a to ensure that it cannot\n // be maximum.\n return Integer.MIN_VALUE;\n }\n\n if (row == pyramid.length - 1) {\n // BASE: Bottom of the pyramid, we just return the value, there's\n // nowhere to slide anymore.\n return pyramid[row][col];\n }\n\n // Otherwise we account for the current position and return maximum of the\n // available \u201cslides\u201d.\n return pyramid[row][col] + Math.max(\n longestSlideDown(pyramid, row + 1, col),\n longestSlideDown(pyramid, row + 1, col + 1));\n}\n\npublic static int longestSlideDown(int[][] pyramid) {\n // We start the slide in the top cell of the pyramid.\n return longestSlideDown(pyramid, 0, 0);\n}\n"})}),"\n",(0,a.jsx)(e.p,{children:"As you can see, we have 2 overloads:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:"int longestSlideDown(int[][] pyramid);\nint longestSlideDown(int[][] pyramid, int row, int col);\n"})}),"\n",(0,a.jsxs)(e.p,{children:["First one is used as a ",(0,a.jsx)(e.em,{children:"public interface"})," to the solution, you just pass in the\npyramid itself. Second one is the recursive \u201calgorithm\u201d that finds the slide\ndown."]}),"\n",(0,a.jsxs)(e.p,{children:["It is a relatively simple solution\u2026 There's nothing to do at the bottom of the\npyramid, so we just return the value in the ",(0,a.jsx)(e.em,{children:"cell"}),". Otherwise we add it and try\nto slide down the available cells below the current row."]}),"\n",(0,a.jsx)(e.h3,{id:"time-complexity",children:"Time complexity"}),"\n",(0,a.jsx)(e.p,{children:"If you get the source code and run it yourself, it runs rather fine\u2026 I hope you\nare wondering about the time complexity of the proposed solution and, since it\nreally is a na\xefve solution, the time complexity is pretty bad. Let's find the\nworst case scenario."}),"\n",(0,a.jsx)(e.p,{children:"Let's start with the first overload:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:"public static int longestSlideDown(int[][] pyramid) {\n return longestSlideDown(pyramid, 0, 0);\n}\n"})}),"\n",(0,a.jsxs)(e.p,{children:["There's not much to do here, so we can safely say that the time complexity of\nthis function is bounded by ",(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"T"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"n"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"T(n)"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.13889em"},children:"T"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"n"}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})})]}),", where ",(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsx)(e.mrow,{children:(0,a.jsx)(e.mi,{children:"T"})}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"T"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"0.6833em"}}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.13889em"},children:"T"})]})})]})," is our second overload. This\ndoesn't tell us anything, so let's move on to the second overload where we are\ngoing to define the ",(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"T"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"n"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"T(n)"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.13889em"},children:"T"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"n"}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})})]})," function."]}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:"public static int longestSlideDown(int[][] pyramid, int row, int col) {\n if (row >= pyramid.length || col < 0 || col >= pyramid[row].length) {\n // BASE: We have gotten out of bounds, there's no reasonable value to\n // return, so we just return the \u2039MIN_VALUE\u203a to ensure that it cannot\n // be maximum.\n return Integer.MIN_VALUE;\n }\n\n if (row == pyramid.length - 1) {\n // BASE: Bottom of the pyramid, we just return the value, there's\n // nowhere to slide anymore.\n return pyramid[row][col];\n }\n\n // Otherwise we account for the current position and return maximum of the\n // available \u201cslides\u201d.\n return pyramid[row][col] + Math.max(\n longestSlideDown(pyramid, row + 1, col),\n longestSlideDown(pyramid, row + 1, col + 1));\n}\n"})}),"\n",(0,a.jsxs)(e.p,{children:["Fun fact is that the whole \u201calgorithm\u201d consists of just 2 ",(0,a.jsx)(e.code,{children:"return"})," statements\nand nothing else. Let's dissect them!"]}),"\n",(0,a.jsxs)(e.p,{children:["First ",(0,a.jsx)(e.code,{children:"return"})," statement is the base case, so it has a constant time complexity."]}),"\n",(0,a.jsxs)(e.p,{children:["Second one a bit tricky. We add two numbers together, which we'll consider as\nconstant, but for the right part of the expression we take maximum from the left\nand right paths. OK\u2026 So what happens? We evaluate the ",(0,a.jsx)(e.code,{children:"longestSlideDown"})," while\nchoosing the under and right both. They are separate computations though, so we\nare branching from each call of ",(0,a.jsx)(e.code,{children:"longestSlideDown"}),", unless it's a base case."]}),"\n",(0,a.jsx)(e.p,{children:"What does that mean for us then? We basically get"}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"T"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"y"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"}),(0,a.jsx)(e.mo,{children:"="}),(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mo,{fence:"true",children:"{"}),(0,a.jsxs)(e.mtable,{rowspacing:"0.36em",columnalign:"left 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If you sum it up, you'll get:"}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"T"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"r"}),(0,a.jsx)(e.mi,{children:"o"}),(0,a.jsx)(e.mi,{children:"w"}),(0,a.jsx)(e.mi,{children:"s"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"}),(0,a.jsx)(e.mo,{children:"\u2208"}),(0,a.jsx)(e.mi,{mathvariant:"script",children:"O"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsxs)(e.msup,{children:[(0,a.jsx)(e.mn,{children:"2"}),(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"r"}),(0,a.jsx)(e.mi,{children:"o"}),(0,a.jsx)(e.mi,{children:"w"}),(0,a.jsx)(e.mi,{children:"s"})]})]}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"T(rows) \\in \\mathcal{O}(2^{rows})"})]})})}),(0,a.jsxs)(e.span,{className:"katex-html","aria-hidden":"true",children:[(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.13889em"},children:"T"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"ro"}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.02691em"},children:"w"}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"s"}),(0,a.jsx)(e.span,{className:"mclose",children:")"}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.2778em"}}),(0,a.jsx)(e.span,{className:"mrel",children:"\u2208"}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.2778em"}})]}),(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathcal",style:{marginRight:"0.02778em"},children:"O"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsxs)(e.span,{className:"mord",children:[(0,a.jsx)(e.span,{className:"mord",children:"2"}),(0,a.jsx)(e.span,{className:"msupsub",children:(0,a.jsx)(e.span,{className:"vlist-t",children:(0,a.jsx)(e.span,{className:"vlist-r",children:(0,a.jsx)(e.span,{className:"vlist",style:{height:"0.7144em"},children:(0,a.jsxs)(e.span,{style:{top:"-3.113em",marginRight:"0.05em"},children:[(0,a.jsx)(e.span,{className:"pstrut",style:{height:"2.7em"}}),(0,a.jsx)(e.span,{className:"sizing reset-size6 size3 mtight",children:(0,a.jsxs)(e.span,{className:"mord mtight",children:[(0,a.jsx)(e.span,{className:"mord mathnormal mtight",children:"ro"}),(0,a.jsx)(e.span,{className:"mord mathnormal mtight",style:{marginRight:"0.02691em"},children:"w"}),(0,a.jsx)(e.span,{className:"mord mathnormal mtight",children:"s"})]})})]})})})})})]}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})]})]})}),"\n",(0,a.jsx)(e.p,{children:"If you wonder why, I'll try to describe it intuitively:"}),"\n",(0,a.jsxs)(e.ol,{children:["\n",(0,a.jsxs)(e.li,{children:["In each call to ",(0,a.jsx)(e.code,{children:"longestSlideDown"})," we do some work in constant time,\nregardless of being in the base case. Those are the ",(0,a.jsx)(e.code,{children:"1"}),"s in both cases."]}),"\n",(0,a.jsxs)(e.li,{children:["If we are not in the base case, we move one row down ",(0,a.jsx)(e.strong,{children:"twice"}),". That's how we\nobtained ",(0,a.jsx)(e.code,{children:"2 *"})," and ",(0,a.jsx)(e.code,{children:"y + 1"})," in the ",(0,a.jsx)(e.em,{children:"otherwise"})," case."]}),"\n",(0,a.jsxs)(e.li,{children:["We move row-by-row, so we move down ",(0,a.jsx)(e.code,{children:"y"}),"-times and each call splits to two\nsubtrees."]}),"\n",(0,a.jsxs)(e.li,{children:["Overall, if we were to represent the calls as a tree, we would get a full\nbinary tree of height ",(0,a.jsx)(e.code,{children:"y"}),", in each node we do some work in constant time,\ntherefore we can just sum the ones."]}),"\n"]}),"\n",(0,a.jsx)(e.admonition,{type:"warning",children:(0,a.jsx)(e.p,{children:"It would've been more complicated to get an exact result. In the equation above\nwe are assuming that the width of the pyramid is bound by the height."})}),"\n",(0,a.jsxs)(e.p,{children:["Hopefully we can agree that this is not the best we can do. ","\ud83d\ude09"]}),"\n",(0,a.jsx)(e.h2,{id:"greedy-solution",children:"Greedy solution"}),"\n",(0,a.jsxs)(e.p,{children:["We will try to optimize it a bit. Let's start with a relatively simple ",(0,a.jsx)(e.em,{children:"greedy"}),"\napproach."]}),"\n",(0,a.jsx)(e.admonition,{title:"Greedy algorithms",type:"info",children:(0,a.jsxs)(e.p,{children:[(0,a.jsx)(e.em,{children:"Greedy algorithms"})," can be described as algorithms that decide the action on the\noptimal option at the moment."]})}),"\n",(0,a.jsx)(e.p,{children:"We can try to adjust the na\xefve solution. The most problematic part are the\nrecursive calls. Let's apply the greedy approach there:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:"public static int longestSlideDown(int[][] pyramid, int row, int col) {\n if (row == pyramid.length - 1) {\n // BASE: We're at the bottom\n return pyramid[row][col];\n }\n\n if (col + 1 >= pyramid[row + 1].length\n || pyramid[row + 1][col] > pyramid[row + 1][col + 1]) {\n // If we cannot go right or it's not feasible, we continue to the left.\n return pyramid[row][col] + longestSlideDown(pyramid, row + 1, col);\n }\n\n // Otherwise we just move to the right.\n return pyramid[row][col] + longestSlideDown(pyramid, row + 1, col + 1);\n}\n"})}),"\n",(0,a.jsxs)(e.p,{children:["OK, if we cannot go right ",(0,a.jsx)(e.strong,{children:"or"})," the right path adds smaller value to the sum,\nwe simply go left."]}),"\n",(0,a.jsx)(e.h3,{id:"time-complexity-1",children:"Time complexity"}),"\n",(0,a.jsxs)(e.p,{children:["We have switched from ",(0,a.jsx)(e.em,{children:"adding the maximum"})," to ",(0,a.jsx)(e.em,{children:"following the \u201cbigger\u201d path"}),", so\nwe improved the time complexity tremendously. We just go down the pyramid all\nthe way to the bottom. Therefore we are getting:"]}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{mathvariant:"script",children:"O"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"r"}),(0,a.jsx)(e.mi,{children:"o"}),(0,a.jsx)(e.mi,{children:"w"}),(0,a.jsx)(e.mi,{children:"s"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\mathcal{O}(rows)"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathcal",style:{marginRight:"0.02778em"},children:"O"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"ro"}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.02691em"},children:"w"}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"s"}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})})]})}),"\n",(0,a.jsx)(e.p,{children:"We have managed to convert our exponential solution into a linear one."}),"\n",(0,a.jsx)(e.h3,{id:"running-the-tests",children:"Running the tests"}),"\n",(0,a.jsx)(e.p,{children:"However, if we run the tests, we notice that the second test failed:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{children:"Test #1: passed\nTest #2: failed\n"})}),"\n",(0,a.jsxs)(e.p,{children:["What's going on? Well, we have improved the time complexity, but greedy\nalgorithms are not the ideal solution to ",(0,a.jsx)(e.strong,{children:"all"})," problems. In this case there\nmay be a solution that is bigger than the one found using the greedy algorithm."]}),"\n",(0,a.jsx)(e.p,{children:"Imagine the following pyramid:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{children:" 1\n 2 3\n 5 6 7\n 8 9 10 11\n99 13 14 15 16\n"})}),"\n",(0,a.jsx)(e.p,{children:"We start at the top:"}),"\n",(0,a.jsxs)(e.ol,{children:["\n",(0,a.jsxs)(e.li,{children:["Current cell: ",(0,a.jsx)(e.code,{children:"1"}),", we can choose from ",(0,a.jsx)(e.code,{children:"2"})," and ",(0,a.jsx)(e.code,{children:"3"}),", ",(0,a.jsx)(e.code,{children:"3"})," looks better, so we\nchoose it."]}),"\n",(0,a.jsxs)(e.li,{children:["Current cell: ",(0,a.jsx)(e.code,{children:"3"}),", we can choose from ",(0,a.jsx)(e.code,{children:"6"})," and ",(0,a.jsx)(e.code,{children:"7"}),", ",(0,a.jsx)(e.code,{children:"7"})," looks better, so we\nchoose it."]}),"\n",(0,a.jsxs)(e.li,{children:["Current cell: ",(0,a.jsx)(e.code,{children:"7"}),", we can choose from ",(0,a.jsx)(e.code,{children:"10"})," and ",(0,a.jsx)(e.code,{children:"11"}),", ",(0,a.jsx)(e.code,{children:"11"})," looks better, so we\nchoose it."]}),"\n",(0,a.jsxs)(e.li,{children:["Current cell: ",(0,a.jsx)(e.code,{children:"11"}),", we can choose from ",(0,a.jsx)(e.code,{children:"15"})," and ",(0,a.jsx)(e.code,{children:"16"}),", ",(0,a.jsx)(e.code,{children:"16"})," looks better, so\nwe choose it."]}),"\n"]}),"\n",(0,a.jsxs)(e.p,{children:["Our final sum is: ",(0,a.jsx)(e.code,{children:"1 + 3 + 7 + 11 + 16 = 38"}),", but in the bottom left cell we\nhave a ",(0,a.jsx)(e.code,{children:"99"})," that is bigger than our whole sum."]}),"\n",(0,a.jsx)(e.admonition,{type:"tip",children:(0,a.jsx)(e.p,{children:"Dijkstra's algorithm is a greedy algorithm too, try to think why it is correct."})}),"\n",(0,a.jsx)(e.h2,{id:"top-down-dp",children:"Top-down DP"}),"\n",(0,a.jsxs)(e.p,{children:[(0,a.jsx)(e.em,{children:"Top-down dynamic programming"})," is probably the most common approach, since (at\nleast looks like) is the easiest to implement. The whole point is avoiding the\nunnecessary computations that we have already done."]}),"\n",(0,a.jsxs)(e.p,{children:["In our case, we can use our na\xefve solution and put a ",(0,a.jsx)(e.em,{children:"cache"})," on top of it that\nwill make sure, we don't do unnecessary calculations."]}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:"// This \u201cstructure\u201d is required, since I have decided to use \u2039TreeMap\u203a which\n// requires the ordering on the keys. It represents one position in the pyramid.\nrecord Position(int row, int col) implements Comparable {\n public int compareTo(Position r) {\n if (row != r.row) {\n return Integer.valueOf(row).compareTo(r.row);\n }\n\n if (col != r.col) {\n return Integer.valueOf(col).compareTo(r.col);\n }\n\n return 0;\n }\n}\n\npublic static int longestSlideDown(\n int[][] pyramid,\n TreeMap cache,\n Position position) {\n int row = position.row;\n int col = position.col;\n\n if (row >= pyramid.length || col < 0 || col >= pyramid[row].length) {\n // BASE: out of bounds\n return Integer.MIN_VALUE;\n }\n\n if (row == pyramid.length - 1) {\n // BASE: bottom of the pyramid\n return pyramid[position.row][position.col];\n }\n\n if (!cache.containsKey(position)) {\n // We haven't computed the position yet, so we run the same \u201cformula\u201d as\n // in the na\xefve version \xbband\xab we put calculated slide into the cache.\n // Next time we want the slide down from given position, it will be just\n // retrieved from the cache.\n int slideDown = Math.max(\n longestSlideDown(pyramid, cache, new Position(row + 1, col)),\n longestSlideDown(pyramid, cache, new Position(row + 1, col + 1)));\n cache.put(position, pyramid[row][col] + slideDown);\n }\n\n return cache.get(position);\n}\n\npublic static int longestSlideDown(int[][] pyramid) {\n // At the beginning we need to create a cache and share it across the calls.\n TreeMap cache = new TreeMap<>();\n return longestSlideDown(pyramid, cache, new Position(0, 0));\n}\n"})}),"\n",(0,a.jsxs)(e.p,{children:["You have probably noticed that ",(0,a.jsx)(e.code,{children:"record Position"})," have appeared. Since we are\ncaching the already computed values, we need a \u201creasonable\u201d key. In this case we\nshare the cache only for one ",(0,a.jsx)(e.em,{children:"run"})," (i.e. pyramid) of the ",(0,a.jsx)(e.code,{children:"longestSlideDown"}),", so\nwe can cache just with the indices within the pyramid, i.e. the ",(0,a.jsx)(e.code,{children:"Position"}),"."]}),"\n",(0,a.jsx)(e.admonition,{title:"Record",type:"tip",children:(0,a.jsxs)(e.p,{children:[(0,a.jsx)(e.em,{children:"Record"})," is relatively new addition to the Java language. It is basically an\nimmutable structure with implicitly defined ",(0,a.jsx)(e.code,{children:".equals()"}),", ",(0,a.jsx)(e.code,{children:".hashCode()"}),",\n",(0,a.jsx)(e.code,{children:".toString()"})," and getters for the attributes."]})}),"\n",(0,a.jsxs)(e.p,{children:["Because of the choice of ",(0,a.jsx)(e.code,{children:"TreeMap"}),", we had to additionally define the ordering\non it."]