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LeetCode/java/find-the-safest-path-in-a-grid.java

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class Solution {
private final int[][] DIRECTIONS = {{0, 1}, {0, -1}, {1, 0}, {-1, 0}};
private boolean inBounds(int[][] graph, int y, int x) {
int n = graph.length;
return y >= 0 && y < n && x >= 0 && x < n;
}
private void setSafeness(int[][] graph, Queue<int[]> queue) {
while (!queue.isEmpty()) {
int size = queue.size();
while (size-- > 0) {
int[] cell = queue.poll();
int y = cell[0], x = cell[1];
for (int[] d : DIRECTIONS) {
int ny = y + d[0];
int nx = x + d[1];
int value = graph[y][x];
if (inBounds(graph, ny, nx) && graph[ny][nx] == -1) {
graph[ny][nx] = value + 1;
queue.add(new int[] {ny, nx});
}
}
}
}
}
private int[][] toGraph(List<List<Integer>> grid) {
int n = grid.size();
int[][] graph = new int[n][n];
Queue<int[]> queue = new LinkedList<>();
for (int i = 0; i < n * n; ++i) {
int y = i / n;
int x = i % n;
if (grid.get(y).get(x) == 1) {
queue.add(new int[] {y, x});
graph[y][x] = 0;
} else {
graph[y][x] = -1;
}
}
// calculate safeness
setSafeness(graph, queue);
return graph;
}
private int safestPath(int[][] graph) {
int n = graph.length;
PriorityQueue<int[]> pq = new PriorityQueue<>((l, r) -> r[2] - l[2]);
pq.add(new int[] {0, 0, graph[0][0]});
graph[0][0] = -1;
while (!pq.isEmpty()) {
int[] next = pq.poll();
int y = next[0], x = next[1], safeness = next[2];
// found the goal
if (y == n - 1 && x == n - 1) {
return safeness;
}
for (int[] d : DIRECTIONS) {
int ny = y + d[0];
int nx = x + d[1];
if (inBounds(graph, ny, nx) && graph[ny][nx] != -1) {
pq.add(new int[] {ny, nx, Math.min(safeness, graph[ny][nx])});
graph[ny][nx] = -1;
}
}
}
return -1;
}
public int maximumSafenessFactor(List<List<Integer>> grid) {
int n = grid.size();
int[][] graph = toGraph(grid);
return safestPath(graph);
}
}