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LeetCode/rs/maximum-level-sum-of-a-binary-tree.rs
Matej Focko 2351dfd0ee
chore: unwrap one layer
Signed-off-by: Matej Focko <mfocko@redhat.com>
2023-12-12 14:36:00 +01:00

60 lines
1.4 KiB
Rust

// Definition for a binary tree node.
// #[derive(Debug, PartialEq, Eq)]
// pub struct TreeNode {
// pub val: i32,
// pub left: Option<Rc<RefCell<TreeNode>>>,
// pub right: Option<Rc<RefCell<TreeNode>>>,
// }
//
// impl TreeNode {
// #[inline]
// pub fn new(val: i32) -> Self {
// TreeNode {
// val,
// left: None,
// right: None
// }
// }
// }
use std::cell::RefCell;
use std::convert::TryInto;
use std::rc::Rc;
impl Solution {
fn max_sum(levels: &mut Vec<i32>, level: usize, root: Option<Rc<RefCell<TreeNode>>>) {
if root == None {
return;
}
let r = root.unwrap();
if level >= levels.len() {
levels.resize(level + 1, 0);
}
levels[level] += r.borrow().val;
Solution::max_sum(levels, level + 1, r.borrow().left.clone());
Solution::max_sum(levels, level + 1, r.borrow().right.clone());
}
pub fn max_level_sum(root: Option<Rc<RefCell<TreeNode>>>) -> i32 {
let mut levels = vec![];
Solution::max_sum(&mut levels, 0, root);
levels
.iter()
.enumerate()
.fold((0, i32::MIN), |(max_l, max_s), (l, s)| {
if *s > max_s {
(l + 1, *s)
} else {
(max_l, max_s)
}
})
.0
.try_into()
.unwrap()
}
}