}),"\n",(0,a.jsxs)(e.p,{children:["In the ",(0,a.jsx)(e.code,{children:"longestSlideDown"})," you can notice that the computation which used to be\nat the end of the na\xefve version above, is now wrapped in an ",(0,a.jsx)(e.code,{children:"if"})," statement that\nchecks for the presence of the position in the cache and computes the slide down\njust when it's needed."]}),"\n",(0,a.jsx)(e.h3,{id:"time-complexity-2",children:"Time complexity"}),"\n",(0,a.jsx)(e.p,{children:"If you think that evaluating time complexity for this approach is a bit more\ntricky, you are right. Keeping the cache in mind, it is not the easiest thing\nto do. However there are some observations that might help us figure this out:"}),"\n",(0,a.jsxs)(e.ol,{children:["\n",(0,a.jsx)(e.li,{children:"Slide down from each position is calculated only once."}),"\n",(0,a.jsx)(e.li,{children:"Once calculated, we use the result from the cache."}),"\n"]}),"\n",(0,a.jsxs)(e.p,{children:["Knowing this, we still cannot, at least easily, describe the time complexity of\nfinding the best slide down from a specific position, ",(0,a.jsx)(e.strong,{children:"but"})," we can bound it\nfrom above for the ",(0,a.jsx)(e.strong,{children:"whole"})," run from the top. Now the question is how we can do\nthat!"]}),"\n",(0,a.jsxs)(e.p,{children:["Overall we are doing the same things for almost",(0,a.jsx)(e.sup,{children:(0,a.jsx)(e.a,{href:"#user-content-fn-2",id:"user-content-fnref-2","data-footnote-ref":!0,"aria-describedby":"footnote-label",children:"2"})})," all of the positions within\nthe pyramid:"]}),"\n",(0,a.jsxs)(e.ol,{children:["\n",(0,a.jsxs)(e.li,{children:["\n",(0,a.jsx)(e.p,{children:"We calculate and store it (using the partial results stored in cache). This\nis done only once."}),"\n",(0,a.jsxs)(e.p,{children:["For each calculation we take 2 values from the cache and insert one value.\nBecause we have chosen ",(0,a.jsx)(e.code,{children:"TreeMap"}),", these 3 operations have logarithmic time\ncomplexity and therefore this step is equivalent to ",(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mn,{children:"3"}),(0,a.jsx)(e.mo,{children:"\u22c5"}),(0,a.jsxs)(e.msub,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"log"}),(0,a.jsx)(e.mo,{children:"\u2061"})]}),(0,a.jsx)(e.mn,{children:"2"})]}),(0,a.jsx)(e.mi,{children:"n"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"3 \\cdot \\log_2{n}"})]})})}),(0,a.jsxs)(e.span,{className:"katex-html","aria-hidden":"true",children:[(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"0.6444em"}}),(0,a.jsx)(e.span,{className:"mord",children:"3"}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.2222em"}}),(0,a.jsx)(e.span,{className:"mbin",children:"\u22c5"}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.2222em"}})]}),(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"0.9386em",verticalAlign:"-0.2441em"}}),(0,a.jsxs)(e.span,{className:"mop",children:[(0,a.jsxs)(e.span,{className:"mop",children:["lo",(0,a.jsx)(e.span,{style:{marginRight:"0.01389em"},children:"g"})]}),(0,a.jsx)(e.span,{className:"msupsub",children:(0,a.jsxs)(e.span,{className:"vlist-t 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will be interleaved with the next step, therefore it is easier to keep the\nretrievals in the following point."}),"\n",(0,a.jsx)(e.admonition,{type:"caution",children:(0,a.jsx)(e.p,{children:"You might have noticed it's still not that easy, cause we're not having full\ncache right from the beginning, but the sum of those logarithms cannot be\nexpressed in a nice way, so taking the upper bound, i.e. expecting the cache\nto be full at all times, is the best option for nice and readable complexity\nof the whole approach."})}),"\n",(0,a.jsxs)(e.p,{children:["Our final upper bound of this work is therefore ",(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsxs)(e.msub,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"log"}),(0,a.jsx)(e.mo,{children:"\u2061"})]}),(0,a.jsx)(e.mn,{children:"2"})]}),(0,a.jsx)(e.mi,{children:"n"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\log_2{n}"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"0.9386em",verticalAlign:"-0.2441em"}}),(0,a.jsxs)(e.span,{className:"mop",children:[(0,a.jsxs)(e.span,{className:"mop",children:["lo",(0,a.jsx)(e.span,{style:{marginRight:"0.01389em"},children:"g"})]}),(0,a.jsx)(e.span,{className:"msupsub",children:(0,a.jsxs)(e.span,{className:"vlist-t 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Same as in first point, but only twice, so we\nget ",(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mn,{children:"2"}),(0,a.jsx)(e.mo,{children:"\u22c5"}),(0,a.jsxs)(e.msub,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"log"}),(0,a.jsx)(e.mo,{children:"\u2061"})]}),(0,a.jsx)(e.mn,{children:"2"})]}),(0,a.jsx)(e.mi,{children:"n"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"2 \\cdot \\log_2{n}"})]})})}),(0,a.jsxs)(e.span,{className:"katex-html","aria-hidden":"true",children:[(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"0.6444em"}}),(0,a.jsx)(e.span,{className:"mord",children:"2"}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.2222em"}}),(0,a.jsx)(e.span,{className:"mbin",children:"\u22c5"}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.2222em"}})]}),(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"0.9386em",verticalAlign:"-0.2441em"}}),(0,a.jsxs)(e.span,{className:"mop",children:[(0,a.jsxs)(e.span,{className:"mop",children:["lo",(0,a.jsx)(e.span,{style:{marginRight:"0.01389em"},children:"g"})]}),(0,a.jsx)(e.span,{className:"msupsub",children:(0,a.jsxs)(e.span,{className:"vlist-t 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",(0,a.jsx)(e.code,{children:"if"})," condition."]})}),"\n"]}),"\n"]}),"\n",(0,a.jsx)(e.p,{children:"Okay, we have evaluated work done for each of the cells in the pyramid and now\nwe need to put it together."}),"\n",(0,a.jsx)(e.p,{children:"Let's split the time complexity of our solution into two operands:"}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{mathvariant:"script",children:"O"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"r"}),(0,a.jsx)(e.mo,{children:"+"}),(0,a.jsx)(e.mi,{children:"s"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\mathcal{O}(r + 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on:"]}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsx)(e.mtable,{rowspacing:"0.25em",columnalign:"right left",columnspacing:"0em",children:(0,a.jsxs)(e.mtr,{children:[(0,a.jsx)(e.mtd,{children:(0,a.jsx)(e.mstyle,{scriptlevel:"0",displaystyle:"true",children:(0,a.jsx)(e.mi,{children:"r"})})}),(0,a.jsx)(e.mtd,{children:(0,a.jsx)(e.mstyle,{scriptlevel:"0",displaystyle:"true",children:(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mrow,{}),(0,a.jsx)(e.mo,{children:"="}),(0,a.jsx)(e.mi,{children:"n"}),(0,a.jsx)(e.mo,{children:"\u22c5"}),(0,a.jsx)(e.mi,{children:"log"}),(0,a.jsx)(e.mo,{children:"\u2061"}),(0,a.jsx)(e.mi,{children:"n"})]})})})]})}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\begin{align*}\nr &= n \\cdot \\log{n} 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Key observation here is the fact that we have 2\nlookups on the tree in each of them ",(0,a.jsx)(e.strong,{children:"and"})," we do it twice, cause each cell has\nat most 2 parents:"]}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mtable,{rowspacing:"0.25em",columnalign:"right 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This is not entirely true, since we have included the\n",(0,a.jsx)(e.code,{children:".containsKey()"})," and ",(0,a.jsx)(e.code,{children:".get()"})," from the ",(0,a.jsx)(e.code,{children:"return"})," statement in the second part."]}),(0,a.jsx)(e.p,{children:"If we were to represent this more precisely, we could've gone with:"}),(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mtable,{rowspacing:"0.25em",columnalign:"right 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However we are expressing the complexity in the\nBachmann-Landau notation, so we care about the ",(0,a.jsx)(e.strong,{children:"upper bound"}),", not the exact\nnumber."]})}),"\n",(0,a.jsxs)(e.admonition,{title:"Can this be optimized?",type:"tip",children:[(0,a.jsx)(e.p,{children:"Yes, it can! Try to think about a way, how can you minimize the memory\ncomplexity of this approach. I'll give you a hint:"}),(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{mathvariant:"script",children:"O"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"r"}),(0,a.jsx)(e.mi,{children:"o"}),(0,a.jsx)(e.mi,{children:"w"}),(0,a.jsx)(e.mi,{children:"s"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\mathcal{O}(rows)"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathcal",style:{marginRight:"0.02778em"},children:"O"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"ro"}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.02691em"},children:"w"}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"s"}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})})]})})]}),"\n",(0,a.jsx)(e.h2,{id:"bottom-up-dp",children:"Bottom-up DP"}),"\n",(0,a.jsxs)(e.p,{children:["If you try to think in depth about the top-down DP solution, you might notice\nthat the ",(0,a.jsx)(e.em,{children:"core"})," of it stands on caching the calculations that have been already\ndone on the lower \u201clevels\u201d of the pyramid. Our bottom-up implementation will be\nusing this fact!"]}),"\n",(0,a.jsxs)(e.admonition,{type:"tip",children:[(0,a.jsxs)(e.p,{children:["As I have said in the ",(0,a.jsx)(e.em,{children:"top-down DP"})," section, it is the easiest way to implement\nDP (unless the cached function has complicated parameters, in that case it might\nget messy)."]}),(0,a.jsx)(e.p,{children:"Bottom-up dynamic programming can be more effective, but may be more complicated\nto implement right from the beginning."})]}),"\n",(0,a.jsx)(e.p,{children:"Let's see how we can implement it:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:"public static int longestSlideDown(int[][] pyramid) {\n // In the beginning we declare new array. At this point it is easier to just\n // work with the one dimension, i.e. just allocating the space for the rows.\n int[][] slideDowns = new int[pyramid.length][];\n\n // Bottom row gets just copied, there's nothing else to do\u2026 It's the base\n // case.\n slideDowns[pyramid.length - 1] = Arrays.copyOf(pyramid[pyramid.length - 1],\n pyramid[pyramid.length - 1].length);\n\n // Then we need to propagate the found slide downs for each of the levels\n // above.\n for (int y = pyramid.length - 2; y >= 0; --y) {\n // We start by copying the values lying in the row we're processing.\n // They get included in the final sum and we need to allocate the space\n // for the precalculated slide downs anyways.\n int[] row = Arrays.copyOf(pyramid[y], pyramid[y].length);\n\n // At this we just need to \u201cfetch\u201d the partial results from \u201cneighbours\u201d\n for (int x = 0; x < row.length; ++x) {\n // We look under our position, since we expect the rows to get\n // shorter, we can safely assume such position exists.\n int under = slideDowns[y + 1][x];\n\n // Then we have a look to the right, such position doesn't have to\n // exist, e.g. on the right edge, so we validate the index, and if\n // it doesn't exist, we just assign minimum of the \u2039int\u203a which makes\n // sure that it doesn't get picked in the \u2039Math.max()\u203a call.\n int toRight = x + 1 < slideDowns[y + 1].length\n ? slideDowns[y + 1][x + 1]\n : Integer.MIN_VALUE;\n\n // Finally we add the best choice at this point.\n row[x] += Math.max(under, toRight);\n }\n\n // And save the row we've just calculated partial results for to the\n // \u201ctable\u201d.\n slideDowns[y] = row;\n }\n\n // At the end we can find our seeked slide down at the top cell.\n return slideDowns[0][0];\n}\n"})}),"\n",(0,a.jsx)(e.p,{children:"I've tried to explain the code as much as possible within the comments, since it\nmight be more beneficial to see right next to the \u201coffending\u201d lines."}),"\n",(0,a.jsxs)(e.p,{children:["As you can see, in this approach we go from the other side",(0,a.jsx)(e.sup,{children:(0,a.jsx)(e.a,{href:"#user-content-fn-3",id:"user-content-fnref-3","data-footnote-ref":!0,"aria-describedby":"footnote-label",children:"3"})}),", the bottom of\nthe pyramid and propagate the partial results up."]}),"\n",(0,a.jsxs)(e.admonition,{type:"info",children:[(0,a.jsxs)(e.mdxAdmonitionTitle,{children:["How is this different from the ",(0,a.jsx)(e.em,{children:"greedy"})," solution???"]}),(0,a.jsxs)(e.p,{children:["If you try to compare them, you might find a very noticable difference. The\ngreedy approach is going from the top to the bottom without ",(0,a.jsx)(e.strong,{children:"any"})," knowledge of\nwhat's going on below. On the other hand, bottom-up DP is going from the bottom\n(",(0,a.jsx)(e.em,{children:"DUH\u2026"}),") and ",(0,a.jsx)(e.strong,{children:"propagates"})," the partial results to the top. The propagation is\nwhat makes sure that at the top I don't choose the best ",(0,a.jsx)(e.strong,{children:"local"})," choice, but\nthe best ",(0,a.jsx)(e.strong,{children:"overall"})," result I can achieve."]})]}),"\n",(0,a.jsx)(e.h3,{id:"time-complexity-3",children:"Time complexity"}),"\n",(0,a.jsx)(e.p,{children:"Time complexity of this solution is rather simple. We allocate an array for the\nrows and then for each row, we copy it and adjust the partial results. Doing\nthis we get:"}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{mathvariant:"script",children:"O"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"r"}),(0,a.jsx)(e.mi,{children:"o"}),(0,a.jsx)(e.mi,{children:"w"}),(0,a.jsx)(e.mi,{children:"s"}),(0,a.jsx)(e.mo,{children:"+"}),(0,a.jsx)(e.mn,{children:"2"}),(0,a.jsx)(e.mi,{children:"n"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\mathcal{O}(rows + 2n)"})]})})}),(0,a.jsxs)(e.span,{className:"katex-html","aria-hidden":"true",children:[(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathcal",style:{marginRight:"0.02778em"},children:"O"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"ro"}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.02691em"},children:"w"}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"s"}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.2222em"}}),(0,a.jsx)(e.span,{className:"mbin",children:"+"}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.2222em"}})]}),(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord",children:"2"}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"n"}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})]})]})}),"\n",(0,a.jsx)(e.p,{children:"Of course, this is an upper bound, since we iterate through the bottom row only\nonce."}),"\n",(0,a.jsx)(e.h3,{id:"memory-complexity-1",children:"Memory complexity"}),"\n",(0,a.jsxs)(e.p,{children:["We're allocating an array for the pyramid ",(0,a.jsx)(e.strong,{children:"again"})," for our partial results, so\nwe get:"]}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{mathvariant:"script",children:"O"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"n"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\mathcal{O}(n)"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathcal",style:{marginRight:"0.02778em"},children:"O"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"n"}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})})]})}),"\n",(0,a.jsxs)(e.admonition,{type:"tip",children:[(0,a.jsx)(e.p,{children:"If we were writing this in C++ or Rust, we could've avoided that, but not\nreally."}),(0,a.jsxs)(e.p,{children:["C++ would allow us to ",(0,a.jsx)(e.strong,{children:"copy"})," the pyramid rightaway into the parameter, so we\nwould be able to directly change it. However it's still a copy, even though we\ndon't need to allocate anything ourselves. It's just implicitly done for us."]}),(0,a.jsxs)(e.p,{children:["Rust is more funny in this case. If the pyramids weren't used after the call of\n",(0,a.jsx)(e.code,{children:"longest_slide_down"}),", it would simply ",(0,a.jsx)(e.strong,{children:"move"})," them into the functions. If they\nwere used afterwards, the compiler would force you to either borrow it, or\n",(0,a.jsx)(e.em,{children:"clone-and-move"})," for the function."]}),(0,a.jsx)(e.hr,{}),(0,a.jsxs)(e.p,{children:["Since we're doing it in Java, we get a reference to the ",(0,a.jsx)(e.em,{children:"original"})," array and we\ncan't do whatever we want with it."]})]}),"\n",(0,a.jsx)(e.h2,{id:"summary",children:"Summary"}),"\n",(0,a.jsxs)(e.p,{children:["And we've finally reached the end. We have seen 4 different \u201csolutions\u201d",(0,a.jsx)(e.sup,{children:(0,a.jsx)(e.a,{href:"#user-content-fn-4",id:"user-content-fnref-4","data-footnote-ref":!0,"aria-describedby":"footnote-label",children:"4"})})," of\nthe same problem using different approaches. Different approaches follow the\norder in which you might come up with them, each approach influences its\nsuccessor and represents the way we can enhance the existing implementation."]}),"\n",(0,a.jsx)(e.hr,{}),"\n",(0,a.jsx)(e.admonition,{title:"source",type:"info",children:(0,a.jsxs)(e.p,{children:["You can find source code referenced in the text\n",(0,a.jsx)(e.a,{href:"pathname:///files/algorithms/recursion/pyramid-slide-down.tar.gz",children:"here"}),"."]