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22 lines
708 B
Java
22 lines
708 B
Java
class Solution {
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public int minCost(String colors, int[] neededTime) {
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int[] dp = new int[colors.length() + 1];
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Arrays.fill(dp, 0);
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char previousColor = 0;
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int previousTime = 0;
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for (int i = 1; i <= colors.length(); ++i) {
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if (colors.charAt(i - 1) == previousColor) {
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dp[i] = dp[i - 1] + Math.min(previousTime, neededTime[i - 1]);
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previousTime = Math.max(previousTime, neededTime[i - 1]);
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} else {
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dp[i] = dp[i - 1];
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previousColor = colors.charAt(i - 1);
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previousTime = neededTime[i - 1];
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}
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}
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return dp[colors.length()];
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}
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}
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