LeetCode/rs/time-needed-to-inform-all-employees.rs

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use std::collections::{HashMap, HashSet, VecDeque};
struct Solution {}
impl Solution {
fn from_managers(managers: &[i32]) -> HashMap<usize, HashSet<usize>> {
let mut mapping = HashMap::new();
for (i, manager) in managers
.iter()
.enumerate()
.filter(|&(_, &manager)| manager != -1)
{
mapping
.entry(*manager as usize)
.or_insert_with(HashSet::new)
.insert(i);
}
mapping
}
pub fn num_of_minutes(_n: i32, head_id: i32, manager: Vec<i32>, inform_time: Vec<i32>) -> i32 {
let manager_mapping = Solution::from_managers(&manager);
let mut q = VecDeque::new();
q.push_back((head_id as usize, 0));
let mut minutes = -1;
while let Some((manager, t)) = q.pop_front() {
minutes = std::cmp::max(minutes, t);
for employee in manager_mapping.get(&manager).unwrap_or(&HashSet::new()) {
q.push_back((*employee, t + inform_time[manager]));
}
}
minutes
}
}
fn main() {}
#[cfg(test)]
mod tests {
use super::*;
// Input: n = 1, headID = 0, manager = [-1], informTime = [0]
// Output: 0
// Explanation: The head of the company is the only employee in the company.
#[test]
fn example_1() {
assert_eq!(Solution::num_of_minutes(1, 0, vec![-1], vec![0]), 0);
}
// Input: n = 6, headID = 2, manager = [2,2,-1,2,2,2], informTime = [0,0,1,0,0,0]
// Output: 1
// Explanation: The head of the company with id = 2 is the direct manager of all the employees in the company and needs 1 minute to inform them all.
// The tree structure of the employees in the company is shown.
#[test]
fn example_2() {
assert_eq!(
Solution::num_of_minutes(6, 2, vec![2, 2, -1, 2, 2, 2], vec![0, 0, 1, 0, 0, 0]),
1
);
}
#[test]
fn regression_1() {
assert_eq!(
Solution::num_of_minutes(
15,
0,
vec![-1, 0, 0, 1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 6, 6],
vec![1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0]
),
3
);
}
}