})}),"\n",(0,a.jsxs)(e.section,{"data-footnotes":!0,className:"footnotes",children:[(0,a.jsx)(e.h2,{className:"sr-only",id:"footnote-label",children:"Footnotes"}),"\n",(0,a.jsxs)(e.ol,{children:["\n",(0,a.jsxs)(e.li,{id:"user-content-fn-1",children:["\n",(0,a.jsxs)(e.p,{children:["cause why not, right!? ",(0,a.jsx)(e.a,{href:"#user-content-fnref-1","data-footnote-backref":"","aria-label":"Back to reference 1",className:"data-footnote-backref",children:"\u21a9"})]}),"\n"]}),"\n",(0,a.jsxs)(e.li,{id:"user-content-fn-2",children:["\n",(0,a.jsxs)(e.p,{children:["except the bottom row ",(0,a.jsx)(e.a,{href:"#user-content-fnref-2","data-footnote-backref":"","aria-label":"Back to reference 2",className:"data-footnote-backref",children:"\u21a9"})]}),"\n"]}),"\n",(0,a.jsxs)(e.li,{id:"user-content-fn-3",children:["\n",(0,a.jsxs)(e.p,{children:["definitely not an RHCP reference ","\ud83d\ude09 ",(0,a.jsx)(e.a,{href:"#user-content-fnref-3","data-footnote-backref":"","aria-label":"Back to reference 3",className:"data-footnote-backref",children:"\u21a9"})]}),"\n"]}),"\n",(0,a.jsxs)(e.li,{id:"user-content-fn-4",children:["\n",(0,a.jsxs)(e.p,{children:["one was not correct, thus the quotes ",(0,a.jsx)(e.a,{href:"#user-content-fnref-4","data-footnote-backref":"","aria-label":"Back to reference 4",className:"data-footnote-backref",children:"\u21a9"})]}),"\n"]}),"\n"]}),"\n"]})]})}function o(s={}){const{wrapper:e}={...(0,i.a)(),...s.components};return e?(0,a.jsx)(e,{...s,children:(0,a.jsx)(h,{...s})}):h(s)}},11151:(s,e,n)=>{n.d(e,{Z:()=>r,a:()=>t});var a=n(67294);const i={},l=a.createContext(i);function t(s){const e=a.useContext(l);return a.useMemo((function(){return"function"==typeof s?s(e):{...e,...s}}),[e,s])}function r(s){let e;return e=s.disableParentContext?"function"==typeof s.components?s.components(i):s.components||i:t(s.components),a.createElement(l.Provider,{value:e},s.children)}}}]); \ No newline at end of file diff --git a/assets/js/5fe5d476.aea47397.js b/assets/js/5fe5d476.aea47397.js deleted file mode 100644 index f5be013..0000000 --- a/assets/js/5fe5d476.aea47397.js +++ /dev/null @@ -1 +0,0 @@ -"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[2619],{14457:(s,e,n)=>{n.r(e),n.d(e,{assets:()=>c,contentTitle:()=>t,default:()=>o,frontMatter:()=>l,metadata:()=>r,toc:()=>m});var a=n(85893),i=n(11151);const l={id:"pyramid-slide-down",title:"Introduction to dynamic programming",description:"Solving a problem in different ways.\n",tags:["java","recursion","exponential","greedy","dynamic-programming","top-down-dp","bottom-up-dp"],last_updated:{date:new Date("2023-08-17T00:00:00.000Z")}},t=void 0,r={id:"recursion/pyramid-slide-down",title:"Introduction to dynamic programming",description:"Solving a problem in different ways.\n",source:"@site/algorithms/04-recursion/2023-08-17-pyramid-slide-down.md",sourceDirName:"04-recursion",slug:"/recursion/pyramid-slide-down",permalink:"/algorithms/recursion/pyramid-slide-down",draft:!1,unlisted:!1,editUrl:"https://github.com/mfocko/blog/tree/main/algorithms/04-recursion/2023-08-17-pyramid-slide-down.md",tags:[{label:"java",permalink:"/algorithms/tags/java"},{label:"recursion",permalink:"/algorithms/tags/recursion"},{label:"exponential",permalink:"/algorithms/tags/exponential"},{label:"greedy",permalink:"/algorithms/tags/greedy"},{label:"dynamic-programming",permalink:"/algorithms/tags/dynamic-programming"},{label:"top-down-dp",permalink:"/algorithms/tags/top-down-dp"},{label:"bottom-up-dp",permalink:"/algorithms/tags/bottom-up-dp"}],version:"current",lastUpdatedAt:1701271124,formattedLastUpdatedAt:"Nov 29, 2023",frontMatter:{id:"pyramid-slide-down",title:"Introduction to dynamic programming",description:"Solving a problem in different ways.\n",tags:["java","recursion","exponential","greedy","dynamic-programming","top-down-dp","bottom-up-dp"],last_updated:{date:"2023-08-17T00:00:00.000Z"}},sidebar:"autogeneratedBar",previous:{title:"Recursion and backtracking with Robot Karel",permalink:"/algorithms/recursion/karel-1"},next:{title:"Red-Black Trees",permalink:"/algorithms/category/red-black-trees"}},c={},m=[{value:"Problem",id:"problem",level:2},{value:"Solving the problem",id:"solving-the-problem",level:2},{value:"Na\xefve solution",id:"na\xefve-solution",level:2},{value:"Time complexity",id:"time-complexity",level:3},{value:"Greedy solution",id:"greedy-solution",level:2},{value:"Time complexity",id:"time-complexity-1",level:3},{value:"Running the tests",id:"running-the-tests",level:3},{value:"Top-down DP",id:"top-down-dp",level:2},{value:"Time complexity",id:"time-complexity-2",level:3},{value:"Memory complexity",id:"memory-complexity",level:3},{value:"Bottom-up DP",id:"bottom-up-dp",level:2},{value:"Time complexity",id:"time-complexity-3",level:3},{value:"Memory complexity",id:"memory-complexity-1",level:3},{value:"Summary",id:"summary",level:2}];function h(s){const e={a:"a",admonition:"admonition",annotation:"annotation",code:"code",em:"em",h2:"h2",h3:"h3",hr:"hr",li:"li",math:"math",mdxAdmonitionTitle:"mdxAdmonitionTitle",mi:"mi",mn:"mn",mo:"mo",mrow:"mrow",mspace:"mspace",mstyle:"mstyle",msub:"msub",msup:"msup",mtable:"mtable",mtd:"mtd",mtext:"mtext",mtr:"mtr",munderover:"munderover",ol:"ol",p:"p",pre:"pre",section:"section",semantics:"semantics",span:"span",strong:"strong",sup:"sup",...(0,i.a)(),...s.components};return(0,a.jsxs)(a.Fragment,{children:[(0,a.jsx)(e.p,{children:"In this post we will try to solve one problem in different ways."}),"\n",(0,a.jsx)(e.h2,{id:"problem",children:"Problem"}),"\n",(0,a.jsxs)(e.p,{children:["The problem we are going to solve is one of ",(0,a.jsx)(e.em,{children:"CodeWars"})," katas and is called\n",(0,a.jsx)(e.a,{href:"https://www.codewars.com/kata/551f23362ff852e2ab000037",children:"Pyramid Slide Down"}),"."]}),"\n",(0,a.jsxs)(e.p,{children:["We are given a 2D array of integers and we are to find the ",(0,a.jsx)(e.em,{children:"slide down"}),".\n",(0,a.jsx)(e.em,{children:"Slide down"})," is a maximum sum of consecutive numbers from the top to the bottom."]}),"\n",(0,a.jsx)(e.p,{children:"Let's have a look at few examples. Consider the following pyramid:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{children:" 3\n 7 4\n 2 4 6\n8 5 9 3\n"})}),"\n",(0,a.jsx)(e.p,{children:"This pyramid has following slide down:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{children:" *3\n *7 4\n 2 *4 6\n8 5 *9 3\n"})}),"\n",(0,a.jsxs)(e.p,{children:["And its value is ",(0,a.jsx)(e.code,{children:"23"}),"."]}),"\n",(0,a.jsxs)(e.p,{children:["We can also have a look at a ",(0,a.jsx)(e.em,{children:"bigger"})," example:"]}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{children:" 75\n 95 64\n 17 47 82\n 18 35 87 10\n 20 4 82 47 65\n 19 1 23 3 34\n 88 2 77 73 7 63 67\n 99 65 4 28 6 16 70 92\n 41 41 26 56 83 40 80 70 33\n 41 48 72 33 47 32 37 16 94 29\n 53 71 44 65 25 43 91 52 97 51 14\n 70 11 33 28 77 73 17 78 39 68 17 57\n 91 71 52 38 17 14 91 43 58 50 27 29 48\n 63 66 4 68 89 53 67 30 73 16 69 87 40 31\n 4 62 98 27 23 9 70 98 73 93 38 53 60 4 23\n"})}),"\n",(0,a.jsxs)(e.p,{children:["Slide down in this case is equal to ",(0,a.jsx)(e.code,{children:"1074"}),"."]}),"\n",(0,a.jsx)(e.h2,{id:"solving-the-problem",children:"Solving the problem"}),"\n",(0,a.jsx)(e.admonition,{type:"caution",children:(0,a.jsxs)(e.p,{children:["I will describe the following ways you can approach this problem and implement\nthem in ",(0,a.jsx)(e.em,{children:"Java"}),(0,a.jsx)(e.sup,{children:(0,a.jsx)(e.a,{href:"#user-content-fn-1",id:"user-content-fnref-1","data-footnote-ref":!0,"aria-describedby":"footnote-label",children:"1"})}),"."]})}),"\n",(0,a.jsxs)(e.p,{children:["For all of the following solutions I will be using basic ",(0,a.jsx)(e.code,{children:"main"})," function that\nwill output ",(0,a.jsx)(e.code,{children:"true"}),"/",(0,a.jsx)(e.code,{children:"false"})," based on the expected output of our algorithm. Any\nother differences will lie only in the solutions of the problem. You can see the\n",(0,a.jsx)(e.code,{children:"main"})," here:"]}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:'public static void main(String[] args) {\n System.out.print("Test #1: ");\n System.out.println(longestSlideDown(new int[][] {\n { 3 },\n { 7, 4 },\n { 2, 4, 6 },\n { 8, 5, 9, 3 }\n }) == 23 ? "passed" : "failed");\n\n System.out.print("Test #2: ");\n System.out.println(longestSlideDown(new int[][] {\n { 75 },\n { 95, 64 },\n { 17, 47, 82 },\n { 18, 35, 87, 10 },\n { 20, 4, 82, 47, 65 },\n { 19, 1, 23, 75, 3, 34 },\n { 88, 2, 77, 73, 7, 63, 67 },\n { 99, 65, 4, 28, 6, 16, 70, 92 },\n { 41, 41, 26, 56, 83, 40, 80, 70, 33 },\n { 41, 48, 72, 33, 47, 32, 37, 16, 94, 29 },\n { 53, 71, 44, 65, 25, 43, 91, 52, 97, 51, 14 },\n { 70, 11, 33, 28, 77, 73, 17, 78, 39, 68, 17, 57 },\n { 91, 71, 52, 38, 17, 14, 91, 43, 58, 50, 27, 29, 48 },\n { 63, 66, 4, 68, 89, 53, 67, 30, 73, 16, 69, 87, 40, 31 },\n { 4, 62, 98, 27, 23, 9, 70, 98, 73, 93, 38, 53, 60, 4, 23 },\n }) == 1074 ? "passed" : "failed");\n}\n'})}),"\n",(0,a.jsx)(e.h2,{id:"na\xefve-solution",children:"Na\xefve solution"}),"\n",(0,a.jsx)(e.p,{children:"Our na\xefve solution consists of trying out all the possible slides and finding\nthe one with maximum sum."}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:"public static int longestSlideDown(int[][] pyramid, int row, int col) {\n if (row >= pyramid.length || col < 0 || col >= pyramid[row].length) {\n // BASE: We have gotten out of bounds, there's no reasonable value to\n // return, so we just return the \u2039MIN_VALUE\u203a to ensure that it cannot\n // be maximum.\n return Integer.MIN_VALUE;\n }\n\n if (row == pyramid.length - 1) {\n // BASE: Bottom of the pyramid, we just return the value, there's\n // nowhere to slide anymore.\n return pyramid[row][col];\n }\n\n // Otherwise we account for the current position and return maximum of the\n // available \u201cslides\u201d.\n return pyramid[row][col] + Math.max(\n longestSlideDown(pyramid, row + 1, col),\n longestSlideDown(pyramid, row + 1, col + 1));\n}\n\npublic static int longestSlideDown(int[][] pyramid) {\n // We start the slide in the top cell of the pyramid.\n return longestSlideDown(pyramid, 0, 0);\n}\n"})}),"\n",(0,a.jsx)(e.p,{children:"As you can see, we have 2 overloads:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:"int longestSlideDown(int[][] pyramid);\nint longestSlideDown(int[][] pyramid, int row, int col);\n"})}),"\n",(0,a.jsxs)(e.p,{children:["First one is used as a ",(0,a.jsx)(e.em,{children:"public interface"})," to the solution, you just pass in the\npyramid itself. Second one is the recursive \u201calgorithm\u201d that finds the slide\ndown."]}),"\n",(0,a.jsxs)(e.p,{children:["It is a relatively simple solution\u2026 There's nothing to do at the bottom of the\npyramid, so we just return the value in the ",(0,a.jsx)(e.em,{children:"cell"}),". Otherwise we add it and try\nto slide down the available cells below the current row."]}),"\n",(0,a.jsx)(e.h3,{id:"time-complexity",children:"Time complexity"}),"\n",(0,a.jsx)(e.p,{children:"If you get the source code and run it yourself, it runs rather fine\u2026 I hope you\nare wondering about the time complexity of the proposed solution and, since it\nreally is a na\xefve solution, the time complexity is pretty bad. Let's find the\nworst case scenario."}),"\n",(0,a.jsx)(e.p,{children:"Let's start with the first overload:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:"public static int longestSlideDown(int[][] pyramid) {\n return longestSlideDown(pyramid, 0, 0);\n}\n"})}),"\n",(0,a.jsxs)(e.p,{children:["There's not much to do here, so we can safely say that the time complexity of\nthis function is bounded by ",(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"T"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"n"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"T(n)"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.13889em"},children:"T"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"n"}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})})]}),", where ",(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsx)(e.mrow,{children:(0,a.jsx)(e.mi,{children:"T"})}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"T"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"0.6833em"}}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.13889em"},children:"T"})]})})]})," is our second overload. This\ndoesn't tell us anything, so let's move on to the second overload where we are\ngoing to define the ",(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"T"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"n"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"T(n)"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.13889em"},children:"T"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"n"}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})})]})," function."]}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:"public static int longestSlideDown(int[][] pyramid, int row, int col) {\n if (row >= pyramid.length || col < 0 || col >= pyramid[row].length) {\n // BASE: We have gotten out of bounds, there's no reasonable value to\n // return, so we just return the \u2039MIN_VALUE\u203a to ensure that it cannot\n // be maximum.\n return Integer.MIN_VALUE;\n }\n\n if (row == pyramid.length - 1) {\n // BASE: Bottom of the pyramid, we just return the value, there's\n // nowhere to slide anymore.\n return pyramid[row][col];\n }\n\n // Otherwise we account for the current position and return maximum of the\n // available \u201cslides\u201d.\n return pyramid[row][col] + Math.max(\n longestSlideDown(pyramid, row + 1, col),\n longestSlideDown(pyramid, row + 1, col + 1));\n}\n"})}),"\n",(0,a.jsxs)(e.p,{children:["Fun fact is that the whole \u201calgorithm\u201d consists of just 2 ",(0,a.jsx)(e.code,{children:"return"})," statements\nand nothing else. Let's dissect them!"]}),"\n",(0,a.jsxs)(e.p,{children:["First ",(0,a.jsx)(e.code,{children:"return"})," statement is the base case, so it has a constant time complexity."]}),"\n",(0,a.jsxs)(e.p,{children:["Second one a bit tricky. We add two numbers together, which we'll consider as\nconstant, but for the right part of the expression we take maximum from the left\nand right paths. OK\u2026 So what happens? We evaluate the ",(0,a.jsx)(e.code,{children:"longestSlideDown"})," while\nchoosing the under and right both. They are separate computations though, so we\nare branching from each call of ",(0,a.jsx)(e.code,{children:"longestSlideDown"}),", unless it's a base case."]}),"\n",(0,a.jsx)(e.p,{children:"What does that mean for us then? 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mathnormal",children:"s"})]})]}),(0,a.jsxs)(e.span,{style:{top:"-2.25em"},children:[(0,a.jsx)(e.span,{className:"pstrut",style:{height:"3.008em"}}),(0,a.jsx)(e.span,{className:"mord",children:(0,a.jsx)(e.span,{className:"mord text",children:(0,a.jsx)(e.span,{className:"mord",children:",\xa0otherwise"})})})]})]}),(0,a.jsx)(e.span,{className:"vlist-s",children:"\u200b"})]}),(0,a.jsx)(e.span,{className:"vlist-r",children:(0,a.jsx)(e.span,{className:"vlist",style:{height:"1.19em"},children:(0,a.jsx)(e.span,{})})})]})})]})}),(0,a.jsx)(e.span,{className:"mclose nulldelimiter"})]})]})]})]})}),"\n",(0,a.jsx)(e.p,{children:"That looks rather easy to compute, isn't it? If you sum it up, you'll get:"}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"T"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"r"}),(0,a.jsx)(e.mi,{children:"o"}),(0,a.jsx)(e.mi,{children:"w"}),(0,a.jsx)(e.mi,{children:"s"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"}),(0,a.jsx)(e.mo,{children:"\u2208"}),(0,a.jsx)(e.mi,{mathvariant:"script",children:"O"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsxs)(e.msup,{children:[(0,a.jsx)(e.mn,{children:"2"}),(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"r"}),(0,a.jsx)(e.mi,{children:"o"}),(0,a.jsx)(e.mi,{children:"w"}),(0,a.jsx)(e.mi,{children:"s"})]})]}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"T(rows) \\in \\mathcal{O}(2^{rows})"})]})})}),(0,a.jsxs)(e.span,{className:"katex-html","aria-hidden":"true",children:[(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.13889em"},children:"T"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"ro"}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.02691em"},children:"w"}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"s"}),(0,a.jsx)(e.span,{className:"mclose",children:")"}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.2778em"}}),(0,a.jsx)(e.span,{className:"mrel",children:"\u2208"}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.2778em"}})]}),(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathcal",style:{marginRight:"0.02778em"},children:"O"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsxs)(e.span,{className:"mord",children:[(0,a.jsx)(e.span,{className:"mord",children:"2"}),(0,a.jsx)(e.span,{className:"msupsub",children:(0,a.jsx)(e.span,{className:"vlist-t",children:(0,a.jsx)(e.span,{className:"vlist-r",children:(0,a.jsx)(e.span,{className:"vlist",style:{height:"0.7144em"},children:(0,a.jsxs)(e.span,{style:{top:"-3.113em",marginRight:"0.05em"},children:[(0,a.jsx)(e.span,{className:"pstrut",style:{height:"2.7em"}}),(0,a.jsx)(e.span,{className:"sizing reset-size6 size3 mtight",children:(0,a.jsxs)(e.span,{className:"mord mtight",children:[(0,a.jsx)(e.span,{className:"mord mathnormal mtight",children:"ro"}),(0,a.jsx)(e.span,{className:"mord mathnormal mtight",style:{marginRight:"0.02691em"},children:"w"}),(0,a.jsx)(e.span,{className:"mord mathnormal mtight",children:"s"})]})})]})})})})})]}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})]})]})}),"\n",(0,a.jsx)(e.p,{children:"If you wonder why, I'll try to describe it intuitively:"}),"\n",(0,a.jsxs)(e.ol,{children:["\n",(0,a.jsxs)(e.li,{children:["In each call to ",(0,a.jsx)(e.code,{children:"longestSlideDown"})," we do some work in constant time,\nregardless of being in the base case. Those are the ",(0,a.jsx)(e.code,{children:"1"}),"s in both cases."]}),"\n",(0,a.jsxs)(e.li,{children:["If we are not in the base case, we move one row down ",(0,a.jsx)(e.strong,{children:"twice"}),". That's how we\nobtained ",(0,a.jsx)(e.code,{children:"2 *"})," and ",(0,a.jsx)(e.code,{children:"y + 1"})," in the ",(0,a.jsx)(e.em,{children:"otherwise"})," case."]}),"\n",(0,a.jsxs)(e.li,{children:["We move row-by-row, so we move down ",(0,a.jsx)(e.code,{children:"y"}),"-times and each call splits to two\nsubtrees."]}),"\n",(0,a.jsxs)(e.li,{children:["Overall, if we were to represent the calls as a tree, we would get a full\nbinary tree of height ",(0,a.jsx)(e.code,{children:"y"}),", in each node we do some work in constant time,\ntherefore we can just sum the ones."]}),"\n"]}),"\n",(0,a.jsx)(e.admonition,{type:"warning",children:(0,a.jsx)(e.p,{children:"It would've been more complicated to get an exact result. In the equation above\nwe are assuming that the width of the pyramid is bound by the height."})}),"\n",(0,a.jsxs)(e.p,{children:["Hopefully we can agree that this is not the best we can do. ","\ud83d\ude09"]}),"\n",(0,a.jsx)(e.h2,{id:"greedy-solution",children:"Greedy solution"}),"\n",(0,a.jsxs)(e.p,{children:["We will try to optimize it a bit. Let's start with a relatively simple ",(0,a.jsx)(e.em,{children:"greedy"}),"\napproach."]}),"\n",(0,a.jsx)(e.admonition,{title:"Greedy algorithms",type:"info",children:(0,a.jsxs)(e.p,{children:[(0,a.jsx)(e.em,{children:"Greedy algorithms"})," can be described as algorithms that decide the action on the\noptimal option at the moment."]})}),"\n",(0,a.jsx)(e.p,{children:"We can try to adjust the na\xefve solution. The most problematic part are the\nrecursive calls. Let's apply the greedy approach there:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:"public static int longestSlideDown(int[][] pyramid, int row, int col) {\n if (row == pyramid.length - 1) {\n // BASE: We're at the bottom\n return pyramid[row][col];\n }\n\n if (col + 1 >= pyramid[row + 1].length\n || pyramid[row + 1][col] > pyramid[row + 1][col + 1]) {\n // If we cannot go right or it's not feasible, we continue to the left.\n return pyramid[row][col] + longestSlideDown(pyramid, row + 1, col);\n }\n\n // Otherwise we just move to the right.\n return pyramid[row][col] + longestSlideDown(pyramid, row + 1, col + 1);\n}\n"})}),"\n",(0,a.jsxs)(e.p,{children:["OK, if we cannot go right ",(0,a.jsx)(e.strong,{children:"or"})," the right path adds smaller value to the sum,\nwe simply go left."]}),"\n",(0,a.jsx)(e.h3,{id:"time-complexity-1",children:"Time complexity"}),"\n",(0,a.jsxs)(e.p,{children:["We have switched from ",(0,a.jsx)(e.em,{children:"adding the maximum"})," to ",(0,a.jsx)(e.em,{children:"following the \u201cbigger\u201d path"}),", so\nwe improved the time complexity tremendously. We just go down the pyramid all\nthe way to the bottom. Therefore we are getting:"]}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{mathvariant:"script",children:"O"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"r"}),(0,a.jsx)(e.mi,{children:"o"}),(0,a.jsx)(e.mi,{children:"w"}),(0,a.jsx)(e.mi,{children:"s"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\mathcal{O}(rows)"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathcal",style:{marginRight:"0.02778em"},children:"O"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"ro"}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.02691em"},children:"w"}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"s"}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})})]})}),"\n",(0,a.jsx)(e.p,{children:"We have managed to convert our exponential solution into a linear one."}),"\n",(0,a.jsx)(e.h3,{id:"running-the-tests",children:"Running the tests"}),"\n",(0,a.jsx)(e.p,{children:"However, if we run the tests, we notice that the second test failed:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{children:"Test #1: passed\nTest #2: failed\n"})}),"\n",(0,a.jsxs)(e.p,{children:["What's going on? Well, we have improved the time complexity, but greedy\nalgorithms are not the ideal solution to ",(0,a.jsx)(e.strong,{children:"all"})," problems. In this case there\nmay be a solution that is bigger than the one found using the greedy algorithm."]}),"\n",(0,a.jsx)(e.p,{children:"Imagine the following pyramid:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{children:" 1\n 2 3\n 5 6 7\n 8 9 10 11\n99 13 14 15 16\n"})}),"\n",(0,a.jsx)(e.p,{children:"We start at the top:"}),"\n",(0,a.jsxs)(e.ol,{children:["\n",(0,a.jsxs)(e.li,{children:["Current cell: ",(0,a.jsx)(e.code,{children:"1"}),", we can choose from ",(0,a.jsx)(e.code,{children:"2"})," and ",(0,a.jsx)(e.code,{children:"3"}),", ",(0,a.jsx)(e.code,{children:"3"})," looks better, so we\nchoose it."]}),"\n",(0,a.jsxs)(e.li,{children:["Current cell: ",(0,a.jsx)(e.code,{children:"3"}),", we can choose from ",(0,a.jsx)(e.code,{children:"6"})," and ",(0,a.jsx)(e.code,{children:"7"}),", ",(0,a.jsx)(e.code,{children:"7"})," looks better, so we\nchoose it."]}),"\n",(0,a.jsxs)(e.li,{children:["Current cell: ",(0,a.jsx)(e.code,{children:"7"}),", we can choose from ",(0,a.jsx)(e.code,{children:"10"})," and ",(0,a.jsx)(e.code,{children:"11"}),", ",(0,a.jsx)(e.code,{children:"11"})," looks better, so we\nchoose it."]}),"\n",(0,a.jsxs)(e.li,{children:["Current cell: ",(0,a.jsx)(e.code,{children:"11"}),", we can choose from ",(0,a.jsx)(e.code,{children:"15"})," and ",(0,a.jsx)(e.code,{children:"16"}),", ",(0,a.jsx)(e.code,{children:"16"})," looks better, so\nwe choose it."]}),"\n"]}),"\n",(0,a.jsxs)(e.p,{children:["Our final sum is: ",(0,a.jsx)(e.code,{children:"1 + 3 + 7 + 11 + 16 = 38"}),", but in the bottom left cell we\nhave a ",(0,a.jsx)(e.code,{children:"99"})," that is bigger than our whole sum."]}),"\n",(0,a.jsx)(e.admonition,{type:"tip",children:(0,a.jsx)(e.p,{children:"Dijkstra's algorithm is a greedy algorithm too, try to think why it is correct."})}),"\n",(0,a.jsx)(e.h2,{id:"top-down-dp",children:"Top-down DP"}),"\n",(0,a.jsxs)(e.p,{children:[(0,a.jsx)(e.em,{children:"Top-down dynamic programming"})," is probably the most common approach, since (at\nleast looks like) is the easiest to implement. The whole point is avoiding the\nunnecessary computations that we have already done."]}),"\n",(0,a.jsxs)(e.p,{children:["In our case, we can use our na\xefve solution and put a ",(0,a.jsx)(e.em,{children:"cache"})," on top of it that\nwill make sure, we don't do unnecessary calculations."]}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:"// This \u201cstructure\u201d is required, since I have decided to use \u2039TreeMap\u203a which\n// requires the ordering on the keys. It represents one position in the pyramid.\nrecord Position(int row, int col) implements Comparable {\n public int compareTo(Position r) {\n if (row != r.row) {\n return Integer.valueOf(row).compareTo(r.row);\n }\n\n if (col != r.col) {\n return Integer.valueOf(col).compareTo(r.col);\n }\n\n return 0;\n }\n}\n\npublic static int longestSlideDown(\n int[][] pyramid,\n TreeMap cache,\n Position position) {\n int row = position.row;\n int col = position.col;\n\n if (row >= pyramid.length || col < 0 || col >= pyramid[row].length) {\n // BASE: out of bounds\n return Integer.MIN_VALUE;\n }\n\n if (row == pyramid.length - 1) {\n // BASE: bottom of the pyramid\n return pyramid[position.row][position.col];\n }\n\n if (!cache.containsKey(position)) {\n // We haven't computed the position yet, so we run the same \u201cformula\u201d as\n // in the na\xefve version \xbband\xab we put calculated slide into the cache.\n // Next time we want the slide down from given position, it will be just\n // retrieved from the cache.\n int slideDown = Math.max(\n longestSlideDown(pyramid, cache, new Position(row + 1, col)),\n longestSlideDown(pyramid, cache, new Position(row + 1, col + 1)));\n cache.put(position, pyramid[row][col] + slideDown);\n }\n\n return cache.get(position);\n}\n\npublic static int longestSlideDown(int[][] pyramid) {\n // At the beginning we need to create a cache and share it across the calls.\n TreeMap cache = new TreeMap<>();\n return longestSlideDown(pyramid, cache, new Position(0, 0));\n}\n"})}),"\n",(0,a.jsxs)(e.p,{children:["You have probably noticed that ",(0,a.jsx)(e.code,{children:"record Position"})," have appeared. Since we are\ncaching the already computed values, we need a \u201creasonable\u201d key. In this case we\nshare the cache only for one ",(0,a.jsx)(e.em,{children:"run"})," (i.e. pyramid) of the ",(0,a.jsx)(e.code,{children:"longestSlideDown"}),", so\nwe can cache just with the indices within the pyramid, i.e. the ",(0,a.jsx)(e.code,{children:"Position"}),"."]}),"\n",(0,a.jsx)(e.admonition,{title:"Record",type:"tip",children:(0,a.jsxs)(e.p,{children:[(0,a.jsx)(e.em,{children:"Record"})," is relatively new addition to the Java language. It is basically an\nimmutable structure with implicitly defined ",(0,a.jsx)(e.code,{children:".equals()"}),", ",(0,a.jsx)(e.code,{children:".hashCode()"}),",\n",(0,a.jsx)(e.code,{children:".toString()"})," and getters for the attributes."]})}),"\n",(0,a.jsxs)(e.p,{children:["Because of the choice of ",(0,a.jsx)(e.code,{children:"TreeMap"}),", we had to additionally define the ordering\non it."]}),"\n",(0,a.jsxs)(e.p,{children:["In the ",(0,a.jsx)(e.code,{children:"longestSlideDown"})," you can notice that the computation which used to be\nat the end of the na\xefve version above, is now wrapped in an ",(0,a.jsx)(e.code,{children:"if"})," statement that\nchecks for the presence of the position in the cache and computes the slide down\njust when it's needed."]}),"\n",(0,a.jsx)(e.h3,{id:"time-complexity-2",children:"Time complexity"}),"\n",(0,a.jsx)(e.p,{children:"If you think that evaluating time complexity for this approach is a bit more\ntricky, you are right. Keeping the cache in mind, it is not the easiest thing\nto do. However there are some observations that might help us figure this out:"}),"\n",(0,a.jsxs)(e.ol,{children:["\n",(0,a.jsx)(e.li,{children:"Slide down from each position is calculated only once."}),"\n",(0,a.jsx)(e.li,{children:"Once calculated, we use the result from the cache."}),"\n"]}),"\n",(0,a.jsxs)(e.p,{children:["Knowing this, we still cannot, at least easily, describe the time complexity of\nfinding the best slide down from a specific position, ",(0,a.jsx)(e.strong,{children:"but"})," we can bound it\nfrom above for the ",(0,a.jsx)(e.strong,{children:"whole"})," run from the top. Now the question is how we can do\nthat!"]}),"\n",(0,a.jsxs)(e.p,{children:["Overall we are doing the same things for almost",(0,a.jsx)(e.sup,{children:(0,a.jsx)(e.a,{href:"#user-content-fn-2",id:"user-content-fnref-2","data-footnote-ref":!0,"aria-describedby":"footnote-label",children:"2"})})," all of the positions within\nthe pyramid:"]}),"\n",(0,a.jsxs)(e.ol,{children:["\n",(0,a.jsxs)(e.li,{children:["\n",(0,a.jsx)(e.p,{children:"We calculate and store it (using the partial results stored in cache). This\nis done only once."}),"\n",(0,a.jsxs)(e.p,{children:["For each calculation we take 2 values from the cache and insert one value.\nBecause we have chosen ",(0,a.jsx)(e.code,{children:"TreeMap"}),", these 3 operations have logarithmic time\ncomplexity and therefore this step is equivalent to ",(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mn,{children:"3"}),(0,a.jsx)(e.mo,{children:"\u22c5"}),(0,a.jsxs)(e.msub,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"log"}),(0,a.jsx)(e.mo,{children:"\u2061"})]}),(0,a.jsx)(e.mn,{children:"2"})]}),(0,a.jsx)(e.mi,{children:"n"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"3 \\cdot 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will be interleaved with the next step, therefore it is easier to keep the\nretrievals in the following point."}),"\n",(0,a.jsx)(e.admonition,{type:"caution",children:(0,a.jsx)(e.p,{children:"You might have noticed it's still not that easy, cause we're not having full\ncache right from the beginning, but the sum of those logarithms cannot be\nexpressed in a nice way, so taking the upper bound, i.e. expecting the cache\nto be full at all times, is the best option for nice and readable complexity\nof the whole approach."})}),"\n",(0,a.jsxs)(e.p,{children:["Our final upper bound of this work is therefore ",(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsxs)(e.msub,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"log"}),(0,a.jsx)(e.mo,{children:"\u2061"})]}),(0,a.jsx)(e.mn,{children:"2"})]}),(0,a.jsx)(e.mi,{children:"n"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\log_2{n}"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"0.9386em",verticalAlign:"-0.2441em"}}),(0,a.jsxs)(e.span,{className:"mop",children:[(0,a.jsxs)(e.span,{className:"mop",children:["lo",(0,a.jsx)(e.span,{style:{marginRight:"0.01389em"},children:"g"})]}),(0,a.jsx)(e.span,{className:"msupsub",children:(0,a.jsxs)(e.span,{className:"vlist-t 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Same as in first point, but only twice, so we\nget ",(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mn,{children:"2"}),(0,a.jsx)(e.mo,{children:"\u22c5"}),(0,a.jsxs)(e.msub,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"log"}),(0,a.jsx)(e.mo,{children:"\u2061"})]}),(0,a.jsx)(e.mn,{children:"2"})]}),(0,a.jsx)(e.mi,{children:"n"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"2 \\cdot 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",(0,a.jsx)(e.code,{children:"if"})," condition."]})}),"\n"]}),"\n"]}),"\n",(0,a.jsx)(e.p,{children:"Okay, we have evaluated work done for each of the cells in the pyramid and now\nwe need to put it together."}),"\n",(0,a.jsx)(e.p,{children:"Let's split the time complexity of our solution into two operands:"}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{mathvariant:"script",children:"O"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"r"}),(0,a.jsx)(e.mo,{children:"+"}),(0,a.jsx)(e.mi,{children:"s"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\mathcal{O}(r + s)"})]})})}),(0,a.jsxs)(e.span,{className:"katex-html","aria-hidden":"true",children:[(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathcal",style:{marginRight:"0.02778em"},children:"O"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.02778em"},children:"r"}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.2222em"}}),(0,a.jsx)(e.span,{className:"mbin",children:"+"}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.2222em"}})]}),(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord 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",(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsx)(e.mrow,{children:(0,a.jsx)(e.mi,{children:"s"})}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"s"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"0.4306em"}}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"s"})]})})]})," will represent\nthe additional retrievals on top of the calculation."]}),"\n",(0,a.jsxs)(e.p,{children:["We calculate the values only ",(0,a.jsx)(e.strong,{children:"once"}),", therefore we can safely agree on:"]}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsx)(e.mtable,{rowspacing:"0.25em",columnalign:"right left",columnspacing:"0em",children:(0,a.jsxs)(e.mtr,{children:[(0,a.jsx)(e.mtd,{children:(0,a.jsx)(e.mstyle,{scriptlevel:"0",displaystyle:"true",children:(0,a.jsx)(e.mi,{children:"r"})})}),(0,a.jsx)(e.mtd,{children:(0,a.jsx)(e.mstyle,{scriptlevel:"0",displaystyle:"true",children:(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mrow,{}),(0,a.jsx)(e.mo,{children:"="}),(0,a.jsx)(e.mi,{children:"n"}),(0,a.jsx)(e.mo,{children:"\u22c5"}),(0,a.jsx)(e.mi,{children:"log"}),(0,a.jsx)(e.mo,{children:"\u2061"}),(0,a.jsx)(e.mi,{children:"n"})]})})})]})}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\begin{align*}\nr &= n \\cdot \\log{n} 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Key observation here is the fact that we have 2\nlookups on the tree in each of them ",(0,a.jsx)(e.strong,{children:"and"})," we do it twice, cause each cell has\nat most 2 parents:"]}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mtable,{rowspacing:"0.25em",columnalign:"right 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but\nit's better than the ",(0,a.jsx)(e.em,{children:"na\xefve"})," one."]}),"\n",(0,a.jsx)(e.h3,{id:"memory-complexity",children:"Memory complexity"}),"\n",(0,a.jsxs)(e.p,{children:["With this approach we need to talk about the memory complexity too, because we\nhave introduced cache. If you think that the memory complexity is linear to the\ninput, you are right. We start at the top and try to find each and every slide\ndown. At the end we get the final result for ",(0,a.jsx)(e.code,{children:"new Position(0, 0)"}),", so we need to\ncompute everything below."]}),"\n",(0,a.jsx)(e.p,{children:"That's how we obtain:"}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{mathvariant:"script",children:"O"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"n"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\mathcal{O}(n)"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathcal",style:{marginRight:"0.02778em"},children:"O"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"n"}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})})]})}),"\n",(0,a.jsxs)(e.p,{children:[(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsx)(e.mrow,{children:(0,a.jsx)(e.mi,{children:"n"})}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"n"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"0.4306em"}}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"n"})]})})]})," represents the total amount of cells in the pyramid, i.e."]}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsxs)(e.munderover,{children:[(0,a.jsx)(e.mo,{children:"\u2211"}),(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{children:"y"}),(0,a.jsx)(e.mo,{children:"="}),(0,a.jsx)(e.mn,{children:"0"})]}),(0,a.jsxs)(e.mrow,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"p"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"y"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"r"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"a"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"m"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"i"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"d"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"."}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"l"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"e"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"n"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"g"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"t"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"h"})]}),(0,a.jsx)(e.mo,{children:"\u2212"}),(0,a.jsx)(e.mn,{children:"1"})]})]}),(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"p"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"y"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"r"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"a"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"m"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"i"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"d"})]}),(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mo,{fence:"true",children:"["}),(0,a.jsx)(e.mi,{children:"y"}),(0,a.jsx)(e.mo,{fence:"true",children:"]"})]}),(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"."}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"l"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"e"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"n"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"g"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"t"}),(0,a.jsx)(e.mi,{mathvariant:"monospace",children:"h"})]})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\sum_{y=0}^{\\mathtt{pyramid.length} - 1} \\mathtt{pyramid}\\left[y\\right]\\mathtt{.length}"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"3.2709em",verticalAlign:"-1.4032em"}}),(0,a.jsx)(e.span,{className:"mop op-limits",children:(0,a.jsxs)(e.span,{className:"vlist-t vlist-t2",children:[(0,a.jsxs)(e.span,{className:"vlist-r",children:[(0,a.jsxs)(e.span,{className:"vlist",style:{height:"1.8677em"},children:[(0,a.jsxs)(e.span,{style:{top:"-1.8829em",marginLeft:"0em"},children:[(0,a.jsx)(e.span,{className:"pstrut",style:{height:"3.05em"}}),(0,a.jsx)(e.span,{className:"sizing reset-size6 size3 mtight",children:(0,a.jsxs)(e.span,{className:"mord mtight",children:[(0,a.jsx)(e.span,{className:"mord mathnormal mtight",style:{marginRight:"0.03588em"},children:"y"}),(0,a.jsx)(e.span,{className:"mrel mtight",children:"="}),(0,a.jsx)(e.span,{className:"mord mtight",children:"0"})]})})]}),(0,a.jsxs)(e.span,{style:{top:"-3.05em"},children:[(0,a.jsx)(e.span,{className:"pstrut",style:{height:"3.05em"}}),(0,a.jsx)(e.span,{children:(0,a.jsx)(e.span,{className:"mop op-symbol large-op",children:"\u2211"})})]}),(0,a.jsxs)(e.span,{style:{top:"-4.3666em",marginLeft:"0em"},children:[(0,a.jsx)(e.span,{className:"pstrut",style:{height:"3.05em"}}),(0,a.jsx)(e.span,{className:"sizing reset-size6 size3 mtight",children:(0,a.jsxs)(e.span,{className:"mord mtight",children:[(0,a.jsx)(e.span,{className:"mord mtight",children:(0,a.jsx)(e.span,{className:"mord mathtt mtight",children:"pyramid.length"})}),(0,a.jsx)(e.span,{className:"mbin mtight",children:"\u2212"}),(0,a.jsx)(e.span,{className:"mord mtight",children:"1"})]})})]})]}),(0,a.jsx)(e.span,{className:"vlist-s",children:"\u200b"})]}),(0,a.jsx)(e.span,{className:"vlist-r",children:(0,a.jsx)(e.span,{className:"vlist",style:{height:"1.4032em"},children:(0,a.jsx)(e.span,{})})})]})}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.1667em"}}),(0,a.jsx)(e.span,{className:"mord",children:(0,a.jsx)(e.span,{className:"mord mathtt",children:"pyramid"})}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.1667em"}}),(0,a.jsxs)(e.span,{className:"minner",children:[(0,a.jsx)(e.span,{className:"mopen delimcenter",style:{top:"0em"},children:"["}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.03588em"},children:"y"}),(0,a.jsx)(e.span,{className:"mclose delimcenter",style:{top:"0em"},children:"]"})]}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.1667em"}}),(0,a.jsx)(e.span,{className:"mord",children:(0,a.jsx)(e.span,{className:"mord mathtt",children:".length"})})]})})]})}),"\n",(0,a.jsx)(e.admonition,{type:"caution",children:(0,a.jsxs)(e.p,{children:["If you're wondering whether it's correct because of the second ",(0,a.jsx)(e.code,{children:"if"})," in our\nfunction, your guess is right. However we are expressing the complexity in the\nBachmann-Landau notation, so we care about the ",(0,a.jsx)(e.strong,{children:"upper bound"}),", not the exact\nnumber."]})}),"\n",(0,a.jsxs)(e.admonition,{title:"Can this be optimized?",type:"tip",children:[(0,a.jsx)(e.p,{children:"Yes, it can! Try to think about a way, how can you minimize the memory\ncomplexity of this approach. I'll give you a hint:"}),(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{mathvariant:"script",children:"O"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"r"}),(0,a.jsx)(e.mi,{children:"o"}),(0,a.jsx)(e.mi,{children:"w"}),(0,a.jsx)(e.mi,{children:"s"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\mathcal{O}(rows)"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathcal",style:{marginRight:"0.02778em"},children:"O"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"ro"}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.02691em"},children:"w"}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"s"}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})})]})})]}),"\n",(0,a.jsx)(e.h2,{id:"bottom-up-dp",children:"Bottom-up DP"}),"\n",(0,a.jsxs)(e.p,{children:["If you try to think in depth about the top-down DP solution, you might notice\nthat the ",(0,a.jsx)(e.em,{children:"core"})," of it stands on caching the calculations that have been already\ndone on the lower \u201clevels\u201d of the pyramid. Our bottom-up implementation will be\nusing this fact!"]}),"\n",(0,a.jsxs)(e.admonition,{type:"tip",children:[(0,a.jsxs)(e.p,{children:["As I have said in the ",(0,a.jsx)(e.em,{children:"top-down DP"})," section, it is the easiest way to implement\nDP (unless the cached function has complicated parameters, in that case it might\nget messy)."]}),(0,a.jsx)(e.p,{children:"Bottom-up dynamic programming can be more effective, but may be more complicated\nto implement right from the beginning."})]}),"\n",(0,a.jsx)(e.p,{children:"Let's see how we can implement it:"}),"\n",(0,a.jsx)(e.pre,{children:(0,a.jsx)(e.code,{className:"language-java",children:"public static int longestSlideDown(int[][] pyramid) {\n // In the beginning we declare new array. At this point it is easier to just\n // work with the one dimension, i.e. just allocating the space for the rows.\n int[][] slideDowns = new int[pyramid.length][];\n\n // Bottom row gets just copied, there's nothing else to do\u2026 It's the base\n // case.\n slideDowns[pyramid.length - 1] = Arrays.copyOf(pyramid[pyramid.length - 1],\n pyramid[pyramid.length - 1].length);\n\n // Then we need to propagate the found slide downs for each of the levels\n // above.\n for (int y = pyramid.length - 2; y >= 0; --y) {\n // We start by copying the values lying in the row we're processing.\n // They get included in the final sum and we need to allocate the space\n // for the precalculated slide downs anyways.\n int[] row = Arrays.copyOf(pyramid[y], pyramid[y].length);\n\n // At this we just need to \u201cfetch\u201d the partial results from \u201cneighbours\u201d\n for (int x = 0; x < row.length; ++x) {\n // We look under our position, since we expect the rows to get\n // shorter, we can safely assume such position exists.\n int under = slideDowns[y + 1][x];\n\n // Then we have a look to the right, such position doesn't have to\n // exist, e.g. on the right edge, so we validate the index, and if\n // it doesn't exist, we just assign minimum of the \u2039int\u203a which makes\n // sure that it doesn't get picked in the \u2039Math.max()\u203a call.\n int toRight = x + 1 < slideDowns[y + 1].length\n ? slideDowns[y + 1][x + 1]\n : Integer.MIN_VALUE;\n\n // Finally we add the best choice at this point.\n row[x] += Math.max(under, toRight);\n }\n\n // And save the row we've just calculated partial results for to the\n // \u201ctable\u201d.\n slideDowns[y] = row;\n }\n\n // At the end we can find our seeked slide down at the top cell.\n return slideDowns[0][0];\n}\n"})}),"\n",(0,a.jsx)(e.p,{children:"I've tried to explain the code as much as possible within the comments, since it\nmight be more beneficial to see right next to the \u201coffending\u201d lines."}),"\n",(0,a.jsxs)(e.p,{children:["As you can see, in this approach we go from the other side",(0,a.jsx)(e.sup,{children:(0,a.jsx)(e.a,{href:"#user-content-fn-3",id:"user-content-fnref-3","data-footnote-ref":!0,"aria-describedby":"footnote-label",children:"3"})}),", the bottom of\nthe pyramid and propagate the partial results up."]}),"\n",(0,a.jsxs)(e.admonition,{type:"info",children:[(0,a.jsxs)(e.mdxAdmonitionTitle,{children:["How is this different from the ",(0,a.jsx)(e.em,{children:"greedy"})," solution???"]}),(0,a.jsxs)(e.p,{children:["If you try to compare them, you might find a very noticable difference. The\ngreedy approach is going from the top to the bottom without ",(0,a.jsx)(e.strong,{children:"any"})," knowledge of\nwhat's going on below. On the other hand, bottom-up DP is going from the bottom\n(",(0,a.jsx)(e.em,{children:"DUH\u2026"}),") and ",(0,a.jsx)(e.strong,{children:"propagates"})," the partial results to the top. The propagation is\nwhat makes sure that at the top I don't choose the best ",(0,a.jsx)(e.strong,{children:"local"})," choice, but\nthe best ",(0,a.jsx)(e.strong,{children:"overall"})," result I can achieve."]})]}),"\n",(0,a.jsx)(e.h3,{id:"time-complexity-3",children:"Time complexity"}),"\n",(0,a.jsx)(e.p,{children:"Time complexity of this solution is rather simple. We allocate an array for the\nrows and then for each row, we copy it and adjust the partial results. Doing\nthis we get:"}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{mathvariant:"script",children:"O"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"r"}),(0,a.jsx)(e.mi,{children:"o"}),(0,a.jsx)(e.mi,{children:"w"}),(0,a.jsx)(e.mi,{children:"s"}),(0,a.jsx)(e.mo,{children:"+"}),(0,a.jsx)(e.mn,{children:"2"}),(0,a.jsx)(e.mi,{children:"n"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\mathcal{O}(rows + 2n)"})]})})}),(0,a.jsxs)(e.span,{className:"katex-html","aria-hidden":"true",children:[(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathcal",style:{marginRight:"0.02778em"},children:"O"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"ro"}),(0,a.jsx)(e.span,{className:"mord mathnormal",style:{marginRight:"0.02691em"},children:"w"}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"s"}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.2222em"}}),(0,a.jsx)(e.span,{className:"mbin",children:"+"}),(0,a.jsx)(e.span,{className:"mspace",style:{marginRight:"0.2222em"}})]}),(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord",children:"2"}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"n"}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})]})]})}),"\n",(0,a.jsx)(e.p,{children:"Of course, this is an upper bound, since we iterate through the bottom row only\nonce."}),"\n",(0,a.jsx)(e.h3,{id:"memory-complexity-1",children:"Memory complexity"}),"\n",(0,a.jsxs)(e.p,{children:["We're allocating an array for the pyramid ",(0,a.jsx)(e.strong,{children:"again"})," for our partial results, so\nwe get:"]}),"\n",(0,a.jsx)(e.span,{className:"katex-display",children:(0,a.jsxs)(e.span,{className:"katex",children:[(0,a.jsx)(e.span,{className:"katex-mathml",children:(0,a.jsx)(e.math,{xmlns:"http://www.w3.org/1998/Math/MathML",display:"block",children:(0,a.jsxs)(e.semantics,{children:[(0,a.jsxs)(e.mrow,{children:[(0,a.jsx)(e.mi,{mathvariant:"script",children:"O"}),(0,a.jsx)(e.mo,{stretchy:"false",children:"("}),(0,a.jsx)(e.mi,{children:"n"}),(0,a.jsx)(e.mo,{stretchy:"false",children:")"})]}),(0,a.jsx)(e.annotation,{encoding:"application/x-tex",children:"\\mathcal{O}(n)"})]})})}),(0,a.jsx)(e.span,{className:"katex-html","aria-hidden":"true",children:(0,a.jsxs)(e.span,{className:"base",children:[(0,a.jsx)(e.span,{className:"strut",style:{height:"1em",verticalAlign:"-0.25em"}}),(0,a.jsx)(e.span,{className:"mord mathcal",style:{marginRight:"0.02778em"},children:"O"}),(0,a.jsx)(e.span,{className:"mopen",children:"("}),(0,a.jsx)(e.span,{className:"mord mathnormal",children:"n"}),(0,a.jsx)(e.span,{className:"mclose",children:")"})]})})]})}),"\n",(0,a.jsxs)(e.admonition,{type:"tip",children:[(0,a.jsx)(e.p,{children:"If we were writing this in C++ or Rust, we could've avoided that, but not\nreally."}),(0,a.jsxs)(e.p,{children:["C++ would allow us to ",(0,a.jsx)(e.strong,{children:"copy"})," the pyramid rightaway into the parameter, so we\nwould be able to directly change it. However it's still a copy, even though we\ndon't need to allocate anything ourselves. It's just implicitly done for us."]}),(0,a.jsxs)(e.p,{children:["Rust is more funny in this case. If the pyramids weren't used after the call of\n",(0,a.jsx)(e.code,{children:"longest_slide_down"}),", it would simply ",(0,a.jsx)(e.strong,{children:"move"})," them into the functions. If they\nwere used afterwards, the compiler would force you to either borrow it, or\n",(0,a.jsx)(e.em,{children:"clone-and-move"})," for the function."]}),(0,a.jsx)(e.hr,{}),(0,a.jsxs)(e.p,{children:["Since we're doing it in Java, we get a reference to the ",(0,a.jsx)(e.em,{children:"original"})," array and we\ncan't do whatever we want with it."]})]}),"\n",(0,a.jsx)(e.h2,{id:"summary",children:"Summary"}),"\n",(0,a.jsxs)(e.p,{children:["And we've finally reached the end. We have seen 4 different \u201csolutions\u201d",(0,a.jsx)(e.sup,{children:(0,a.jsx)(e.a,{href:"#user-content-fn-4",id:"user-content-fnref-4","data-footnote-ref":!0,"aria-describedby":"footnote-label",children:"4"})})," of\nthe same problem using different approaches. Different approaches follow the\norder in which you might come up with them, each approach influences its\nsuccessor and represents the way we can enhance the existing implementation."]}),"\n",(0,a.jsx)(e.hr,{}),"\n",(0,a.jsx)(e.admonition,{title:"source",type:"info",children:(0,a.jsxs)(e.p,{children:["You can find source code referenced in the text\n",(0,a.jsx)(e.a,{href:"pathname:///files/algorithms/recursion/pyramid-slide-down.tar.gz",children:"here"}),"."]})}),"\n",(0,a.jsxs)(e.section,{"data-footnotes":!0,className:"footnotes",children:[(0,a.jsx)(e.h2,{className:"sr-only",id:"footnote-label",children:"Footnotes"}),"\n",(0,a.jsxs)(e.ol,{children:["\n",(0,a.jsxs)(e.li,{id:"user-content-fn-1",children:["\n",(0,a.jsxs)(e.p,{children:["cause why not, right!? ",(0,a.jsx)(e.a,{href:"#user-content-fnref-1","data-footnote-backref":"","aria-label":"Back to reference 1",className:"data-footnote-backref",children:"\u21a9"})]}),"\n"]}),"\n",(0,a.jsxs)(e.li,{id:"user-content-fn-2",children:["\n",(0,a.jsxs)(e.p,{children:["except the bottom row ",(0,a.jsx)(e.a,{href:"#user-content-fnref-2","data-footnote-backref":"","aria-label":"Back to reference 2",className:"data-footnote-backref",children:"\u21a9"})]}),"\n"]}),"\n",(0,a.jsxs)(e.li,{id:"user-content-fn-3",children:["\n",(0,a.jsxs)(e.p,{children:["definitely not an RHCP reference ","\ud83d\ude09 ",(0,a.jsx)(e.a,{href:"#user-content-fnref-3","data-footnote-backref":"","aria-label":"Back to reference 3",className:"data-footnote-backref",children:"\u21a9"})]}),"\n"]}),"\n",(0,a.jsxs)(e.li,{id:"user-content-fn-4",children:["\n",(0,a.jsxs)(e.p,{children:["one was not correct, thus the quotes ",(0,a.jsx)(e.a,{href:"#user-content-fnref-4","data-footnote-backref":"","aria-label":"Back to reference 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Till then changes can be reviewed\non ",(0,r.jsx)(n.em,{children:"Merge Request"})," and additional changes may be made based on the reviews. Once\nthe changes satisfy requirements, the merge request is merged."]}),"\n",(0,r.jsx)(n.h2,{id:"tutorial",children:"Tutorial"}),"\n",(0,r.jsxs)(n.blockquote,{children:["\n",(0,r.jsxs)(n.p,{children:["Use this tutorial only for bonus assignments ",(0,r.jsx)(n.strong,{children:"made by your tutors"})," or in case\nyou need to make up for the absence."]}),"\n"]}),"\n",(0,r.jsx)(n.h3,{id:"step-1---starting-from-the-clean-repository",children:"Step #1 - Starting from the clean repository"}),"\n",(0,r.jsxs)(n.p,{children:["In your repository (either locally or on aisa) type ",(0,r.jsx)(n.code,{children:"git status"})," and check if your\nrepository is clean and you are present on the main branch (",(0,r.jsx)(n.code,{children:"master"}),", ",(0,r.jsx)(n.code,{children:"main"})," or\n",(0,r.jsx)(n.code,{children:"trunk"}),"). 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For example\nif you are working on 3rd seminar, you can do so by:"}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{children:"aisa$ wget https://www.fi.muni.cz/pb071/seminars/seminar-03/pb071-seminar-03.zip\naisa$ unzip pb071-seminar-03.zip\n# Now you should have directory 'seminar-03'.\naisa$ rm pb071-seminar-03.zip\naisa$ cd seminar-03\n# You can work on the assignment.\n"})}),"\n",(0,r.jsx)(n.h3,{id:"step-4---commit-and-upload-the-changes-to-gitlab",children:"Step #4 - Commit and upload the changes to GitLab"}),"\n",(0,r.jsxs)(n.p,{children:["The same way you ",(0,r.jsx)(n.em,{children:"add"})," and ",(0,r.jsx)(n.em,{children:"commit"})," files for the homework assignments, you do for\nthe seminar."]}),"\n",(0,r.jsxs)(n.p,{children:["Now you can upload the changes to GitLab. ",(0,r.jsx)(n.code,{children:"git push"})," is not enough, since repository\non GitLab does not know your new branch. You can solve this by adding arguments:"]}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{children:"aisa$ git push origin BRANCH\n...\nremote: To create a merge request for BRANCH, visit:\nremote: https://gitlab.fi.muni.cz/login/pb071/merge_requests/new?merge_request%5Bsource_branch%5D=BRANCH\n...\n"})}),"\n",(0,r.jsx)(n.p,{children:"In the output you should have a link for creating a merge request. If you see this\nlink, open it and skip next step."}),"\n",(0,r.jsx)(n.h3,{id:"step-5---creating-a-merge-request-manually",children:"Step #5 - Creating a merge request manually"}),"\n",(0,r.jsxs)(n.ol,{children:["\n",(0,r.jsx)(n.li,{children:"Open your repository on GitLab."}),"\n",(0,r.jsxs)(n.li,{children:["On the left panel click on ",(0,r.jsx)(n.em,{children:"Merge Requests"}),"."]}),"\n",(0,r.jsxs)(n.li,{children:["Click on ",(0,r.jsx)(n.em,{children:"New Merge Request"}),"."]}),"\n",(0,r.jsxs)(n.li,{children:["In ",(0,r.jsx)(n.em,{children:"Source branch"})," select ",(0,r.jsx)(n.code,{children:"login/pb071"})," and ",(0,r.jsx)(n.code,{children:"BRANCH"}),", which you created."]}),"\n",(0,r.jsxs)(n.li,{children:["In ",(0,r.jsx)(n.em,{children:"Target branch"})," select ",(0,r.jsx)(n.code,{children:"login/pb071"})," and your default branch you have seen\nin the output of the first command. (most likely ",(0,r.jsx)(n.code,{children:"master"}),")"]}),"\n",(0,r.jsxs)(n.li,{children:["Click on ",(0,r.jsx)(n.em,{children:"Compare branches and continue"}),"."]}),"\n"]}),"\n",(0,r.jsx)(n.h3,{id:"step-6---set-assignees",children:"Step #6 - Set assignees"}),"\n",(0,r.jsxs)(n.p,{children:["On the page that is opened, please check at the top that you are creating merge\nrequest ",(0,r.jsx)(n.strong,{children:"from"})," your new branch ",(0,r.jsx)(n.strong,{children:"to"})," your default branch (one of ",(0,r.jsx)(n.code,{children:"master"}),", ",(0,r.jsx)(n.code,{children:"main"}),"\nor ",(0,r.jsx)(n.code,{children:"trunk"}),")."]}),"\n",(0,r.jsxs)(n.p,{children:["Then in the field ",(0,r.jsx)(n.em,{children:"Assignees"})," set your tutors based on the seminar group. You can\nuse login for a quick look up."]}),"\n",(0,r.jsxs)(n.p,{children:["In the end click on ",(0,r.jsx)(n.em,{children:"Submit merge request"}),"."]}),"\n",(0,r.jsx)(n.h3,{id:"step-7---return-to-default-branch",children:"Step #7 - Return to default branch"}),"\n",(0,r.jsx)(n.p,{children:"Homework assignments can be submitted only from branches specified in the rules\nfor the course. Because of that, before you do anything else, you should switch\nback to your default branch."}),"\n",(0,r.jsxs)(n.p,{children:["First of all, same as in step #1, check that your repository is clean with ",(0,r.jsx)(n.code,{children:"git status"}),".\nFor the sake of safety, do not continue without clean repository. Then with command\n",(0,r.jsx)(n.code,{children:"git checkout BRANCH"})," switch to your default branch ",(0,r.jsx)(n.code,{children:"BRANCH"}),"."]}),"\n",(0,r.jsxs)(n.p,{children:["If you do not know which branch is your default, try ",(0,r.jsx)(n.code,{children:"git branch"})," that outputs all branches in your repository. Default branch is typically ",(0,r.jsx)(n.code,{children:"master"}),", but can\nbe ",(0,r.jsx)(n.code,{children:"main"})," or ",(0,r.jsx)(n.code,{children:"trunk"}),"."]}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{children:"aisa$ git status\n# Check if repository is clean\n\n# If you know, what is your default branch, you can skip next command.\naisa$ git branch\n# Find the default branch in the list; should be one of the `master`, `main` or\n# `trunk` and you should not have more than one of those.\n# In case the list clears the terminal and you cannot see shell prompt, you can\n# press `q` to quit the pager.\n\naisa$ git checkout master\n"})}),"\n",(0,r.jsx)(n.hr,{}),"\n",(0,r.jsxs)(n.p,{children:["Adapted from: ",(0,r.jsx)(n.a,{href:"https://www.fi.muni.cz/~xlacko1/pb071/mr.html",children:"https://www.fi.muni.cz/~xlacko1/pb071/mr.html"})]})]})}function d(e={}){const{wrapper:n}={...(0,s.a)(),...e.components};return n?(0,r.jsx)(n,{...e,children:(0,r.jsx)(l,{...e})}):l(e)}},11151:(e,n,t)=>{t.d(n,{Z:()=>a,a:()=>i});var r=t(67294);const s={},o=r.createContext(s);function i(e){const n=r.useContext(o);return r.useMemo((function(){return"function"==typeof e?e(n):{...n,...e}}),[n,e])}function a(e){let n;return n=e.disableParentContext?"function"==typeof e.components?e.components(s):e.components||s:i(e.components),r.createElement(o.Provider,{value:n},e.children)}}}]); \ No newline at end of file +"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[59],{51456:(e,n,t)=>{t.r(n),t.d(n,{assets:()=>c,contentTitle:()=>i,default:()=>d,frontMatter:()=>o,metadata:()=>a,toc:()=>h});var r=t(85893),s=t(11151);const o={title:"Submitting merge requests"},i="Submitting merge requests for review",a={id:"mr",title:"Submitting merge requests",description:"This tutorial aims to show you how to follow basic git workflow and submit changes",source:"@site/c/mr.md",sourceDirName:".",slug:"/mr",permalink:"/c/mr",draft:!1,unlisted:!1,editUrl:"https://github.com/mfocko/blog/tree/main/c/mr.md",tags:[],version:"current",lastUpdatedAt:1703373170,formattedLastUpdatedAt:"Dec 23, 2023",frontMatter:{title:"Submitting merge requests"},sidebar:"autogeneratedBar",previous:{title:"Practice exam C",permalink:"/c/pexam/cams"}},c={},h=[{value:"Tutorial",id:"tutorial",level:2},{value:"Step #1 - Starting from the clean repository",id:"step-1---starting-from-the-clean-repository",level:3},{value:"Step #2 - Create new branch",id:"step-2---create-new-branch",level:3},{value:"Step #3 - Do the assignment",id:"step-3---do-the-assignment",level:3},{value:"Step #4 - Commit and upload the changes to GitLab",id:"step-4---commit-and-upload-the-changes-to-gitlab",level:3},{value:"Step #5 - Creating a merge request manually",id:"step-5---creating-a-merge-request-manually",level:3},{value:"Step #6 - Set assignees",id:"step-6---set-assignees",level:3},{value:"Step #7 - Return to default branch",id:"step-7---return-to-default-branch",level:3}];function l(e){const n={a:"a",blockquote:"blockquote",code:"code",em:"em",h1:"h1",h2:"h2",h3:"h3",hr:"hr",li:"li",ol:"ol",p:"p",pre:"pre",strong:"strong",...(0,s.a)(),...e.components};return(0,r.jsxs)(r.Fragment,{children:[(0,r.jsx)(n.h1,{id:"submitting-merge-requests-for-review",children:"Submitting merge requests for review"}),"\n",(0,r.jsxs)(n.p,{children:["This tutorial aims to show you how to follow basic git workflow and submit changes\nthrough ",(0,r.jsx)(n.em,{children:"Merge Requests"})," for review."]}),"\n",(0,r.jsxs)(n.p,{children:["The rudimentary idea behind aims for changes to be present on a separate branch\nthat is supposedly ",(0,r.jsx)(n.em,{children:"merged"})," into the default branch. Till then changes can be reviewed\non ",(0,r.jsx)(n.em,{children:"Merge Request"})," and additional changes may be made based on the reviews. Once\nthe changes satisfy requirements, the merge request is merged."]}),"\n",(0,r.jsx)(n.h2,{id:"tutorial",children:"Tutorial"}),"\n",(0,r.jsxs)(n.blockquote,{children:["\n",(0,r.jsxs)(n.p,{children:["Use this tutorial only for bonus assignments ",(0,r.jsx)(n.strong,{children:"made by your tutors"})," or in case\nyou need to make up for the absence."]}),"\n"]}),"\n",(0,r.jsx)(n.h3,{id:"step-1---starting-from-the-clean-repository",children:"Step #1 - Starting from the clean repository"}),"\n",(0,r.jsxs)(n.p,{children:["In your repository (either locally or on aisa) type ",(0,r.jsx)(n.code,{children:"git status"})," and check if your\nrepository is clean and you are present on the main branch (",(0,r.jsx)(n.code,{children:"master"}),", ",(0,r.jsx)(n.code,{children:"main"})," or\n",(0,r.jsx)(n.code,{children:"trunk"}),"). If you do not know what your default branch is, it is probably ",(0,r.jsx)(n.code,{children:"master"}),"\nand you should not be on any other branch."]}),"\n",(0,r.jsx)(n.p,{children:"Output of the command should look like this:"}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{children:"aisa$ git status\nOn branch master # Or main or trunk.\nYour branch is up to date with 'origin/master'.\n\nnothing to commit, working tree clean\n"})}),"\n",(0,r.jsxs)(n.blockquote,{children:["\n",(0,r.jsxs)(n.p,{children:["In case you are on different branch or there are uncommitted changes,\n",(0,r.jsx)(n.strong,{children:"do not continue!!!"})," Clean your repository (commit the changes or discard\nthem), before you continue."]}),"\n"]}),"\n",(0,r.jsx)(n.h3,{id:"step-2---create-new-branch",children:"Step #2 - Create new branch"}),"\n",(0,r.jsx)(n.p,{children:"In your repository write command:"}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{children:"aisa$ git checkout -b BRANCH\nSwitched to a new branch 'BRANCH'\n"})}),"\n",(0,r.jsxs)(n.p,{children:["Instead of ",(0,r.jsx)(n.code,{children:"BRANCH"})," use some reasonable name for the branch. For example if you\nare working on the seminar from 3rd week, name the branch ",(0,r.jsx)(n.code,{children:"seminar-03"}),"."]}),"\n",(0,r.jsx)(n.h3,{id:"step-3---do-the-assignment",children:"Step #3 - Do the assignment"}),"\n",(0,r.jsx)(n.p,{children:"Download the skeleton for the seminar assignment, extract and program. For example\nif you are working on 3rd seminar, you can do so by:"}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{children:"aisa$ wget https://www.fi.muni.cz/pb071/seminars/seminar-03/pb071-seminar-03.zip\naisa$ unzip pb071-seminar-03.zip\n# Now you should have directory 'seminar-03'.\naisa$ rm pb071-seminar-03.zip\naisa$ cd seminar-03\n# You can work on the assignment.\n"})}),"\n",(0,r.jsx)(n.h3,{id:"step-4---commit-and-upload-the-changes-to-gitlab",children:"Step #4 - Commit and upload the changes to GitLab"}),"\n",(0,r.jsxs)(n.p,{children:["The same way you ",(0,r.jsx)(n.em,{children:"add"})," and ",(0,r.jsx)(n.em,{children:"commit"})," files for the homework assignments, you do for\nthe seminar."]}),"\n",(0,r.jsxs)(n.p,{children:["Now you can upload the changes to GitLab. ",(0,r.jsx)(n.code,{children:"git push"})," is not enough, since repository\non GitLab does not know your new branch. You can solve this by adding arguments:"]}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{children:"aisa$ git push origin BRANCH\n...\nremote: To create a merge request for BRANCH, visit:\nremote: https://gitlab.fi.muni.cz/login/pb071/merge_requests/new?merge_request%5Bsource_branch%5D=BRANCH\n...\n"})}),"\n",(0,r.jsx)(n.p,{children:"In the output you should have a link for creating a merge request. If you see this\nlink, open it and skip next step."}),"\n",(0,r.jsx)(n.h3,{id:"step-5---creating-a-merge-request-manually",children:"Step #5 - Creating a merge request manually"}),"\n",(0,r.jsxs)(n.ol,{children:["\n",(0,r.jsx)(n.li,{children:"Open your repository on GitLab."}),"\n",(0,r.jsxs)(n.li,{children:["On the left panel click on ",(0,r.jsx)(n.em,{children:"Merge Requests"}),"."]}),"\n",(0,r.jsxs)(n.li,{children:["Click on ",(0,r.jsx)(n.em,{children:"New Merge Request"}),"."]}),"\n",(0,r.jsxs)(n.li,{children:["In ",(0,r.jsx)(n.em,{children:"Source branch"})," select ",(0,r.jsx)(n.code,{children:"login/pb071"})," and ",(0,r.jsx)(n.code,{children:"BRANCH"}),", which you created."]}),"\n",(0,r.jsxs)(n.li,{children:["In ",(0,r.jsx)(n.em,{children:"Target branch"})," select ",(0,r.jsx)(n.code,{children:"login/pb071"})," and your default branch you have seen\nin the output of the first command. (most likely ",(0,r.jsx)(n.code,{children:"master"}),")"]}),"\n",(0,r.jsxs)(n.li,{children:["Click on ",(0,r.jsx)(n.em,{children:"Compare branches and continue"}),"."]}),"\n"]}),"\n",(0,r.jsx)(n.h3,{id:"step-6---set-assignees",children:"Step #6 - Set assignees"}),"\n",(0,r.jsxs)(n.p,{children:["On the page that is opened, please check at the top that you are creating merge\nrequest ",(0,r.jsx)(n.strong,{children:"from"})," your new branch ",(0,r.jsx)(n.strong,{children:"to"})," your default branch (one of ",(0,r.jsx)(n.code,{children:"master"}),", ",(0,r.jsx)(n.code,{children:"main"}),"\nor ",(0,r.jsx)(n.code,{children:"trunk"}),")."]}),"\n",(0,r.jsxs)(n.p,{children:["Then in the field ",(0,r.jsx)(n.em,{children:"Assignees"})," set your tutors based on the seminar group. You can\nuse login for a quick look up."]}),"\n",(0,r.jsxs)(n.p,{children:["In the end click on ",(0,r.jsx)(n.em,{children:"Submit merge request"}),"."]}),"\n",(0,r.jsx)(n.h3,{id:"step-7---return-to-default-branch",children:"Step #7 - Return to default branch"}),"\n",(0,r.jsx)(n.p,{children:"Homework assignments can be submitted only from branches specified in the rules\nfor the course. Because of that, before you do anything else, you should switch\nback to your default branch."}),"\n",(0,r.jsxs)(n.p,{children:["First of all, same as in step #1, check that your repository is clean with ",(0,r.jsx)(n.code,{children:"git status"}),".\nFor the sake of safety, do not continue without clean repository. Then with command\n",(0,r.jsx)(n.code,{children:"git checkout BRANCH"})," switch to your default branch ",(0,r.jsx)(n.code,{children:"BRANCH"}),"."]}),"\n",(0,r.jsxs)(n.p,{children:["If you do not know which branch is your default, try ",(0,r.jsx)(n.code,{children:"git branch"})," that outputs all branches in your repository. Default branch is typically ",(0,r.jsx)(n.code,{children:"master"}),", but can\nbe ",(0,r.jsx)(n.code,{children:"main"})," or ",(0,r.jsx)(n.code,{children:"trunk"}),"."]}),"\n",(0,r.jsx)(n.pre,{children:(0,r.jsx)(n.code,{children:"aisa$ git status\n# Check if repository is clean\n\n# If you know, what is your default branch, you can skip next command.\naisa$ git branch\n# Find the default branch in the list; should be one of the `master`, `main` or\n# `trunk` and you should not have more than one of those.\n# In case the list clears the terminal and you cannot see shell prompt, you can\n# press `q` to quit the pager.\n\naisa$ git checkout master\n"})}),"\n",(0,r.jsx)(n.hr,{}),"\n",(0,r.jsxs)(n.p,{children:["Adapted from: ",(0,r.jsx)(n.a,{href:"https://www.fi.muni.cz/~xlacko1/pb071/mr.html",children:"https://www.fi.muni.cz/~xlacko1/pb071/mr.html"})]})]})}function d(e={}){const{wrapper:n}={...(0,s.a)(),...e.components};return n?(0,r.jsx)(n,{...e,children:(0,r.jsx)(l,{...e})}):l(e)}},11151:(e,n,t)=>{t.d(n,{Z:()=>a,a:()=>i});var r=t(67294);const s={},o=r.createContext(s);function i(e){const n=r.useContext(o);return r.useMemo((function(){return"function"==typeof e?e(n):{...n,...e}}),[n,e])}function a(e){let n;return n=e.disableParentContext?"function"==typeof e.components?e.components(s):e.components||s:i(e.components),r.createElement(o.Provider,{value:n},e.children)}}}]); \ No newline at end of file diff --git a/assets/js/bb984793.0560af7f.js b/assets/js/bb984793.0560af7f.js deleted file mode 100644 index bbff3b6..0000000 --- a/assets/js/bb984793.0560af7f.js +++ /dev/null @@ -1 +0,0 @@ -"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[6864],{82505:e=>{e.exports=JSON.parse('{"label":"karel","permalink":"/algorithms/tags/karel","allTagsPath":"/algorithms/tags","count":1,"items":[{"id":"recursion/karel-1","title":"Recursion and backtracking with Robot Karel","description":"A problem with too many restrictions.\\n","permalink":"/algorithms/recursion/karel-1"}],"unlisted":false}')}}]); \ No newline at end of file diff --git a/assets/js/bb984793.22b3e630.js b/assets/js/bb984793.22b3e630.js new file mode 100644 index 0000000..0b5839d --- /dev/null +++ b/assets/js/bb984793.22b3e630.js @@ -0,0 +1 @@ +"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[6864],{82505:e=>{e.exports=JSON.parse('{"label":"karel","permalink":"/algorithms/tags/karel","allTagsPath":"/algorithms/tags","count":2,"items":[{"id":"recursion/2022-11-29-karel/karel","title":"Recursion and backtracking with Robot Karel","description":"A problem with too many restrictions.\\n","permalink":"/algorithms/recursion/karel"},{"id":"recursion/2022-11-29-karel/solution","title":"Solution to the problem","description":"Solving the problem introduced in the previous post.\\n","permalink":"/algorithms/recursion/karel/solution"}],"unlisted":false}')}}]); \ No newline at end of file diff --git a/assets/js/d05e838c.462c3eb8.js b/assets/js/d05e838c.2fe4800a.js similarity index 98% rename from assets/js/d05e838c.462c3eb8.js rename to assets/js/d05e838c.2fe4800a.js index a4e629f..e32d734 100644 --- a/assets/js/d05e838c.462c3eb8.js +++ b/assets/js/d05e838c.2fe4800a.js @@ -1 +1 @@ -"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[6544],{63004:(e,n,r)=>{r.r(n),r.d(n,{assets:()=>d,contentTitle:()=>c,default:()=>a,frontMatter:()=>i,metadata:()=>o,toc:()=>l});var s=r(85893),t=r(11151);const i={id:"seminar-05-06",title:"5th and 6th seminar",description:"200IQ encryption.\n"},c=void 0,o={id:"bonuses/seminar-05-06",title:"5th and 6th seminar",description:"200IQ encryption.\n",source:"@site/c/bonuses/05-06.md",sourceDirName:"bonuses",slug:"/bonuses/seminar-05-06",permalink:"/c/bonuses/seminar-05-06",draft:!1,unlisted:!1,editUrl:"https://github.com/mfocko/blog/tree/main/c/bonuses/05-06.md",tags:[],version:"current",lastUpdatedAt:1701271124,formattedLastUpdatedAt:"Nov 29, 2023",frontMatter:{id:"seminar-05-06",title:"5th and 6th seminar",description:"200IQ encryption.\n"},sidebar:"autogeneratedBar",previous:{title:"4th seminar",permalink:"/c/bonuses/seminar-04"},next:{title:"8th seminar",permalink:"/c/bonuses/seminar-08"}},d={},l=[{value:"Introduction",id:"introduction",level:2},{value:"Task no. 1: Reverse (0.5 K\u20a1)",id:"task-no-1-reverse-05-k",level:3},{value:"Task no. 2: Vigen\xe8re (0.5 K\u20a1)",id:"task-no-2-vigen\xe8re-05-k",level:3},{value:"Bonus part (0.5 K\u20a1)",id:"bonus-part-05-k",level:4},{value:"Task no. 3: Bit madness (0.5 K\u20a1)",id:"task-no-3-bit-madness-05-k",level:3},{value:"Task no. 4: All combined to BMP (0.5 K\u20a1)",id:"task-no-4-all-combined-to-bmp-05-k",level:3},{value:"Submitting",id:"submitting",level:2}];function h(e){const n={a:"a",code:"code",h2:"h2",h3:"h3",h4:"h4",hr:"hr",li:"li",ol:"ol",p:"p",pre:"pre",ul:"ul",...(0,t.a)(),...e.components};return(0,s.jsxs)(s.Fragment,{children:[(0,s.jsx)(n.p,{children:"For this bonus you can get at maximum 2.5 K\u20a1."}),"\n",(0,s.jsx)(n.p,{children:(0,s.jsx)(n.a,{href:"pathname:///files/c/bonuses/05-06.tar.gz",children:"Source"})}),"\n",(0,s.jsx)(n.h2,{id:"introduction",children:"Introduction"}),"\n",(0,s.jsx)(n.p,{children:"In this bonus you will implement few functions that will be used together for\nimplementing a very special cipher."}),"\n",(0,s.jsx)(n.h3,{id:"task-no-1-reverse-05-k",children:"Task no. 1: Reverse (0.5 K\u20a1)"}),"\n",(0,s.jsxs)(n.p,{children:["Write a function ",(0,s.jsx)(n.code,{children:"char* reverse(const char* text)"})," that returns copy of the input\nstring in reversed order (also uppercase)."]}),"\n",(0,s.jsxs)(n.p,{children:["In case you are given ",(0,s.jsx)(n.code,{children:"NULL"}),", return ",(0,s.jsx)(n.code,{children:"NULL"}),"."]}),"\n",(0,s.jsx)(n.p,{children:"Example (more in tests):"}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{className:"language-c",children:'char* reversed = reverse("Hello world!");\n\nprintf("%s\\n", reversed);\n// "!DLROW OLLEH"\n\nif (reversed != NULL) {\n free(reversed);\n}\n'})}),"\n",(0,s.jsx)(n.h3,{id:"task-no-2-vigen\xe8re-05-k",children:"Task no. 2: Vigen\xe8re (0.5 K\u20a1)"}),"\n",(0,s.jsx)(n.p,{children:"Vigen\xe8re cipher is similar to the Caesar cipher, but you also have a key that is\nused for encrypting (or decrypting)."}),"\n",(0,s.jsx)(n.p,{children:"Your task is to write two functions:"}),"\n",(0,s.jsxs)(n.ul,{children:["\n",(0,s.jsxs)(n.li,{children:[(0,s.jsx)(n.code,{children:"char* vigenere_encrypt(const char* key, const char* text)"})," for encrypting"]}),"\n",(0,s.jsxs)(n.li,{children:[(0,s.jsx)(n.code,{children:"char* vigenere_decrypt(const char* key, const char* text)"})," for decrypting"]}),"\n"]}),"\n",(0,s.jsx)(n.p,{children:"In both of those you should return uppercase characters."}),"\n",(0,s.jsx)(n.p,{children:"Meaning of the parameters you are given:"}),"\n",(0,s.jsxs)(n.ul,{children:["\n",(0,s.jsxs)(n.li,{children:[(0,s.jsx)(n.code,{children:"key"})," - String that represents key that is used for *crypting. It consists of\none word and can have only characters of the alphabet. Does not matter if they\nare uppercase or lowercase."]}),"\n",(0,s.jsxs)(n.li,{children:[(0,s.jsx)(n.code,{children:"text"})," - String that is to be *crypted."]}),"\n"]}),"\n",(0,s.jsxs)(n.p,{children:["Function returns address of the encrypted (or decrypted) string. Or ",(0,s.jsx)(n.code,{children:"NULL"})," in case\nerror occurs."]}),"\n",(0,s.jsx)(n.p,{children:"Example:"}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{className:"language-c",children:'char *encrypted = vigenere_encrypt("CoMPuTeR", "Hello world!");\n\nprintf("%s\\n", encrypted);\n// "JSXAI PSINR!"\n\nif (encrypted != NULL) {\n free(encrypted)\n}\n'})}),"\n",(0,s.jsx)(n.h4,{id:"bonus-part-05-k",children:"Bonus part (0.5 K\u20a1)"}),"\n",(0,s.jsx)(n.p,{children:"If you can utilize helper function that would do both encrypting and decrypting,\nyou can gain 0.5 K\u20a1."}),"\n",(0,s.jsxs)(n.p,{children:["Usage of ",(0,s.jsx)(n.code,{children:"true"}),"/",(0,s.jsx)(n.code,{children:"false"})," to decide path in code is prohibited. It leads to merging\nof both functions into one. Point of this part is to discover a way to do this\ngenerically in such way that there are no separate paths for one or the other. One\nfunction with no branching for both of them, parametrization is your friend :)"]}),"\n",(0,s.jsx)(n.h3,{id:"task-no-3-bit-madness-05-k",children:"Task no. 3: Bit madness (0.5 K\u20a1)"}),"\n",(0,s.jsx)(n.p,{children:"This is a state of the art crypto. Please do not share :)"}),"\n",(0,s.jsx)(n.p,{children:"For encrypting:"}),"\n",(0,s.jsxs)(n.ol,{children:["\n",(0,s.jsx)(n.li,{children:"Split the character that is to be encrypted in halves (4 and 4 bits each)."}),"\n",(0,s.jsx)(n.li,{children:"Bits in 1st half are to be split into pairs. Swap bits in those pairs."}),"\n",(0,s.jsxs)(n.li,{children:["Then use the 4 bits that you created in the 2nd step for ",(0,s.jsx)(n.code,{children:"XOR"})," with the other\n4 bits."]}),"\n"]}),"\n",(0,s.jsxs)(n.p,{children:["This simple and ingenious principle will be illustrated on the following example.\nString we want to encrypt is ",(0,s.jsx)(n.code,{children:"Hello world!"}),". We need to encrypt each letter separately,\nso we will demonstrate on letter ",(0,s.jsx)(n.code,{children:"H"}),":"]}),"\n",(0,s.jsxs)(n.ol,{children:["\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsxs)(n.p,{children:["Letter ",(0,s.jsx)(n.code,{children:"H"})," is represented in ASCII as ",(0,s.jsx)(n.code,{children:"72"}),"."]}),"\n",(0,s.jsxs)(n.p,{children:[(0,s.jsx)(n.code,{children:"72"})," represented in binary is: ",(0,s.jsx)(n.code,{children:"01001000"}),". So first 4 bits are: ",(0,s.jsx)(n.code,{children:"0100"})," and last\n4 bits are ",(0,s.jsx)(n.code,{children:"1000"}),"."]}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsxs)(n.p,{children:["First half of bits (",(0,s.jsx)(n.code,{children:"0100"}),") consists of 2 pairs (",(0,s.jsx)(n.code,{children:"01"})," and ",(0,s.jsx)(n.code,{children:"00"}),") which we swap\n(",(0,s.jsx)(n.code,{children:"01 ~> 10"})," and ",(0,s.jsx)(n.code,{children:"00 ~> 00"}),"). That way we get ",(0,s.jsx)(n.code,{children:"1000"}),"."]}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsx)(n.p,{children:"That half is used for xor with the other 4 bits:"}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{children:" 1000 // second half\nXOR 1000 // first half after 2nd step\n--------\n 0000\n"})}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsxs)(n.p,{children:["Now we combine both halves (first one is ",(0,s.jsx)(n.code,{children:"1000"}),", which we got from the 2nd step\nand second one is ",(0,s.jsx)(n.code,{children:"0000"}),", which we got from the 3rd step) and get ",(0,s.jsx)(n.code,{children:"10000000"}),",\nwhich is encrypted character ",(0,s.jsx)(n.code,{children:"H"})," using this method."]}),"\n"]}),"\n"]}),"\n",(0,s.jsx)(n.p,{children:"In case of decryption, reverse those steps."}),"\n",(0,s.jsx)(n.p,{children:"Your task is to implement functions:"}),"\n",(0,s.jsxs)(n.ul,{children:["\n",(0,s.jsx)(n.li,{children:(0,s.jsx)(n.code,{children:"unsigned char* bit_encrypt(const char* text)"})}),"\n",(0,s.jsx)(n.li,{children:(0,s.jsx)(n.code,{children:"char* bit_decrypt(const unsigned char* text)"})}),"\n"]}),"\n",(0,s.jsx)(n.p,{children:"Example:"}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{className:"language-c",children:'unsigned char* encrypted = bit_encrypt("Hello world!");\n\nfor (int i = 0; i < 12;i++) {\n printf("%x ", encrypted[i]);\n //80 9c 95 95 96 11 bc 96 b9 95 9d 10\n}\n\nif (encrypted != NULL) {\n free(encrypted);\n}\n'})}),"\n",(0,s.jsx)(n.h3,{id:"task-no-4-all-combined-to-bmp-05-k",children:"Task no. 4: All combined to BMP (0.5 K\u20a1)"}),"\n",(0,s.jsx)(n.p,{children:"Authors of the BMP cipher are non-disclosed :)"}),"\n",(0,s.jsx)(n.p,{children:"Create pair of functions:"}),"\n",(0,s.jsxs)(n.ul,{children:["\n",(0,s.jsx)(n.li,{children:(0,s.jsx)(n.code,{children:"unsigned char* bmp_encrypt(const char* key, const char* text)"})}),"\n",(0,s.jsx)(n.li,{children:(0,s.jsx)(n.code,{children:"char* bmp_decrypt(const char* key, const unsigned char* text)"})}),"\n"]}),"\n",(0,s.jsx)(n.p,{children:"BMP cipher consists of following steps for encrypting:"}),"\n",(0,s.jsxs)(n.ol,{children:["\n",(0,s.jsx)(n.li,{children:"Reverse the input string"}),"\n",(0,s.jsx)(n.li,{children:"Use Vigenere on the string you got from step #1"}),"\n",(0,s.jsx)(n.li,{children:"Use bit madness on the string you got from step #2"}),"\n"]}),"\n",(0,s.jsx)(n.p,{children:"For decrypting, reverse the steps."}),"\n",(0,s.jsx)(n.h2,{id:"submitting",children:"Submitting"}),"\n",(0,s.jsx)(n.p,{children:"In case you have any questions, feel free to reach out to me."}),"\n",(0,s.jsx)(n.hr,{})]})}function a(e={}){const{wrapper:n}={...(0,t.a)(),...e.components};return n?(0,s.jsx)(n,{...e,children:(0,s.jsx)(h,{...e})}):h(e)}},11151:(e,n,r)=>{r.d(n,{Z:()=>o,a:()=>c});var s=r(67294);const t={},i=s.createContext(t);function c(e){const n=s.useContext(i);return s.useMemo((function(){return"function"==typeof e?e(n):{...n,...e}}),[n,e])}function o(e){let n;return n=e.disableParentContext?"function"==typeof e.components?e.components(t):e.components||t:c(e.components),s.createElement(i.Provider,{value:n},e.children)}}}]); \ No newline at end of file +"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[6544],{63004:(e,n,r)=>{r.r(n),r.d(n,{assets:()=>d,contentTitle:()=>c,default:()=>a,frontMatter:()=>i,metadata:()=>o,toc:()=>l});var s=r(85893),t=r(11151);const i={id:"seminar-05-06",title:"5th and 6th seminar",description:"200IQ encryption.\n"},c=void 0,o={id:"bonuses/seminar-05-06",title:"5th and 6th seminar",description:"200IQ encryption.\n",source:"@site/c/bonuses/05-06.md",sourceDirName:"bonuses",slug:"/bonuses/seminar-05-06",permalink:"/c/bonuses/seminar-05-06",draft:!1,unlisted:!1,editUrl:"https://github.com/mfocko/blog/tree/main/c/bonuses/05-06.md",tags:[],version:"current",lastUpdatedAt:1703373170,formattedLastUpdatedAt:"Dec 23, 2023",frontMatter:{id:"seminar-05-06",title:"5th and 6th seminar",description:"200IQ encryption.\n"},sidebar:"autogeneratedBar",previous:{title:"4th seminar",permalink:"/c/bonuses/seminar-04"},next:{title:"8th seminar",permalink:"/c/bonuses/seminar-08"}},d={},l=[{value:"Introduction",id:"introduction",level:2},{value:"Task no. 1: Reverse (0.5 K\u20a1)",id:"task-no-1-reverse-05-k",level:3},{value:"Task no. 2: Vigen\xe8re (0.5 K\u20a1)",id:"task-no-2-vigen\xe8re-05-k",level:3},{value:"Bonus part (0.5 K\u20a1)",id:"bonus-part-05-k",level:4},{value:"Task no. 3: Bit madness (0.5 K\u20a1)",id:"task-no-3-bit-madness-05-k",level:3},{value:"Task no. 4: All combined to BMP (0.5 K\u20a1)",id:"task-no-4-all-combined-to-bmp-05-k",level:3},{value:"Submitting",id:"submitting",level:2}];function h(e){const n={a:"a",code:"code",h2:"h2",h3:"h3",h4:"h4",hr:"hr",li:"li",ol:"ol",p:"p",pre:"pre",ul:"ul",...(0,t.a)(),...e.components};return(0,s.jsxs)(s.Fragment,{children:[(0,s.jsx)(n.p,{children:"For this bonus you can get at maximum 2.5 K\u20a1."}),"\n",(0,s.jsx)(n.p,{children:(0,s.jsx)(n.a,{href:"pathname:///files/c/bonuses/05-06.tar.gz",children:"Source"})}),"\n",(0,s.jsx)(n.h2,{id:"introduction",children:"Introduction"}),"\n",(0,s.jsx)(n.p,{children:"In this bonus you will implement few functions that will be used together for\nimplementing a very special cipher."}),"\n",(0,s.jsx)(n.h3,{id:"task-no-1-reverse-05-k",children:"Task no. 1: Reverse (0.5 K\u20a1)"}),"\n",(0,s.jsxs)(n.p,{children:["Write a function ",(0,s.jsx)(n.code,{children:"char* reverse(const char* text)"})," that returns copy of the input\nstring in reversed order (also uppercase)."]}),"\n",(0,s.jsxs)(n.p,{children:["In case you are given ",(0,s.jsx)(n.code,{children:"NULL"}),", return ",(0,s.jsx)(n.code,{children:"NULL"}),"."]}),"\n",(0,s.jsx)(n.p,{children:"Example (more in tests):"}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{className:"language-c",children:'char* reversed = reverse("Hello world!");\n\nprintf("%s\\n", reversed);\n// "!DLROW OLLEH"\n\nif (reversed != NULL) {\n free(reversed);\n}\n'})}),"\n",(0,s.jsx)(n.h3,{id:"task-no-2-vigen\xe8re-05-k",children:"Task no. 2: Vigen\xe8re (0.5 K\u20a1)"}),"\n",(0,s.jsx)(n.p,{children:"Vigen\xe8re cipher is similar to the Caesar cipher, but you also have a key that is\nused for encrypting (or decrypting)."}),"\n",(0,s.jsx)(n.p,{children:"Your task is to write two functions:"}),"\n",(0,s.jsxs)(n.ul,{children:["\n",(0,s.jsxs)(n.li,{children:[(0,s.jsx)(n.code,{children:"char* vigenere_encrypt(const char* key, const char* text)"})," for encrypting"]}),"\n",(0,s.jsxs)(n.li,{children:[(0,s.jsx)(n.code,{children:"char* vigenere_decrypt(const char* key, const char* text)"})," for decrypting"]}),"\n"]}),"\n",(0,s.jsx)(n.p,{children:"In both of those you should return uppercase characters."}),"\n",(0,s.jsx)(n.p,{children:"Meaning of the parameters you are given:"}),"\n",(0,s.jsxs)(n.ul,{children:["\n",(0,s.jsxs)(n.li,{children:[(0,s.jsx)(n.code,{children:"key"})," - String that represents key that is used for *crypting. It consists of\none word and can have only characters of the alphabet. Does not matter if they\nare uppercase or lowercase."]}),"\n",(0,s.jsxs)(n.li,{children:[(0,s.jsx)(n.code,{children:"text"})," - String that is to be *crypted."]}),"\n"]}),"\n",(0,s.jsxs)(n.p,{children:["Function returns address of the encrypted (or decrypted) string. Or ",(0,s.jsx)(n.code,{children:"NULL"})," in case\nerror occurs."]}),"\n",(0,s.jsx)(n.p,{children:"Example:"}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{className:"language-c",children:'char *encrypted = vigenere_encrypt("CoMPuTeR", "Hello world!");\n\nprintf("%s\\n", encrypted);\n// "JSXAI PSINR!"\n\nif (encrypted != NULL) {\n free(encrypted)\n}\n'})}),"\n",(0,s.jsx)(n.h4,{id:"bonus-part-05-k",children:"Bonus part (0.5 K\u20a1)"}),"\n",(0,s.jsx)(n.p,{children:"If you can utilize helper function that would do both encrypting and decrypting,\nyou can gain 0.5 K\u20a1."}),"\n",(0,s.jsxs)(n.p,{children:["Usage of ",(0,s.jsx)(n.code,{children:"true"}),"/",(0,s.jsx)(n.code,{children:"false"})," to decide path in code is prohibited. It leads to merging\nof both functions into one. Point of this part is to discover a way to do this\ngenerically in such way that there are no separate paths for one or the other. One\nfunction with no branching for both of them, parametrization is your friend :)"]}),"\n",(0,s.jsx)(n.h3,{id:"task-no-3-bit-madness-05-k",children:"Task no. 3: Bit madness (0.5 K\u20a1)"}),"\n",(0,s.jsx)(n.p,{children:"This is a state of the art crypto. Please do not share :)"}),"\n",(0,s.jsx)(n.p,{children:"For encrypting:"}),"\n",(0,s.jsxs)(n.ol,{children:["\n",(0,s.jsx)(n.li,{children:"Split the character that is to be encrypted in halves (4 and 4 bits each)."}),"\n",(0,s.jsx)(n.li,{children:"Bits in 1st half are to be split into pairs. Swap bits in those pairs."}),"\n",(0,s.jsxs)(n.li,{children:["Then use the 4 bits that you created in the 2nd step for ",(0,s.jsx)(n.code,{children:"XOR"})," with the other\n4 bits."]}),"\n"]}),"\n",(0,s.jsxs)(n.p,{children:["This simple and ingenious principle will be illustrated on the following example.\nString we want to encrypt is ",(0,s.jsx)(n.code,{children:"Hello world!"}),". We need to encrypt each letter separately,\nso we will demonstrate on letter ",(0,s.jsx)(n.code,{children:"H"}),":"]}),"\n",(0,s.jsxs)(n.ol,{children:["\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsxs)(n.p,{children:["Letter ",(0,s.jsx)(n.code,{children:"H"})," is represented in ASCII as ",(0,s.jsx)(n.code,{children:"72"}),"."]}),"\n",(0,s.jsxs)(n.p,{children:[(0,s.jsx)(n.code,{children:"72"})," represented in binary is: ",(0,s.jsx)(n.code,{children:"01001000"}),". So first 4 bits are: ",(0,s.jsx)(n.code,{children:"0100"})," and last\n4 bits are ",(0,s.jsx)(n.code,{children:"1000"}),"."]}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsxs)(n.p,{children:["First half of bits (",(0,s.jsx)(n.code,{children:"0100"}),") consists of 2 pairs (",(0,s.jsx)(n.code,{children:"01"})," and ",(0,s.jsx)(n.code,{children:"00"}),") which we swap\n(",(0,s.jsx)(n.code,{children:"01 ~> 10"})," and ",(0,s.jsx)(n.code,{children:"00 ~> 00"}),"). That way we get ",(0,s.jsx)(n.code,{children:"1000"}),"."]}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsx)(n.p,{children:"That half is used for xor with the other 4 bits:"}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{children:" 1000 // second half\nXOR 1000 // first half after 2nd step\n--------\n 0000\n"})}),"\n"]}),"\n",(0,s.jsxs)(n.li,{children:["\n",(0,s.jsxs)(n.p,{children:["Now we combine both halves (first one is ",(0,s.jsx)(n.code,{children:"1000"}),", which we got from the 2nd step\nand second one is ",(0,s.jsx)(n.code,{children:"0000"}),", which we got from the 3rd step) and get ",(0,s.jsx)(n.code,{children:"10000000"}),",\nwhich is encrypted character ",(0,s.jsx)(n.code,{children:"H"})," using this method."]}),"\n"]}),"\n"]}),"\n",(0,s.jsx)(n.p,{children:"In case of decryption, reverse those steps."}),"\n",(0,s.jsx)(n.p,{children:"Your task is to implement functions:"}),"\n",(0,s.jsxs)(n.ul,{children:["\n",(0,s.jsx)(n.li,{children:(0,s.jsx)(n.code,{children:"unsigned char* bit_encrypt(const char* text)"})}),"\n",(0,s.jsx)(n.li,{children:(0,s.jsx)(n.code,{children:"char* bit_decrypt(const unsigned char* text)"})}),"\n"]}),"\n",(0,s.jsx)(n.p,{children:"Example:"}),"\n",(0,s.jsx)(n.pre,{children:(0,s.jsx)(n.code,{className:"language-c",children:'unsigned char* encrypted = bit_encrypt("Hello world!");\n\nfor (int i = 0; i < 12;i++) {\n printf("%x ", encrypted[i]);\n //80 9c 95 95 96 11 bc 96 b9 95 9d 10\n}\n\nif (encrypted != NULL) {\n free(encrypted);\n}\n'})}),"\n",(0,s.jsx)(n.h3,{id:"task-no-4-all-combined-to-bmp-05-k",children:"Task no. 4: All combined to BMP (0.5 K\u20a1)"}),"\n",(0,s.jsx)(n.p,{children:"Authors of the BMP cipher are non-disclosed :)"}),"\n",(0,s.jsx)(n.p,{children:"Create pair of functions:"}),"\n",(0,s.jsxs)(n.ul,{children:["\n",(0,s.jsx)(n.li,{children:(0,s.jsx)(n.code,{children:"unsigned char* bmp_encrypt(const char* key, const char* text)"})}),"\n",(0,s.jsx)(n.li,{children:(0,s.jsx)(n.code,{children:"char* bmp_decrypt(const char* key, const unsigned char* text)"})}),"\n"]}),"\n",(0,s.jsx)(n.p,{children:"BMP cipher consists of following steps for encrypting:"}),"\n",(0,s.jsxs)(n.ol,{children:["\n",(0,s.jsx)(n.li,{children:"Reverse the input string"}),"\n",(0,s.jsx)(n.li,{children:"Use Vigenere on the string you got from step #1"}),"\n",(0,s.jsx)(n.li,{children:"Use bit madness on the string you got from step #2"}),"\n"]}),"\n",(0,s.jsx)(n.p,{children:"For decrypting, reverse the steps."}),"\n",(0,s.jsx)(n.h2,{id:"submitting",children:"Submitting"}),"\n",(0,s.jsx)(n.p,{children:"In case you have any questions, feel free to reach out to me."}),"\n",(0,s.jsx)(n.hr,{})]})}function a(e={}){const{wrapper:n}={...(0,t.a)(),...e.components};return n?(0,s.jsx)(n,{...e,children:(0,s.jsx)(h,{...e})}):h(e)}},11151:(e,n,r)=>{r.d(n,{Z:()=>o,a:()=>c});var s=r(67294);const t={},i=s.createContext(t);function c(e){const n=s.useContext(i);return s.useMemo((function(){return"function"==typeof e?e(n):{...n,...e}}),[n,e])}function o(e){let n;return n=e.disableParentContext?"function"==typeof e.components?e.components(t):e.components||t:c(e.components),s.createElement(i.Provider,{value:n},e.children)}}}]); \ No newline at end of file diff --git a/assets/js/d1aceb2e.3f8e795e.js b/assets/js/d1aceb2e.3f8e795e.js deleted file mode 100644 index 2f97321..0000000 --- a/assets/js/d1aceb2e.3f8e795e.js +++ /dev/null @@ -1 +0,0 @@ -"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[1353],{71466:(e,n,t)=>{t.r(n),t.d(n,{assets:()=>a,contentTitle:()=>s,default:()=>h,frontMatter:()=>i,metadata:()=>l,toc:()=>d});var o=t(85893),r=t(11151);const i={id:"karel-1",title:"Recursion and backtracking with Robot Karel",description:"A problem with too many restrictions.\n",tags:["python","karel","recursion","backtracking"],last_update:{date:new Date("2022-11-29T00:00:00.000Z")}},s=void 0,l={id:"recursion/karel-1",title:"Recursion and backtracking with Robot Karel",description:"A problem with too many restrictions.\n",source:"@site/algorithms/04-recursion/2022-11-29-karel-1.md",sourceDirName:"04-recursion",slug:"/recursion/karel-1",permalink:"/algorithms/recursion/karel-1",draft:!1,unlisted:!1,editUrl:"https://github.com/mfocko/blog/tree/main/algorithms/04-recursion/2022-11-29-karel-1.md",tags:[{label:"python",permalink:"/algorithms/tags/python"},{label:"karel",permalink:"/algorithms/tags/karel"},{label:"recursion",permalink:"/algorithms/tags/recursion"},{label:"backtracking",permalink:"/algorithms/tags/backtracking"}],version:"current",lastUpdatedAt:166968e4,formattedLastUpdatedAt:"Nov 29, 2022",frontMatter:{id:"karel-1",title:"Recursion and backtracking with Robot Karel",description:"A problem with too many restrictions.\n",tags:["python","karel","recursion","backtracking"],last_update:{date:"2022-11-29T00:00:00.000Z"}},sidebar:"autogeneratedBar",previous:{title:"Recursion",permalink:"/algorithms/category/recursion"},next:{title:"Introduction to dynamic programming",permalink:"/algorithms/recursion/pyramid-slide-down"}},a={},d=[{value:"Introduction",id:"introduction",level:2},{value:"Your environment and problem description",id:"your-environment-and-problem-description",level:2},{value:"Environment",id:"environment",level:3},{value:"Interface",id:"interface",level:3},{value:"Problem",id:"problem",level:3},{value:"Simple problem to get familiar with the robot",id:"simple-problem-to-get-familiar-with-the-robot",level:2},{value:"Brainstorm the idea",id:"brainstorm-the-idea",level:2},{value:"\xbbRough\xab pseudocode",id:"rough-pseudocode",level:2},{value:"\xbbProper\xab pseudocode",id:"proper-pseudocode",level:2},{value:"Library",id:"library",level:2},{value:"Solution",id:"solution",level:2}];function c(e){const n={a:"a",admonition:"admonition",code:"code",em:"em",h2:"h2",h3:"h3",img:"img",li:"li",ol:"ol",p:"p",pre:"pre",strong:"strong",ul:"ul",...(0,r.a)(),...e.components};return(0,o.jsxs)(o.Fragment,{children:[(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsx)(n.li,{children:(0,o.jsx)(n.a,{href:"pathname:///files/algorithms/recursion/karel-1.tar.gz",children:"Sources"})}),"\n"]}),"\n",(0,o.jsx)(n.h2,{id:"introduction",children:"Introduction"}),"\n",(0,o.jsx)(n.p,{children:"In this exercise we will be working with a Robot Karel and with a \xbbvery\xab limited\nresources. The point of this exercise is to show how powerful recursion and\nbacktracking can be even without anything else at your hand."}),"\n",(0,o.jsx)(n.h2,{id:"your-environment-and-problem-description",children:"Your environment and problem description"}),"\n",(0,o.jsx)(n.h3,{id:"environment",children:"Environment"}),"\n",(0,o.jsx)(n.p,{children:"You are given a robot that is present in a maze and is looking for an exit. Maze\nconsists of different walls and exit is marked with a single so-called \u201cbeeper\u201d."}),"\n",(0,o.jsx)(n.p,{children:"Walking into a wall results in a permanent damage of the robot."}),"\n",(0,o.jsx)(n.h3,{id:"interface",children:"Interface"}),"\n",(0,o.jsx)(n.p,{children:"You can control the robot using the following interface:"}),"\n",(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsxs)(n.li,{children:["actions \u200b\xad\u2014 you can use them to change the current state of the robot and its\nsurroundings","\n",(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsxs)(n.li,{children:[(0,o.jsx)(n.code,{children:"robot.step()"})," \u2014 moves robot one step further"]}),"\n",(0,o.jsxs)(n.li,{children:[(0,o.jsx)(n.code,{children:"robot.turn_left()"})," \u2014 turns robot 90-degrees counter-clockwise","\n",(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsxs)(n.li,{children:["notice that you are not given ",(0,o.jsx)(n.code,{children:"turn_right"})," or ",(0,o.jsx)(n.code,{children:"turn_around"}),", but feel free\nto implement them yourself"]}),"\n"]}),"\n"]}),"\n",(0,o.jsxs)(n.li,{children:[(0,o.jsx)(n.code,{children:"robot.pick_beeper()"})," and opposite operation ",(0,o.jsx)(n.code,{children:"robot.put_beeper()"})," \u2014 that\nallows you to either pick or put \u201cbeeper\u201d from or onto the current position"]}),"\n"]}),"\n"]}),"\n",(0,o.jsxs)(n.li,{children:["queries \u2014 you can use them to check the current state of the robot and its\nsurroundings","\n",(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsxs)(n.li,{children:[(0,o.jsx)(n.code,{children:"robot.beepers_present()"})," \u2014 to check if there are any beepers at the robot's\ncurrent location"]}),"\n",(0,o.jsxs)(n.li,{children:[(0,o.jsx)(n.code,{children:"robot.left_is_clear()"})," \u2014 to check if you can step to the left","\n",(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsxs)(n.li,{children:["analogically for ",(0,o.jsx)(n.code,{children:"front"})," and ",(0,o.jsx)(n.code,{children:"right"})]}),"\n"]}),"\n"]}),"\n"]}),"\n"]}),"\n"]}),"\n",(0,o.jsxs)(n.admonition,{type:"caution",children:[(0,o.jsx)(n.p,{children:"Helper functions / procedures are allowed. Return values are allowed."}),(0,o.jsx)(n.p,{children:(0,o.jsx)(n.strong,{children:"Variables are prohibited!"})})]}),"\n",(0,o.jsx)(n.h3,{id:"problem",children:"Problem"}),"\n",(0,o.jsx)(n.p,{children:"Your task is to decide whether there is an exit from the maze or not. You can see\nan example of a maze here:"}),"\n",(0,o.jsx)(n.p,{children:(0,o.jsx)(n.img,{alt:"Image of the maze",src:t(19857).Z+"",width:"770",height:"839"})}),"\n",(0,o.jsx)(n.h2,{id:"simple-problem-to-get-familiar-with-the-robot",children:"Simple problem to get familiar with the robot"}),"\n",(0,o.jsx)(n.p,{children:"If you feel completely lost after the previous description, let me start you off\nwith a simpler problem."}),"\n",(0,o.jsx)(n.p,{children:"You are standing in front of the stairs, your task is to walk up the stairs."}),"\n",(0,o.jsx)(n.p,{children:"You can see an example of such map here:"}),"\n",(0,o.jsx)(n.p,{children:(0,o.jsx)(n.img,{alt:"Image of the stairs",src:t(68617).Z+"",width:"1058",height:"1161"})}),"\n",(0,o.jsx)(n.h2,{id:"brainstorm-the-idea",children:"Brainstorm the idea"}),"\n",(0,o.jsx)(n.p,{children:"As a first step write down any ideas and things that you have noticed or came to\nyour mind. Ideally:"}),"\n",(0,o.jsxs)(n.ol,{children:["\n",(0,o.jsx)(n.li,{children:"Write down a nested list of the problems"}),"\n",(0,o.jsx)(n.li,{children:"Write down list of problems that can happen"}),"\n",(0,o.jsxs)(n.li,{children:["Write down ",(0,o.jsx)(n.strong,{children:"anything"})," you consider important to solving the problem"]}),"\n"]}),"\n",(0,o.jsxs)(n.admonition,{title:"Example",type:"tip",children:[(0,o.jsxs)(n.p,{children:[(0,o.jsx)(n.strong,{children:"Problem"}),": I want to find out whether the display on smartphone should rotate."]}),(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsxs)(n.li,{children:["nested list of problems","\n",(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsxs)(n.li,{children:["Check if display has been rotated","\n",(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsxs)(n.li,{children:["Read data from some sensor","\n",(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsx)(n.li,{children:"From what sensor"}),"\n"]}),"\n"]}),"\n",(0,o.jsx)(n.li,{children:"In what format are the data I have read?"}),"\n",(0,o.jsx)(n.li,{children:"How do I communicate with the sensor?"}),"\n",(0,o.jsx)(n.li,{children:"What is the meaning of the data that I got?"}),"\n",(0,o.jsx)(n.li,{children:"How can I process it?"}),"\n"]}),"\n"]}),"\n"]}),"\n"]}),"\n",(0,o.jsxs)(n.li,{children:["any problems that can happen","\n",(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsx)(n.li,{children:"What if the sensor doesn't work?"}),"\n",(0,o.jsx)(n.li,{children:"What if the data doesn't conform to the specification?"}),"\n",(0,o.jsx)(n.li,{children:"What if my formulas are wrong?"}),"\n"]}),"\n"]}),"\n",(0,o.jsxs)(n.li,{children:["anything important","\n",(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsx)(n.li,{children:"I could probably use gyroscope."}),"\n",(0,o.jsx)(n.li,{children:"I should probably look up the datasheet for that module."}),"\n",(0,o.jsx)(n.li,{children:"I could write some tests to verify that my computations are correct."}),"\n"]}),"\n"]}),"\n"]})]}),"\n",(0,o.jsx)(n.h2,{id:"rough-pseudocode",children:"\xbbRough\xab pseudocode"}),"\n",(0,o.jsxs)(n.p,{children:["As a next step write a ",(0,o.jsx)(n.strong,{children:"mock up"})," of a pseudocode solving the problem, you are\nallowed to use comments as placeholders for bigger chunks of code."]}),"\n",(0,o.jsx)(n.p,{children:"Those comments are also a very good hints for decomposition and short, but\ndescriptive, commnets (if they are short enough and you decide not to factor them\nout to separate functions)."}),"\n",(0,o.jsx)(n.admonition,{type:"tip",children:(0,o.jsx)(n.p,{children:"The smaller the function is, the easier it is to test it and argue about its\ncorrectness."})}),"\n",(0,o.jsx)(n.h2,{id:"proper-pseudocode",children:"\xbbProper\xab pseudocode"}),"\n",(0,o.jsxs)(n.p,{children:["If you are satisfied with the ",(0,o.jsx)(n.em,{children:"\xbbrough\xab pseudocode"}),", it's time to convert it into\na proper one. Get rid of the uncertain pieces of functionality and replace them\nwith proper pseudocode, i.e. list of the things that should happen in its place."]}),"\n",(0,o.jsx)(n.h2,{id:"library",children:"Library"}),"\n",(0,o.jsxs)(n.p,{children:["If you got here, and you ",(0,o.jsx)(n.strong,{children:"actually"})," wrote down the pseudocode, you can try your\nsolution after downloading the sources linked at the beginning. If you download\nthe ZIP-file, you can there:"]}),"\n",(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsxs)(n.li,{children:["\n",(0,o.jsxs)(n.p,{children:[(0,o.jsx)(n.code,{children:"generate_mazes.py"})," - that was used to generate the same maze with beepers in\ndifferent locations"]}),"\n"]}),"\n",(0,o.jsxs)(n.li,{children:["\n",(0,o.jsxs)(n.p,{children:[(0,o.jsx)(n.code,{children:"karel_tk.py"})," - library which can run Karel given the his world"]}),"\n",(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsxs)(n.li,{children:["documentation can be found ",(0,o.jsx)(n.a,{href:"https://www.fi.muni.cz/~xfocko/ib111/10/docs/",children:"here"})]}),"\n",(0,o.jsx)(n.li,{children:"also requires Tk Python library to be installed (it should be included in\nmajority of Python installations)"}),"\n"]}),"\n"]}),"\n",(0,o.jsxs)(n.li,{children:["\n",(0,o.jsxs)(n.p,{children:[(0,o.jsx)(n.code,{children:"*.kw"})," - which represent multiple worlds for Karel I have prepared"]}),"\n"]}),"\n",(0,o.jsxs)(n.li,{children:["\n",(0,o.jsxs)(n.p,{children:[(0,o.jsx)(n.code,{children:"skeleton.py"})," - skeleton for your solution, needs to be put in the same directory\nas ",(0,o.jsx)(n.code,{children:"karel_tk.py"})," and takes path to the world as a first argument, example usage:"]}),"\n",(0,o.jsx)(n.pre,{children:(0,o.jsx)(n.code,{children:"$ python3 skeleton.py stairs.kw\n"})}),"\n",(0,o.jsxs)(n.ul,{children:["\n",(0,o.jsx)(n.li,{children:"of course, this file can be renamed ;)"}),"\n"]}),"\n"]}),"\n"]}),"\n",(0,o.jsx)(n.h2,{id:"solution",children:"Solution"}),"\n",(0,o.jsx)(n.p,{children:"Solution to this problem will be released as a second part, so that you can try\nit out by yourself without any influence of \u201cexample solution\u201d."}),"\n",(0,o.jsx)(n.p,{children:"If you want to get any feedback, feel free to mail me your solution (including\nall the steps that lead to your final solution, if you wish to get feedback on\nthose too)."})]})}function h(e={}){const{wrapper:n}={...(0,r.a)(),...e.components};return n?(0,o.jsx)(n,{...e,children:(0,o.jsx)(c,{...e})}):c(e)}},19857:(e,n,t)=>{t.d(n,{Z:()=>o});const o=t.p+"assets/images/maze-a374d908bc9445061e15faeddc71641e.png"},68617:(e,n,t)=>{t.d(n,{Z:()=>o});const o=t.p+"assets/images/stairs-5ee5d03905645aeb13eeaa7774451a64.png"},11151:(e,n,t)=>{t.d(n,{Z:()=>l,a:()=>s});var o=t(67294);const r={},i=o.createContext(r);function s(e){const n=o.useContext(i);return o.useMemo((function(){return"function"==typeof e?e(n):{...n,...e}}),[n,e])}function l(e){let n;return n=e.disableParentContext?"function"==typeof e.components?e.components(r):e.components||r:s(e.components),o.createElement(i.Provider,{value:n},e.children)}}}]); \ No newline at end of file diff --git a/assets/js/eba2374c.71f2685d.js b/assets/js/eba2374c.71f2685d.js deleted file mode 100644 index ae893ad..0000000 --- a/assets/js/eba2374c.71f2685d.js +++ /dev/null @@ -1 +0,0 @@ -"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[8387],{47662:a=>{a.exports=JSON.parse('{"label":"backtracking","permalink":"/algorithms/tags/backtracking","allTagsPath":"/algorithms/tags","count":1,"items":[{"id":"recursion/karel-1","title":"Recursion and backtracking with Robot Karel","description":"A problem with too many restrictions.\\n","permalink":"/algorithms/recursion/karel-1"}],"unlisted":false}')}}]); \ No newline at end of file diff --git a/assets/js/eba2374c.dcc463b2.js b/assets/js/eba2374c.dcc463b2.js new file mode 100644 index 0000000..b2e0144 --- /dev/null +++ b/assets/js/eba2374c.dcc463b2.js @@ -0,0 +1 @@ +"use strict";(self.webpackChunkfi=self.webpackChunkfi||[]).push([[8387],{47662:i=>{i.exports=JSON.parse('{"label":"backtracking","permalink":"/algorithms/tags/backtracking","allTagsPath":"/algorithms/tags","count":2,"items":[{"id":"recursion/2022-11-29-karel/karel","title":"Recursion and backtracking with Robot Karel","description":"A problem with too many restrictions.\\n","permalink":"/algorithms/recursion/karel"},{"id":"recursion/2022-11-29-karel/solution","title":"Solution to the problem","description":"Solving the problem introduced in the previous post.\\n","permalink":"/algorithms/recursion/karel/solution"}],"unlisted":false}')}}]); \ No newline at end of file diff --git a/assets/js/main.92563b55.js b/assets/js/main.92563b55.js deleted file mode 100644 index dd66d4d..0000000 --- a/assets/js/main.92563b55.js +++ /dev/null @@ -1,2 +0,0 @@ -/*! 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